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Thank you once more Prodgalson; What I want to do is to display the elements of the array starting from the second one when I click Next button but I ended up displaying only the second element. so in attempt to display other elements from the array I decided to shuffle the elements. So I still beg for complete solution |
Thank you very much Prodgalson for given me your precious time, I want to display only one image starting from the first when I click Next and the previous image when I click prev button but it is not done in the order in which the images are placed in the array. This is the code i used to select the images. <body> <table border="0" align="center"> <?php $im0 = "<img src = './pic/car.gif' width = '150' height = '150'>"; $im1 = "<img src = './pic/fl.jpg' width = '150' height = '150'>"; $im2 ="<img src = './pic/house.jpg' width = '150' height = '150'>"; $im3 = "<img src = './pic/phone.gif' width = '150' height = '150'>"; $im4 = "<img src = './pic/pope.jpg' width = '150' height = '150'>"; $image = array($im0, $im1, $im2, $im3, $im4); shuffle($image); echo next($image); ?> </td></tr></table> <table align="center" border="0"> <form action="<?php $_SERVER['PHP_SELF'] ?>" method="post"> <input type ="submit" value ="Previous" name="prv"> <input type="submit" value="Next" name="nxt" /> </form> </td></tr></table> </body> I appreciate any suggestion on how best to do it. Cnn |
Hi all; I am newbie in php. I have array of 5 pictures. i want to display one picture at a time by clicking next or previous button. however, i'm able to display different pictures if I shuffle the elements of the array, but I want to display the images starting from the first element as I click the next button. I appreciate any suggestion on how to do it. I am using php5. Thanks ![]() |
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