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Education / Re: UNIBEN STUDENTS ADMISSION THREAD, 2015/2016 by medwhite0: 8:49am On Jun 16, 2015 |
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Education / Re: UNIBEN STUDENTS ADMISSION THREAD, 2015/2016 by medwhite0: 5:58pm On Jun 01, 2015 |
Education / Re: UNIBEN STUDENTS ADMISSION THREAD, 2015/2016 by medwhite0: 2:45pm On Jun 01, 2015 |
Education / Re: UNIBEN STUDENTS ADMISSION THREAD, 2015/2016 by medwhite0: 1:56pm On Jun 01, 2015 |
RobinHez:18months. |
Education / Re: UNIBEN STUDENTS ADMISSION THREAD, 2015/2016 by medwhite0: 1:54pm On Jun 01, 2015 |
RobinHez:C. 40 |
Education / Re: UNIBEN STUDENTS ADMISSION THREAD, 2015/2016 by medwhite0: 1:46pm On Jun 01, 2015 |
Education / Re: University Of Ibadan 2015/16 Applicants by medwhite0: 11:17am On May 30, 2015 |
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Education / Re: University Of Ibadan 2015/16 Applicants by medwhite0: 10:17am On May 29, 2015 |
horpeyemmi66:1B 2A 3D 4B 5B 6C 7B 8A 9B 10A 2 Likes |
Education / Re: University Of Ibadan 2015/16 Applicants by medwhite0: 8:22am On May 29, 2015 |
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Education / Re: UNIBEN STUDENTS ADMISSION THREAD, 2015/2016 by medwhite0: 8:26am On May 23, 2015 |
Education / Re: UNIBEN STUDENTS ADMISSION THREAD, 2015/2016 by medwhite0: 10:37pm On May 14, 2015 |
Education / Re: UNIBEN STUDENTS ADMISSION THREAD, 2015/2016 by medwhite0: 1:37pm On May 14, 2015 |
RobinHez: Heat lost(supplied) = heat gained by ice + heat gained by container Heat gained by ice = ml (change in state) + mc@(change in temperature) Heat gained by container= H@ H=ML+MC@ +H@ m=10g=0.01kg. 6000=333000*0.01 + 0.01*4200*@ +20@ 6000 = 3330 + 42@ + 20@ 6000-3330=62@ @= 2670/62 @=43.06 |
Education / Re: UNIBEN STUDENTS ADMISSION THREAD, 2015/2016 by medwhite0: 9:50am On May 14, 2015 |
6000J of heat Is delivered to 10g of dry ice at 0°C. What is the final temperature if the container has a heat capacity of 20J/K? c of water = 4200J/kg/K, latent heat of fusion of ice = 3.33 x 10^5J/kg. |
Education / Re: UNIBEN STUDENTS ADMISSION THREAD, 2015/2016 by medwhite0: 9:35am On May 14, 2015 |
Princecalm:yeah....check my working again....modified # |
Education / Re: UNIBEN STUDENTS ADMISSION THREAD, 2015/2016 by medwhite0: 9:21am On May 14, 2015 |
Princecalm:Y=MX+C M=slope. 2Y=-8x+17 m=-8/2=-4 y2-y1/x2-x1=M (2--p)/(-2p--1)=-4 2+p/-2p+1=-4 2+p=-4(-2p+1) 2+p=8p-4 2+4=8p-p 6=7p p=6/7 |
Education / Re: UNIBEN STUDENTS ADMISSION THREAD, 2015/2016 by medwhite0: 9:14am On May 14, 2015 |
Education / Re: UNIBEN STUDENTS ADMISSION THREAD, 2015/2016 by medwhite0: 7:46pm On May 07, 2015 |
RobinHez:1/a^2. + 1/b^2 =>> a^2+b^2/(ab)^2 from factorization a^2+b^2=(a+b)^2 - 2ab thus... [(a+b)^2 - 2ab]/(ab)^2 a+b = sum of root= 10 ab=product of root =2 = [ 10^2 - 2(2)] / (2)^2 =(100-4)/4 =96/4 =24. |
Education / Re: UNIBEN STUDENTS ADMISSION THREAD, 2015/2016 by medwhite0: 8:25am On May 07, 2015 |
