Nairaland 2016 Jamb Tutorial Classroon [mathematics Thread] - Education (4)

Nairaland 2016 Jamb Tutorial Classroon [mathematics Thread] - Education (4) - Nairaland

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Re: Nairaland 2016 Jamb Tutorial Classroon [mathematics Thread] by Affable0709(m): 5:16pm On Sep 07, 2015

Umartins1:
I'm Umartins1...... I no dey get una mentions.

I salute you too.

Evening sir, I have some questions from my friend's aptitude test.

Solve for x of equation 4^2x =2^6x-1

I still have enough questions left unanswered. Just request.

Re: Nairaland 2016 Jamb Tutorial Classroon [mathematics Thread] by Orezy5(m): 5:43pm On Sep 07, 2015

THE MIDPOINT THEOREM..

The formula used for calculating the coordinates of the midpoint of a straight line are:

x₁ + x₂/2, y₁ + y₂/2

example: find the coordinates of the midpoint of the line joining (3, -4) and (-1, 10)

solution:

using the formula provided above,
x₁= 3
x₂= -1
y₁= -4
y₂= 10

now, lets solve 1st for the coordinates of the midpoint of the x-axis:

using the formula:
x₁ + x₂/2

3 +(-1)/2

3 - 1/2
2/2
x=1
therefore, the coordinate of the midpoint of the x-axis is 1

now, lets solve for y:

y1 + y2/2

-4 + 10/2
6/2
y=3
therefore, the coordinates of the midpoint of y-axis is 3.

therefore, we're going to bring the two answers together according to the form (x, y).

therefore, the final answer will now be:

(1, 3)

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Re: Nairaland 2016 Jamb Tutorial Classroon [mathematics Thread] by Nobody: 5:47pm On Sep 07, 2015

Affable0709:
Evening sir, I have some questions from my friend's aptitude test.

Solve for x of equation 4^2x =2^6x-1

I still have enough questions left unanswered. Just request.

4^2x = 2^6x-1

2^2(2x) = 2^6x-1

2^4x = 2^6x-1

4x= 6x-1

4x-6x= -1

-2x= -1

x= 1/2.

3 Likes 1 Share

Re: Nairaland 2016 Jamb Tutorial Classroon [mathematics Thread] by Geofavor(m): 5:50pm On Sep 07, 2015

Affable0709:
Evening sir, I have some questions from my friend's aptitude test.

Solve for x of equation 4^2x =2^6x-1

I still have enough questions left unanswered. Just request.

4^2x = 2^6x-1

2^2(2x) = 2^6x-1

2(2x) = 6x - 1

4x = 6x - 1

1 = 6x - 4x

1 = 2x

1/2 = x

X = 1/2 = 0.5

2 Likes 1 Share

Re: Nairaland 2016 Jamb Tutorial Classroon [mathematics Thread] by Orezy5(m): 5:53pm On Sep 07, 2015

Geofavor:
4^2x = 2^6x-1
2^2(2x) = 2^6x-1
2(2x) = 6x - 1
4x = 6x - 1
1 = 6x - 4x
1 = 2x
1/2 = x
X = 1/2 = 0.5

nice one

1 Like

Re: Nairaland 2016 Jamb Tutorial Classroon [mathematics Thread] by Orezy5(m): 5:54pm On Sep 07, 2015

Umartins1:
4^2x = 2^6x-1

2^2(2x) = 2^6x-1

2^4x = 2^6x-1

4x= 6x-1

4x-6x= -1

-2x= -1

x= 1/2.

GRREEEEAAATT!

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Re: Nairaland 2016 Jamb Tutorial Classroon [mathematics Thread] by Affable0709(m): 7:50pm On Sep 07, 2015

Umartins1, Geofavor, Orezy5.

Re: Nairaland 2016 Jamb Tutorial Classroon [mathematics Thread] by Orezy5(m): 8:03pm On Sep 07, 2015

Affable0709, can u pls type out d questions. i dnt have a big screen.
thanks.

