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Please I Need Help With This Maths Problem. / Great Mathematicians Help Me Solve This Maths Please / Pls Help Me With The Solution To This Maths Problem. (2) (3) (4)
Please I Need Help With This Maths Problem. by Timijo(m): 9:09am On Oct 19, 2022 |
A right triangle with sides a, b, c forming arithmetic sequence. The perimeter of that triangle is p cm and its area is q cm squared. Given that 3p = 2q, what is the value of b? |
Re: Please I Need Help With This Maths Problem. by Kosoco(m): 9:14am On Oct 19, 2022 |
Value of B is Buhari.... chaii upon all the money my people spent for me to learn maths still e no gree enter. |
Re: Please I Need Help With This Maths Problem. by Chnbanc: 9:28am On Oct 19, 2022 |
How this math wan take put food for ya table this morning? |
Re: Please I Need Help With This Maths Problem. by Timijo(m): 10:22am On Oct 19, 2022 |
If you can't help, just say something reasonable or look and pass. Chnbanc: |
Re: Please I Need Help With This Maths Problem. by zealousayo(m): 12:57pm On Oct 19, 2022 |
b= 10 (Answer) a=9, c=11 Since the sides form an arithmetic sequence, then c will be the longest (hypotenus) while b and a will be the base and height. Since we are looking for b, the sequence will be: b-1, b, b+1 Perimeter, p= (b-1) + (b) + (b+1) = 3b Area= 1/2 (bh)= 1/2 (b)(b-1) Area,q= (b^2 - b)/2 Since 3p = 2q 3(3b)= 2(b^2-b)/2 9b=b^2-b b^2-10b= 0 b=0 or b=10 For an obvious reason, we have to consider 10 and leave out 0. Therefore, b=10 C’est fini. 1 Like |
Re: Please I Need Help With This Maths Problem. by Timijo(m): 1:20pm On Oct 19, 2022 |
zealousayo:Thank you so much. I need to stay in touch with you. Can you give me your WhatsApp contact? |
Re: Please I Need Help With This Maths Problem. by Timijo(m): 1:25pm On Oct 19, 2022 |
Timijo:One more questions We have 10b = b^2 How did we arrive at b =10? |
Re: Please I Need Help With This Maths Problem. by Timijo(m): 1:25pm On Oct 19, 2022 |
zealousayo:One more questions We have 10b = b^2 How did we arrive at b =10? |
Re: Please I Need Help With This Maths Problem. by zealousayo(m): 5:31pm On Oct 19, 2022 |
Timijo:All right, no problem... Can you send me a private mail? |
Re: Please I Need Help With This Maths Problem. by zealousayo(m): 5:33pm On Oct 19, 2022 |
Timijo:Even if you divide both sides by b, the answer is 10 (without resorting to a quadratic equation). |
Re: Please I Need Help With This Maths Problem. by victorogundepo0(m): 4:01am On Oct 20, 2022 |
Timijo: 10b=b² 10(b)=b(b) Divide both side by b and you have b=10. |
Re: Please I Need Help With This Maths Problem. by Timijo(m): 7:33am On Oct 20, 2022 |
zealousayo:I sent you an email. |
Re: Please I Need Help With This Maths Problem. by zealousayo(m): 8:12am On Oct 20, 2022 |
Timijo:Okay, I've responded to it. |
Re: Please I Need Help With This Maths Problem. by Najdorf: 9:59am On Oct 20, 2022 |
zealousayo:Approach is somewhat correct but this is wrong. OP if you have not submitted this then don't. You made a critical assumption which is that the AP is of difference 1. That was never stated anywhere in the question. If you would like to verify your answer then the three side lengths should adhere to Pythagoras since we are dealing with a right-angled triangle. (92)+(102)≠(112). Here is the correct solution. The three sides a,b,c can be written as a-d, a, a+d respectively since it's in an A.P p=(a-d)+a+(a+d) p=3a The area is the product the two smaller sides divided by two(this is from 1/2*base*height) q=(1/2)*(a-d)*a q=(a2-ad)/2 Note: Since we are dealing with a right angled triangle: (a-d)2 + a2 = (a+d)2 Basic simplification gives you a=4d...(1) We'll need this later. Now, 3p=2q 9a=a2-ad Substituting d with a/4 from Equation (1) 9a=a2-(a*a/4) 9a=a2-(a2/4) => (3/4)a2 = 9a =>(3/4)a=9 =>a=12 Therefore the three sides of the triangle are: a-d=9 a=12 a+d=15 We can check that these are truly Pythagorean triples since 92+122=152 The question asked for only b though so b=12 1 Like |
Re: Please I Need Help With This Maths Problem. by zealousayo(m): 7:22pm On Oct 20, 2022 |
Najdorf:You're right, I shouldn't have made that assumption. @Timijo... Follow this approach. |
Re: Please I Need Help With This Maths Problem. by Timijo(m): 7:34pm On Oct 20, 2022 |
zealousayo:Okay, thanks. |
Re: Please I Need Help With This Maths Problem. by Timijo(m): 1:04pm On Oct 29, 2022 |
Thank you for the correction. Please, I will need to keep in touch with you. I need help with some questions. Please send me your WhatsApp number via email. I have sent you an email. Najdorf: |
Re: Please I Need Help With This Maths Problem. by Najdorf: 1:29pm On Oct 29, 2022 |
Timijo:I can't receive emails through Nairaland for some reason I'll send you one |
Re: Please I Need Help With This Maths Problem. by Timijo(m): 1:34pm On Oct 29, 2022 |
Najdorf:I have replied you, please check. |
Re: Please I Need Help With This Maths Problem. by Timijo(m): 3:28pm On Oct 29, 2022 |
Bros, please I need your help ooo. I'm stuck with these questions. Can you send me your WhatsApp number via email? Najdorf: |
Re: Please I Need Help With This Maths Problem. by Najdorf: 3:37pm On Oct 29, 2022 |
Timijo:. |
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