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Mathematicians in the house, I salute o.

Pls, does anyone know where or how I can get a pdf copy of Schaum's outline of vector analysis?

jaryeh:
Mathematicians in the house, I salute o.

Pls, does anyone know where or how I can get a pdf copy of Schaum's outline of vector analysis?

follow this link..then download any of them


www.google.com/m?q=pdf+on+vector+analysis&client=ms-opera-mini-android&channel=new

Can u pls help me to upload your solution.The former is not clear.

agentofchange1:
OK BRo...UWc....

I have £=-1 in the solution with me but is just complicated.

Onase:
Can u pls help me to upload your solution.The former is not clear.I have £=-1 in the solution with me but is just complicated.

OK that will be later ...

am not at home now

u mean d ans is -1 & not 5?.

jaryeh:
Mathematicians in the house, I salute o.

Pls, does anyone know where or how I can get a pdf copy of Schaum's outline of vector analysis?

search for ucforum ---->ebook--->education... you may not find that exact book but am sure u will find a book very close to it... good morning

pls which textbook can i see a replicate of this example?

agentofchange1:
OK that will be later ...

am not at home now

u mean d ans is -1 & not 5?.

Yes.

Pls Nairalanders help me to solve this question.Find the value of alpha(i will use pound symbol)£ for which the following equation possesses solutions>
x-3y+2z=4
2x+y-z=1
3x-2y+z=£(alpha)
A friend solved it and gave me the following answers.
z=7,y=2,x=-4,alpha=-1.But is workings are complicated.I have made an attempt but i am hooked at reducing echelon matrix.

Onase:
Pls Nairalanders help me to solve this question.Find the value of alpha(i will use pound symbol)£ for which the following equation possesses solutions>
x-3y+2z=4
2x+y-z=1
3x-2y+z=£(alpha)
A friend solved it and gave me the following answers.
z=7,y=2,x=-4,alpha=-1.But is workings are complicated.I have made an attempt but i am hooked at reducing echelon matrix.

hmm.

no bro..those values don't satisfy the equations

Check

putting x=-4 , y=2 , z=7

for eqn1 ,
-4-3(2)+2(7)=-4-6+14= =4 .....(eqn 1 satisfied)

for eqn 2,
2(-4)+2-7 =-8+2-7=-13=/=1 (eqn2 not satisfied)

for eqn3,
3(-4)-2(2)+7=-12-4+7=-9=/=-1(eqn3 not satisfied)
it must satisfy all .

here , check my solution , the values are
x=1 , y=-1 , z=0 & £=5

Check
for eqn1,

1-3(-1)+0=1+3=4 (eqn1 satisfied)

for eqn2
2(1)+(-1)+0=2-1 =1 (eqn2 satisfied)

for eqn3 ,
3(1)-2(-1)+0=3+2=5.(eqn3 satisfied)

that's it man . pix below.

Onase:
pls which textbook can i see a replicate of this example?Yes.

you can check. Engineering mathematics by H.K Dass.

Hello, pls, help solve this algebra..

I'm very confused.
if x=(p+q)⅓+(p-q)⅓
and r=(p²-q²)½
prove that x³-3rx=2p

randwise:
Hello, pls, help solve this algebra..

I'm very confused.
if x=(p+q)⅓+(p-q)⅓
and r=(p²-q²)½
prove that x³-3rx=2p

OK check the 2nd eqn


I think it ought to be ^1/3. not ^1/2


********Solution ************

proof:

x=(p+q)^1/3 +(p-q)^1/3

r=(p² -p² )^1/3

r=(p+q)^1/3 *(p-q)^1/3

set a=(p+q)^1/3

& b=(p-q)^1/3

=> x=a+b
& r=ab

now LHS,
x³ -3rx

=> (a+b)³ -3ab(a+b)

=> a³ + b³
thus we have ,

[(p+q)^1/3 ]³. +[(p-q)^1/3 ]³

=p+q+p-q

2p ...............(as required )

Tanx bro...I really appreciate.

agentofchange1:
you can check. Engineering mathematics by H.K Dass.

..

Onase:
Tanx bro...I really appreciate.

any day bro.
ur welcome....seen d solutions. right.?

Downloading.

agentofchange1:
any day bro.
ur welcome....seen d solutions. right.?

yes.Pls how did u arrive at O O O in the third row? Cuz R3-3R1 wont give us Zero.