Re: Nairaland 2016 Jamb Tutorial Classroon [mathematics Thread] by Affable0709(m): 9:13pm On Sep 07, 2015

Simplify log 45-log 9/2

Re: Nairaland 2016 Jamb Tutorial Classroon [mathematics Thread] by Geofavor(m): 9:42pm On Sep 07, 2015

Affable0709:
Simplify log 45-log 9/2

Log45 - (log9 - log2)

Log9 × 5 - (log9 - log2)

(Log9 + log5) - (log9 - log2)

Log9 + log5 - log9 + log2

Log5 + log2

Log5 × 2

Log10

Log10 = 1

A.

1 Like

Re: Nairaland 2016 Jamb Tutorial Classroon [mathematics Thread] by Jamb2016Expo: 11:17pm On Sep 07, 2015

2+2=22

Re: Nairaland 2016 Jamb Tutorial Classroon [mathematics Thread] by Jamb2016Expo: 11:20pm On Sep 07, 2015

Re: Nairaland 2016 Jamb Tutorial Classroon [mathematics Thread] by Orezy5(m): 8:20am On Sep 08, 2015

Affable0709:
Simplify log 45-log 9/2

log45 - log 9/2

log(45 divided by 9/2)

log(45 * 2/9)

log(90/9)

log 10= 1

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Re: Nairaland 2016 Jamb Tutorial Classroon [mathematics Thread] by Nobody: 8:22am On Sep 08, 2015

41. Solve for x if 4^2x = 2^6x-1

Solution

2^4x = 2^6x-1

4x= 6x-1

4x-6x= -1

-2x= -1

x= 1/2...... B

42. Simplify Log45-log 9/2

Solution

Log(90/2) - Log(9/2)

Log(90/2 / 9/2)

Log (90/2 X 2/9)

Log 10

= 1. ........... A

43. Find the HCF of:

a³x²y² = a*a*a*x*x*y*y

b³xy²= b*b*b*x*y*y

C³x²y= c*c*c*x*x*y

Common factor= x*y

HCF= xy........... C

44. Evaluate....

I think you should write the fractions out. I aint getting them.

45. If 12:22=n:1, find n

Solution

12/22 = n/1

22n= 12

n=12/22

n= 0.545.......... B

46. If #738 is divided in the ratio 3/2, 2, 10/3......

Solution.

Sharing ratio= 3/2 + 2 + 10/3

(9+12+20) / 6

41/6

Each share= #738 divided by 41/6

= #738 X 6/41

= #108

The share for 2 is

#108 X 2

= #216........ B

47. %error= actual length-error / actual length. X 100

Let error =x

(25-x)/25 X 100= 4

(2500-100x) / 25 =4

2500-100x= 25X4

2500-100x=100

-100x= 100-2500

-100x= -2400

x= 24

The measurement is wrong by,

25m-24m

= 1m......... A

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Re: Nairaland 2016 Jamb Tutorial Classroon [mathematics Thread] by Orezy5(m): 8:23am On Sep 08, 2015

gud morning guys

Re: Nairaland 2016 Jamb Tutorial Classroon [mathematics Thread] by HomoSapiien(op): 8:33am On Sep 08, 2015

Orezy5:
gud morning guys

Good morning sir

1 Like

Re: Nairaland 2016 Jamb Tutorial Classroon [mathematics Thread] by Nobody: 8:46am On Sep 08, 2015

48. axy + bcxy - az - bcz

xy(a+bc)-z(a+bc)

(Xy-z)(a+bc)

(A+bc)......... B

49. 5x-y varies as 10x-11y

5x-y=k(10x-11y)

K= 5x-y / 10x-11y

When x=7 and y=5

K= 5(7)-5 / 10(7)-11(5)