Education / Re: UNIBEN STUDENTS ADMISSION THREAD, 2015/2016 by medwhite0: 2:31pm On May 02, 2015 |
chibuzineo:my oga. I hail oo |
Education / Re: UNIBEN STUDENTS ADMISSION THREAD, 2015/2016 by medwhite0: 1:01pm On May 02, 2015 |
RobinHez: |
Education / Re: UNIBEN STUDENTS ADMISSION THREAD, 2015/2016 by medwhite0: 12:42pm On May 02, 2015 |
RobinHez:Yeah. good afternoon. |
Education / Re: UNIBEN STUDENTS ADMISSION THREAD, 2015/2016 by medwhite0: 10:51am On May 02, 2015 |
RobinHez how fa na? |
Education / Re: UNIBEN STUDENTS ADMISSION THREAD, 2015/2016 by medwhite0: 8:44am On Apr 30, 2015 |
RobinHez: PRT=225. t=3 PR=225/3=75. comp interest= Amount - principal. 153= P(1-R)^2 - P 153= P[(1-R)^2-1)] 153= P(1-2R+R^2-1) 153= P(2R+R^2) 153=2PR-PR^2 153=2PR- (PR)R recall PR=75 153=2(75)-(75)R 153-150=75*R 3=75R R=3/75 R=0.04 since PR=75 P=75/0.04 P=1875. |
Education / Re: UNIBEN STUDENTS ADMISSION THREAD, 2015/2016 by medwhite0: 8:24am On Apr 30, 2015 |
RobinHez:. At last......D.(1875) |
Education / Re: UNIBEN STUDENTS ADMISSION THREAD, 2015/2016 by medwhite0: 10:25pm On Apr 29, 2015 |
RobinHez:10... E |
Education / Re: UNIBEN STUDENTS ADMISSION THREAD, 2015/2016 by medwhite0: 9:57pm On Apr 29, 2015 |
RobinHez:B |
Politics / Re: Arrest My Husband And Nigeria Will Boil –asari-dokubo’s Wife Dares Buhari by medwhite0: 2:49pm On Apr 28, 2015 |
Education / Re: UNIBEN STUDENTS ADMISSION THREAD, 2015/2016 by medwhite0: 2:25pm On Apr 28, 2015 |
TryAces:Yes Boss. |
Education / Re: UNIBEN STUDENTS ADMISSION THREAD, 2015/2016 by medwhite0: 2:06pm On Apr 28, 2015 |
RobinHez: Weight W= Force F W=MeM/Re^2 -----------(1) 1/2W=MeM/(Re+H)^2--------(2) (1)÷(2) W/0.5W=(MeM)/(MeM) * Re^2/(Re+H)^2 2=(Re+H)^2/Re Radius of the earthRe=6400km=6400000m √2=Re+H/Re Re√2=Re+ H Re√2-Re=H Re(√2-1)=H √2=1.4 Re(1.4-1)=H 6.4*10^6*0.4=H 2.6*10^6M |
Education / Re: UNIBEN STUDENTS ADMISSION THREAD, 2015/2016 by medwhite0: 1:48pm On Apr 28, 2015 |
RobinHez:WoW! cool tips. |
Education / Re: UNIBEN STUDENTS ADMISSION THREAD, 2015/2016 by medwhite0: 1:44pm On Apr 28, 2015 |
RobinHez:big bro...the formula doesn't apply to all questions...it is used when comparing the weight of a body in diff radius on the earth. Check out this one. g=go * w^2 where w= Re/Re + h g=go [(Re)^2/(Re+h)^2] go =A due to gravity of earth g=A due to gravity due to increase in height. Re radius of of earth. h= altitude or height at which a body is placed. that formula is used to get the change in A due to gravity due to increase in height.... back to my first sentence, that formula Wr2=wr2. can't solve this question... At what distance from the earth surface would the weight of a body be halved?? |
Education / Re: UNIBEN STUDENTS ADMISSION THREAD, 2015/2016 by medwhite0: 9:36am On Apr 28, 2015 |
TryAces:Messenger ribonucleic acid...mRNA. is the correct answer. |
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