₦airaland Forum

Welcome, Guest: RegisterLoginWith GoogleTrendingRecentNew

Stats: 3,327,377 members, 8,430,722 topics. Date: Sunday, 21 June 2026 at 12:01 AM

Toggle theme

Can You Solve This Arithmetic? - Education (2) - Nairaland

Nairaland ForumNairaland GeneralEducationCan You Solve This Arithmetic? (3153 Views)

1 2 Reply (Go Down)

Re: Can You Solve This Arithmetic? by delishpot: 7:56pm On Sep 12, 2015
kstadaura:
Here is another one for you and everyone:
A certain number of horses and an equal number of men are going to somewhere.Half of the owners are on their horses's back while the remaining ones are walking along leading their horses. If the number of legs walking on the ground is 70, how many horses are there?
14 horses and 7 men walking.
I did not have any formular o. Just wisdom to know that the number of humans on the ground should be half the number of horses since half of the ow ers are ridding and the number of men in total equal the number of horses.
Re: Can You Solve This Arithmetic? by llaykorn: 8:37pm On Sep 12, 2015
kstadaura:
A bird shooter was asked how many birds he had in the bag. He replied that there were all sparrows but six,all pegeons but six, and all ducks but six. How many birds he had in the bag in all?

cc:ebbybest,ksslib,teempakguy,llaykorn,horpeyemi18,delishpot,Engrczar, and others.
9..
Re: Can You Solve This Arithmetic? by delishpot: 8:44pm On Sep 12, 2015
This one is tricky for me. I will sampeem here and wait for others to decode it.
Re: Can You Solve This Arithmetic? by Oahray: 10:32pm On Sep 12, 2015
kstadaura:
A bird shooter was asked how many birds he had in the bag. He replied that there were all sparrows but six,all pegeons but six, and all ducks but six. How many birds he had in the bag in all?

cc:ebbybest,ksslib,teempakguy,llaykorn,horpeyemi18,delishpot,Engrczar, and others.
9 birds. 3 of each.
Re: Can You Solve This Arithmetic? by delishpot: 10:35pm On Sep 12, 2015
Oahray:
9 birds. 3 of each.
Ohh. Now I gorrit. grin
Re: Can You Solve This Arithmetic? by Oahray: 10:42pm On Sep 12, 2015
delishpot:
14 horses and 7 men walking.
I did not have any formular o. Just wisdom to know that the number of humans on the ground should be half the number of horses since half of the owners are ridding and the number of men in total equal the number of horses.
hmmm... Same answer here. A horse has twice as many legs as a man, and there are twice as many horses walking as there are walking men. So the ratio of horses legs to men legs is 4:1. Simply divide the total number of legs with the number of legs a man has. (70/2)

So the number of men would be = (1/5) × 35 = 7 men.

Number of horses would thus be 14.

I don't have your wisdom, so I had to solve it in my head cheesy
Re: Can You Solve This Arithmetic? by kstadaura(op): 11:01pm On Sep 12, 2015
Oahray:
hmmm... Same answer here. A horse has twice as many legs as a man, and there are twice as many horses walking as there are walking men. So the ratio of horses legs to men legs is 4:1. Simply divide the total number of legs with the number of legs a man has. (70/2)

So the number of men would be = (1/5) × 35 = 7 men.

Number of horses would thus be 14.

I don't have your wisdom, so I had to solve it in my head cheesy
Thats good, its correct.
Re: Can You Solve This Arithmetic? by kstadaura(op): 11:13pm On Sep 12, 2015
Oahray:
9 birds. 3 of each.
llaykorn:
9..
delishpot:
14 horses and 7 men walking.
I did not have any formular o. Just wisdom to know that the number of humans on the ground should be half the number of horses since half of the ow ers are ridding and the number of men in total equal the number of horses.
All correct.
Re: Can You Solve This Arithmetic? by kstadaura(op): 11:57pm On Sep 12, 2015
In a forest 150 donkeys were caught, tagged with electronic markers,then released.A week later, 50 donkeys were captured in the same forest.Of these 50 donkeys, it was found that 5 had been tagged with the electronic markers.If the percentage of the tagged donkeys in the second sample approximates the percentage of tagged donkeys in the forest, and if no donkey had either left nor entered the forest over the preceding week, what is the approximate number of donkeys in the forest?

cc:
ebbybest,ksslib,teempakguy,llaykorn,horpeyemi18,delishpot,Engrczar,Oahray, and others.
Re: Can You Solve This Arithmetic? by Nobody: 9:12am On Sep 13, 2015
kstadaura:
In a forest 150 donkeys were caught, tagged with electronic markers,then released.A week later, 50 donkeys were captured in the same forest.Of these 50 donkeys, it was found that 5 had been tagged with the electronic markers.If the percentage of the tagged donkeys in the second sample approximates the percentage of tagged donkeys in the forest, and if no donkey had either left nor entered the forest over the preceding week, what is the approximate number of donkeys in the forest?