K= 35-5 / 70-55

K= 30 / 15

K= 2

Sub for k in 5x-y=K(10x-11y)

5x-y=2(10x-11y)

5x-y= 20x-22y

-y+22y= 20x-5x

21y= 15x

Y= 15x/21

Y= 5x/7

50. I can't view it very well. Type it.

51. I don't know biz maths.

52. Gradient= y2-y1 / x2-x1

5-0 / 7-2

5/5

1............ A

53. X+y+z=27

7-5+z=27

2+z=27

Z= 27-2

Z= 25........... B

Cc: Affable0709

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Re: Nairaland 2016 Jamb Tutorial Classroon [mathematics Thread] by HomoSapiien(op): 8:50am On Sep 08, 2015

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Re: Nairaland 2016 Jamb Tutorial Classroon [mathematics Thread] by Orezy5(m): 9:03am On Sep 08, 2015

THE DISTANCE BETWEEN TWO POINTS
for a system of two points, i.e (x1, y1) and (x2, y2);
the formula for calculating the distance between two points is:
d=[square root](x2 - x1)² + (y2 - y1)²[/square root]
example one: what is the distance between the points (3, -2) and (8, 10)?
solution
using the formula given above, x1= 3,
y1= -2,
x2= 8,
y2= 10
d=[square root](8 -3)² + (10 -(-2)²[/square root]
d=[square root](5)² + (10 + 2)²[/square root]
d=[square root](5)² + (12)²[/square root]
d=[square root]25 + 144[/square root] d=[square root]169[/square root]
d=13units.
therefore, the distance between the two points is 13units.

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Re: Nairaland 2016 Jamb Tutorial Classroon [mathematics Thread] by Nobody: 9:07am On Sep 08, 2015

My batt is low, I'm gonna upload the rest later

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Re: Nairaland 2016 Jamb Tutorial Classroon [mathematics Thread] by Orezy5(m): 12:51pm On Sep 08, 2015

example two:

the distance between the points (x, 3) and (-x, 2) is 5. find x.

solution.

although we're going to use the same formula just like the first example, notice that this example is slightly different from the 1st one, the only difference is that we've been given the value of the distance and we're only asked to find the value of one of the coordinates.. it sounds funny abi? let's solve!

since d=square root(x2 - x1)² + (y2 - y1)².

let's bring out all our values:
x1= x
y1= 3
x2= -x
y2= 2
d= 5units.

5=sqrt(x - (-x)² + (2 - 3)²

5=sqrt(x + x)² + (-1)²

5=sqrt(2x)² + 1

5=sqrt 4x² + 1

the square root crosses the = sign to 'marry' 5 and it becomes 5²

5²= 4x² + 1

25= 4x² + 1

collect like terms:

4x²= 25 - 1

4x²= 24

divide both sides by 4:

4x²/4= 24/4

x²= 6

now the square sign 'divorces' x and marries 6:

NB: WHEN THE SQUARE ROOT SIGN CROSSES = SIGN, IT BECOMES THE SQUARED SIGN AND VICE-VERSA

x= sqrt 6
x= 2.449units

NB: sqrt means square root

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Re: Nairaland 2016 Jamb Tutorial Classroon [mathematics Thread] by markpeakson(m): 12:45pm On Sep 09, 2015

Orezy5:
example two:

the distance between the points (x, 3) and (-x, 2) is 5. find x.

solution.

although we're going to use the same formula just like the first example, notice that this example is slightly different from the 1st one, the only difference is that we've been given the value of the distance and we're only asked to find the value of one of the coordinates.. it sounds funny abi? let's solve!

since d=square root(x2 - x1)² + (y2 - y1)².

let's bring out all our values:
x1= x
y1= 3
x2= -x
y2= 2
d= 5units.

