₦airaland Forum

will someone help me with this math problem including step by step instructions of how you arrived at the answer? I would appreciate the help so much.


A committee of 6 is selected from 7 male and 10 female. If at least 4 female must be on the committee, in how many ways can the committee be formed?




ps: the only reason i put it in romance is because no one would answer it in the education section

TisaBone:
A committee of 6 is selected from 7 male and 10 female. If at least 4 female must be on the committee, in how many ways can the committee be formed?

^
Here's an attempt:

Since there must be at least 4 females on the committee of 6, the possible combinations are:

6F + 0M, 5F + 1M, 4F + 2M; and the question can be rephrased as what possible ways to select 6 Females, 5 Females + 1 Male and so on.

The total number of ways = (number of ways to choose 6F + 0M) + (number of ways to choose 5F + 1M) + (number of ways to choose 4F + 2M).

Order does not matter so.

Number of ways to choose 6F + 0M = 10!/6!(10-6)! * 7!/0!(7-0)! = 210*1 = 210

Number of ways to choose 5F + 1M = 10!/5!(10-5)! * 7!/1!(7-1)! = 252*7 = 1764

Number of ways to choose 4F + 2M = 10!/4!(10-4)! * 7!/2!(7-2)! = 210*21 = 4410

So the total number of ways = 210 + 1764 + 4410 = 6384

I hope this helps.

^^^ You just refreshed my permutation and combination knowledge. I used to confuse the two. You made is so easy and palpable. Thanks so much!

"in a study to determine iff
there is an association
between alcohol consumption
and cigarette smokers a
researcher collected the
following data from 1090
respondent. Those who take
alcohol and
cigarette-580,those who take
alcohol only-40, those who
take cigarette only-200,and
those who take neither 270.
Is there any association
between them".........im supose
to usee the (o-e)2/e
formula,but im kinda
stuck...any help??

Jayjuice: "in a study to determine iff
there is an association
between alcohol consumption
and cigarette smokers a
researcher collected the
following data from 1090
respondent. Those who take
alcohol and
cigarette-580,those who take
alcohol only-40, those who
take cigarette only-200,and
those who take neither 270.
Is there any association
between them".........im supose
to usee the (o-e)2/e
formula,but im kinda
stuck...any help??

See u 2mrw morning.

Jayjuice: "in a study to determine iff
there is an association
between alcohol consumption
and cigarette smokers a
researcher collected the
following data from 1090
respondent. Those who take
alcohol and
cigarette-580,those who take
alcohol only-40, those who
take cigarette only-200,and
those who take neither 270.
Is there any association
between them".........im supose
to usee the (o-e)2/e
formula,but im kinda
stuck...any help??

dis is set.

Let d uni set be U or £,
Let dose dat take alcohol be AC,
dose dat take cirgarette C,
dose who take neither be N and X those dat take both. . . . . .
So,
U = 1090
AC = 40+580 = 620
C = 200+580 = 780
N = 270
n(AC) n n(C) = 580
<prove 1090=620+780+270-580>
thus, there exist an association btw those dat takes cirgaratte and dose dat drinks;
such that 580 consumes both. . . .

Em-my:
Let d uni set be U or £,
Let dose dat take alcohol be AC,
dose dat take cirgarette C,
dose who take neither be N and X those dat take both. . . . . .
So,
U = 1090
AC = 40+580 = 620
C = 200+580 = 780
N = 270
n(AC) n n(C) = 580
<prove 1090=620+780+270-580>
thus, there exist an association btw those dat takes cirgaratte and dose dat drinks;
such that 580 consumes both. . . .

Yes u got it there is an association btw smokers and those that drink. But that's not what they want u to find. U're required to perform a test of significance to know if there is actually a significant association btw smoking and drinking using the chi-squared test. Hope u know about "test of hypothesis?"

ishmael: Yes u got it there is an association btw smokers and those that drink. But that's not what they want u to find. U're required to perform a test of significance to know if there is actually a significant association btw smoking and drinking using the chi-squared test. Hope u know about "test of hypothesis?"

ya. . . Letme try