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Maths Wizards Please Help On This. - Education - Nairaland

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Maths Wizards Please Help On This. by Adrenaline123(op): 12:05am On Jul 14, 2015
Differentiate wrt x (3x-1)(x+5) all over 2x^2
Re: Maths Wizards Please Help On This. by agentofchange1(m): 7:03am On Jul 14, 2015
Adrenaline123:
Differentiate wrt x
(3x-1)(x+5) all over 2x^2
let p= (3x-1)(x+5) = 3x^2 +14x-5 so that p'= 6x+14
&
q= 2x^2 ; q' = 4x

y' = dy/dx = (p'*q - p*q ' )/q ^2

thus => [ 2x^2 (6x+14) - 4x(3x^2 +14x-5)]/(2x^2)^2

y' = (12x^3 +28x^2 -12x^3 -56x^2 +20)/4x^4

y'= (-2x^2 +20)/4x^4 = (-x^2 +10)/2x^4

that's it man hope you get .?
Re: Maths Wizards Please Help On This. by Adrenaline123(op): 10:15pm On Jul 14, 2015
agentofchange1:
let p= (3x-1)(x+5) = 3x^2 +14x-5 so that p'= 6x+14
&
q= 2x^2 ; q' = 4x

y' = dy/dx = (p'*q - p*q ' )/q ^2

thus => [ 2x^2 (6x+14) - 4x(3x^2 +14x-5)]/(2x^2)^2

y' = (12x^3 +28x^2 -12x^3 -56x^2 +20)/4x^4

y'= (-2x^2 +20)/4x^4 = (-x^2 +10)/2x^4

that's it man hope you get .?
yeah, Thanks man really appriciate.
Re: Maths Wizards Please Help On This. by Adrenaline123(op): 10:30pm On Jul 16, 2015
agentofchange1 please can you help me out with this integration.

$(x- 1/x)^2 dx
Re: Maths Wizards Please Help On This. by agentofchange1(m): 8:00am On Jul 17, 2015
Adrenaline123:
agentofchange1 please can you help me out with this integration.

$(x- 1/x)^2 dx
OK,
=> $(x^2 - 2 +x^-2)dx

= x^3 /3 -2x - 1/x + c

That it.
Re: Maths Wizards Please Help On This. by Adrenaline123(op): 7:25am On Jul 22, 2015
agentofchange1:
OK,
=> $(x^2 - 2 +x^-2)dx

= x^3 /3 -2x - 1/x + c

That it.
Thanks a lot
Re: Maths Wizards Please Help On This. by agentofchange1(m): 3:56pm On Jul 22, 2015
Adrenaline123:
Thanks a lot
wc man.
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