5=sqrt(x - (-x)² + (2 - 3)²

5=sqrt(x + x)² + (-1)²

5=sqrt(2x)² + 1

5=sqrt 4x² + 1

the square root crosses the = sign to 'marry' 5 and it becomes 5²

5²= 4x² + 1

25= 4x² + 1

collect like terms:

4x²= 25 - 1

4x²= 24

divide both sides by 4:

4x²/4= 24/4

x²= 6

now the square sign 'divorces' x and marries 6:

NB: WHEN THE SQUARE ROOT SIGN CROSSES = SIGN, IT BECOMES THE SQUARED SIGN AND VICE-VERSA

x= sqrt 6
x= 2.449units

NB: sqrt means square root

5=sqrt(-2x) 2 + (-1) 2
5=√4x + 1
not √4x 2 + 1

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Re: Nairaland 2016 Jamb Tutorial Classroon [mathematics Thread] by Orezy5(m): 2:22pm On Sep 09, 2015

markpeakson:
5=sqrt(-2x) 2 + (-1) 2 5=√4x + 1 not √4x 2 + 1

u r wrong.
how did u get 4x when the squared sign would also affect x?
(-2x)²simply means: (-2)² * (x)²
=4x²

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Re: Nairaland 2016 Jamb Tutorial Classroon [mathematics Thread] by markpeakson(m): 2:54pm On Sep 09, 2015

Orezy5:
u r wrong.
how did u get 4x when the squared sign would also affect x?
(-2x)²simply means: (-2)² * (x)²
=4x²

you are absolutely right... am sorry

Re: Nairaland 2016 Jamb Tutorial Classroon [mathematics Thread] by markpeakson(m): 2:54pm On Sep 09, 2015

Orezy5:
u r wrong.
how did u get 4x when the squared sign would also affect x?
(-2x)²simply means: (-2)² * (x)²
=4x²

you are absolutely right... am sorry

1 Like

Re: Nairaland 2016 Jamb Tutorial Classroon [mathematics Thread] by Orezy5(m): 3:53pm On Sep 09, 2015

markpeakson:
you are absolutely right... am sorry

its alryt. we're all learning

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Re: Nairaland 2016 Jamb Tutorial Classroon [mathematics Thread] by cee001(m): 7:01pm On Sep 09, 2015

U all are doing a great job. I'll b lending and learning here...#following

1 Like

Re: Nairaland 2016 Jamb Tutorial Classroon [mathematics Thread] by Orezy5(m): 7:40pm On Sep 09, 2015

cee001:
U all are doing a great job. I'll b lending and learning here...#following

u r welcm

2 Likes

Re: Nairaland 2016 Jamb Tutorial Classroon [mathematics Thread] by Francis95(m): 8:54pm On Sep 09, 2015

Orezy5:
General form of a linear equation

The general form of linear equations is: y=mx + c. examples of such equations are:
y=3x + 2 etc.

According to the general form(y=mx + c),

m=the gradient/slope of the line

c=the y-intercept, i.e the point where the line/graph crosses the y-axis.

Hope i'm making sense.

Orezy.. I need your Whatsapp number.. Am interested in what you guys are doing here..

1 Like

Re: Nairaland 2016 Jamb Tutorial Classroon [mathematics Thread] by Francis95(m): 10:52pm On Sep 09, 2015

Am following ooooo..... grin

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Re: Nairaland 2016 Jamb Tutorial Classroon [mathematics Thread] by Orezy5(m): 5:14am On Sep 10, 2015

Francis95:
Orezy.. I need your Whatsapp number.. Am interested in what you guys are doing here..

i'm nt on whatsapp. the type of phone i'm using dnt support it.
But u can still have my number: 08175863538

2 Likes

Re: Nairaland 2016 Jamb Tutorial Classroon [mathematics Thread] by Orezy5(m): 5:15am On Sep 10, 2015

Francis95:
Orezy.. I need your Whatsapp number.. Am interested in what you guys are doing here..

i'm nt on whatsapp. the type of phone i'm using dnt support it.
But u can still have my number: 08175863538.

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