I have question for you all.Two fathers and two sons went to the market to buy bottles of wine,they all had #450 whiles each bottle costs #150,they to share the bottle of wines equally and not in fractions,how is this possible.

agentofchange1:
OK check the 2nd eqn


I think it ought to be ^1/3. not ^1/2


********Solution ************

proof:

x=(p+q)^1/3 +(p-q)^1/3

r=(p² -p² )^1/3

r=(p+q)^1/3 *(p-q)^1/3

set a=(p+q)^1/3

& b=(p-q)^1/3

=> x=a+b
& r=ab

now LHS,
x³ -3rx

=> (a+b)³ -3ab(a+b)

=> a³ + b³
thus we have ,

[(p+q)^1/3 ]³. +[(p-q)^1/3 ]³

=p+q+p-q

2p ...............(as required )

I'm happy. Thanks brother. You just solved out one my MTS101 problems. Thank you.

Onase:
Tanx bro...I really appreciate.

its nothing man, just solving for fun /learning & helping ....return all praise to God, the giver of life & knowledge, nothing was ever done exclusive of his grace .




BTW: I CNT view the P.m u sent me earlier , kindly re-send.

randwise:
I'm happy. Thanks brother. You just solved out one my MTS101 problems. Thank you.

its OK bro....any day. , try also to give an helping hands /teach also others in need , also make sure you try a particular problem exhaustively before posting here , that's how we learnt / reached the level we are ,

its fun solving..


#shalim....#1love

benji93:
I have question for you all.Two fathers and two sons went to the market to buy bottles of wine,they all had #450 whiles each bottle costs #150,they to share the bottle of wines equally and not in fractions,how is this possible.

this isnt mathematics but a riddle..

Obviously, there are three guys involved.. The son, the father and the grandfather.. i.e

the two fathers are the father and the grandfather.

the 2 sons are the father and the son..since the father is stil a son to the grandfather..


Therefore, they will have one bottle each..

Good morning my ogas here

benji93:
I have question for you all.Two fathers and two sons went to the market to buy bottles of wine,they all had #450 whiles each bottle costs #150,they to share the bottle of wines equally and not in fractions,how is this possible.

there are 3 people involved, one grandfather, one father nd his 2 sons.... meaning 2 fathers nd 2 sons
So, #150 * 3 =#450

Drniyi4u:
there are 3 people involved, one grandfather, one father nd his 2 sons.... meaning 2 fathers nd 2 sons
So, #150 * 3 =#450

nxt tym, m gonna cover my works..lol.
Howdy!

Onase:
yes.Pls how did u arrive at O O O in the third row? Cuz R3-3R1 wont give us Zero.

oh...sorry....my bad...

its R3 -R2 rather.....don't know what I was thinking when I wrote that..

correct it plz....thanks for drawing my attention.

Find the area of the Shaded Portion if the side of the Square measures 20 cm.
Give the answer in cm^2.

(Use the Value of Pi as 3.14 only. Exactly 3.14)

What is the area of the large square ?

FOLLOWING BADLY. I GREET ALL THE BOSSES AND MASTERS IN THE HOUSE I'D BE LEARNING A LOT FROM YOU GUYS HOPEFULLY VERY SOON ASSIGNMENTS WOULD ALWAYS BE UPLOADED HERE

furetin20:
FOLLOWING BADLY. I GREET ALL THE BOSSES AND MASTERS IN THE HOUSE I'D BE LEARNING A LOT FROM YOU GUYS HOPEFULLY VERY SOON ASSIGNMENTS WOULD ALWAYS BE UPLOADED HERE

make sure you include airtime and data

lol

benji93:
What is the area of the large square ?

men,i tink this will make you sweat

Pls guys help with this

. ytan xdy/dx = (4+y^2) sec^2x

DeeCherry:
Pls guys help with this

. ytan xdy/dx = (4+y^2) sec^2x

OK dear in a bus now...let's sha .

using separable variables,

=> dy /dx = (4+y^2)(sec^2 x)/(ytanx)

=> dy/dx =(sec^2 x)/(tanx) * (4+y^2)/y

=> ydy/(4+y^2) = (1/cos^2 x)/(tanx)dx


now take integral of both sides

guess you finish up from dia... right .?