₦airaland Forum

doubleDx: Oh well then, I dunno 'bout that; I'd really like to see the solution. Could please have them solve the question and post it here so we can learn from it? And yeah, I know, sophomore's dream can be used for ∫ x^x dx....

...how do you expect me to solve what guru like you doesn't know bro...i don't know it...but i promise you that immediately i will post it here...coz i have asked my generals and i know i will get positive result...SOPHOMORE'S DREAM...HMMMMMMMM

Obeni precious: Group 1 element of trioxocarbonate do not decompose on heating. That is why k2CO3 answer's the question.

...i love that bro...

Hello my general doubledx...i have also tried the questions too but i have some ogas who say the question has solution but higher studies can solve it...one of them said...transformation will be used(not laplace transformation but the other one)and we will integrate using double integrals...ok...pls,what about this...integral x^x dx...THIS ONE IS SOLVED USING SOPHOMORE's DREAM

Pls,my ogas at the top...i'm back ooooo...help me on this...integral e^sinx dx

Richiez: No bro I never intended doing that...lol
Well to get more acquainted with you proposed field (mech engr) make more researches online. U'd also be getting little help here from time to time

...pls my gurus,explain zeno's paradox...i don't know it before ooo

Shollypopz: I need someone to solve this, I don't think I'm right.

Problem: A jar is filled with red, white and blue tokens that are equivalent except for their color. The chance of randomly selecting a red token, replacing it, then randomly selecting a white token is the same as the chance of randomly selecting a blue token. If the number of tokens of every color is a multiple of 3, what is the smallest possible total number of tokens in the jar?

a.)9 (b.)12 (c.)15 (d.)18 (e.)21

hmmmmmmmmmmmmmmmmm

Richiez: You have a wonderful username 'calculusf(x)' u'r very good at calculus problems ryt

...i'm nowhere to be found for now in maths world...but i know one day i will be great...i'm not that very good at calculus but i'm trying...don't give me questions here oooo...so that people will not make jest of me...this is my email bro...omoyeleolalekanjacob@gmail.com...

Richiez: hahahahaha calculusf(x) you're very funny what branch of engineering are you studying?

...still an aspirant bro going for mechanical engineering...pls help me oooo,i'm reticent to what engineering course is......

Richiez: hahahahaha calculusf(x) you're very funny what branch of engineering are you studying?

...still an aspirant bro going for mechanical engineering...pls help me oooo,i'm ignoramous of what engineering course is...

Pls...i need engineers here who can put me through in school

I'm short of words here coz my ogas at the top are online here...just sit down and learn if i don't want to receive cane

Thank God...i meet a thread like this...pls,my great engineers...don't hesitate to help we young engineers

Hello friends...,i got 264 in jamb going for engineering course...what's my fate pls

You have really done a great job@general doubledx...

Pls,i need a maths guru who is already in school...pls,add me on 2go with the username mathemagician...

Pls,let's be frank...is the form out?

Remember this bro,the square root of a natural number is + or -...so,from where you got y^2=4...therefore y=+ or - 2...therefore y=+2 or -2...from the first equation x+2y=0...substitute y=-2...therefore x+2(-2)=0...x-4=0...x=4...substitute y=2...x+2y=0...x+2(2)=0...x+4=0...x=-4...therefore,when y=-2,x=4 and when y=2,x=-4

Pls.how did you draw the diagram bro?

To find the sum of positive integers...1+2+3+...+n=n(n+1)/2...

Richiez: Your answer is correct but show your workings nau

...hmmmmm...i can't draw the diagram here...and i can't explain without diagram...i'm very sorry for that...

[quote author=Omosivie,] Thanks, I still have some questions i'd like u guys to solve. Can I post them here? [/quote]...don't worry sister,if you have any other question,just type it...we will try our best...but remember nobody is an iceland of knowledge...

Richiez: Solve Lim. (SinX)/X
(X->0)

...that's 1

[quote author=Omosivie,] Thanks, but ur answer is not among the options. The options are:
A 2x+1
B 2x+2
C x/2
D 2x-2.
I hope u can understand my workings cos i don't know how to use subscript and superscrpit on nairaland cos i'm on mobile. Log25^x(base 5) - log 4/100(base 5)
log5^2x(base 5) - log 5^-2(base 5)
NB: log5(base 5) = 1.
2x-(-2)
2x+2. My final answer is 2x+2 but the textbook says it's 2x-2. Can u pls point out my mistake? [/quote]...you are very right bro with what you did,i can't say the textbook is wrong,maybe it's typographical error,i mean the answer the textbook provided but your answer is right...

[quote author=Omosivie,] Hi, pls can u teach me how to multiply numbers in different bases apart from base 10? I really need it. [/quote]...base 10...is generally use by everyone...but when i get any trick for any other base,i will let you know

Ortarico: Does this also apply to all numbers?

...not all bro,we will meet at 2go to sort the remaining

Maths gurus in the house...why are you silent...let's gain from one another

Pls bro...my email is omoyeleolalekanjacob@gmail.com...for uniben postjamb past questionsPls bro...my email is omoyeleolalekanjacob@gmail.com...for uniben postjamb past questionsPls bro...my email is omoyeleolalekanjacob@gmail.com...for uniben postjamb past questions

Pls bro...my email is omoyeleolalekanjacob@gmail.com

Going for mechanical engineering but not unilag oooooo

[quote author=@farano]1. A chord of length 6cm is drawn in a circle of radius 5cm.find d distance of d chord from d centre of d circle a)2.5cm b)3.0cm c)3.5cm d)4.0cm.......2. A rectangle picture 6 cm by 8cm is enclosed by a frame 1/2cm wide.calculate d area of d frame a)20sqcm b)15sqcm c)13sqcm d)16sqcm.......3. In one &a half hours,d min hand of a clock rotates through an angle of a)90 b)180 c)540 d)450......4. If d surface area of a sphere is increased by 44%,find d % increased in d diameter a)44 b)30 c)22 d)20.......5. By selling an article for #45.00 a man makes a profit of 8% for how much should he hav sold it in order to make a profit of 32%? A)180.00 b)58.00 c)55.00 d)63.00[/quote]...1.draw a circle and a chord AB inside it.a straight line from the centre to the point where the chord meet the circle (A)=radius of the circle=5...also,a straight line from the centre of a circle which makes a right angle to the chord bisects it at O...so the place is 3cm from (A)...which makes a triangle OAB...with right angle at O...which makes a right angle triangle...so using pythagora's theorem...the answer=4cm...2...the size is 6cm by 8cm=48cm square...and increased by half...up and down...then the length is 9cm...both sides,the breath is 7cm=63cm square...the difference is 15cm square which shows the area...3...for a complete 1 hour,the tips rotate for complete revolution=360' and a half hour is half a revolution=180'...add it to give 540'...4...the area of a sphere is 4¥r^2.where ¥ is equal to pie..and r=d/2...substitute that,therefore s=¥d^2...¥ is a constant...therefore s is proportional to d^2 and s=kd^2...(1)if s is increased by 44%...therefore 144s/100=kd'^2...(2)...divide 2 by 1...therefore (d'/d)^2=144/100.find the square root of both sides...therefore d'/d=12/10=120/100...therefore d is increased by 20%...5...selling price is 45...and a profit of 8%...therefore is 108x/100=45...x=125/3 where x is the cost price...the price he should sell it to gain 32% will be equal to 132/100 * 125/3=55...so the answer is #55...

To know if a number is divisible by 9...just add the numbers together,if it's a multiple of 9.then 9 will surely go in it...e.g.747...you say 7+4+7=18...18 is a multiple of 9...then 9 is a factor of 747...what about 735...add the numbers 7+3+5=15...15 is not a multiple of 9...therefore 9 is not a factor of 735.THE SAME RULE APPLY FOR 3...THEREFORE 735 IS A MULTIPLE OF 3 BECAUSE 15 IS A MULTIPLE OF 3

JungleboyT: My fwend choose uniben as 1st choice and had an aggregate 199 going 4 ecostat. plz wat hope doz he hv? Also wat score shud he aim 4 d putme if posibu d cut off is reduced?

...uniben can't accept x<200...