cc:
ebbybest,ksslib,teempakguy,llaykorn,horpeyemi18,delishpot,Engrczar,Oahray, and others.
answer=1950
Re: Can You Solve This Arithmetic? by kstadaura(op): 9:19am On Sep 13, 2015
timonski:
answer=1950
wrong,How did you get 1950?
Re: Can You Solve This Arithmetic? by Nobody: 9:39am On Sep 13, 2015
kstadaura:
wrong,How did you get 1950?
ok. Initial number of marked donkeys=x=150. Now, out of the the newly captured donkeys, 5 had already been marked.
So percent of already marked donkeys in the new sample is approximately equal to the percentage of marked donkeys. I.e
150/y * 100=5/50 * 100
=> y=(50/5)*(100/100)*150=1500
therefore number of donkeys =1500.
Re: Can You Solve This Arithmetic? by kstadaura(op): 10:39am On Sep 13, 2015
timonski:
ok. Initial number of marked donkeys=x=150. Now, out of the the newly captured donkeys, 5 had already been marked.
So percent of already marked donkeys in the new sample is approximately equal to the percentage of marked donkeys. I.e
150/y * 100=5/50 * 100
=> y=(50/5)*(100/100)*150=1500
therefore number of donkeys =1500.
Now u got it.
Re: Can You Solve This Arithmetic? by Nobody: 10:40am On Sep 13, 2015
Another one, pls
Re: Can You Solve This Arithmetic? by kstadaura(op): 10:51am On Sep 13, 2015
A sum of 690 consists of a certain number of ten Naira notes twice as many five Naira notes three times as many one Naira notes.How many of each note are there?

cc:ebbybest,ksslib,teempakguy,llaykorn,horpeyemi18,delishpot,Engrczar,Oahray,timonski, and others.
Re: Can You Solve This Arithmetic? by Nobody: 11:13am On Sep 13, 2015
kstadaura:
A bird shooter was asked how many birds he had in the bag. He replied that there were all sparrows but six,all pegeons but six, and all ducks but six. How many birds he had in the bag in all?

cc:ebbybest,ksslib,teempakguy,llaykorn,horpeyemi18,delishpot,Engrczar, and others.
sorry I'm late guys!

I saw this yesterday, but my battery was low. This morning, I saw some people have given answers. But no workings. Hmmmn.
So, maybe I should do that . . . let's get to it.

There are three birds in the bag.

Let the number of sparrows be x
Let the number of pigeons be y
Let the number of ducks be z
Let the total number of birds be t.

From question,

t = x + y + z . . . . 1

From question, there are x number of sparrows, as well as 6 of the other kinds.
The same is true for the duck and pigeon.
Hence,

t = x + 6 . . . . .2
t = y + 6 . . . . . .3
t = z + 6. . . . . . .4

eqn 2, 3, 4 are all equal to t and are therefore equal to one another.
Hence,

x + 6 = y + 6 = z + 6

Subtract 6 from all sides, and eureka.

x = y = z !

Hence, eqn 1 becomes

t = x + x + x since both y and z are equal to x.

t = 3x . . . . . 5

But t is equal to x + 6

Hence,

x + 6 = 3x

Collect like terms,

6 = 2x

Divide both sides, and finally,

x = 3.

Replace this in equation 5 and

t = 3(3)
t = 9

Woah . . . yeah, they were totally right. grin


Ah, I see timonski has solved the next question.
Op, be kind to mention me when another question is posted. smiley
Re: Can You Solve This Arithmetic? by Nobody: 11:14am On Sep 13, 2015
kstadaura:
A sum of 690 consists of a certain number of ten Naira notes twice as many five Naira notes three times as many one Naira notes.How many of each note are there?
noted.
Re: Can You Solve This Arithmetic? by kstadaura(op): 11:32am On Sep 13, 2015
Teempakguy:
sorry I'm late guys!

I saw this yesterday, but my battery was low. This morning, I saw some people have given answers. But no workings. Hmmmn.
So, maybe I should do that . . . let's get to it.

There are three birds in the bag.

Let the number of sparrows be x
Let the number of pigeons be y
Let the number of ducks be z
Let the total number of birds be t.

From question,

t = x + y + z . . . . 1

From question, there are x number of sparrows, as well as 6 of the other kinds.
The same is true for the duck and pigeon.
Hence,

t = x + 6 . . . . .2
t = y + 6 . . . . . .3
t = z + 6. . . . . . .4

eqn 2, 3, 4 are all equal to t and are therefore equal to one another.
Hence,

x + 6 = y + 6 = z + 6

Subtract 6 from all sides, and eureka.

x = y = z !

Hence, eqn 1 becomes

t = x + x + x since both y and z are equal to x.

t = 3x . . . . . 5

But t is equal to x + 6

Hence,

x + 6 = 3x

Collect like terms,

6 = 2x

Divide both sides, and finally,

x = 3.

Replace this in equation 5 and

t = 3(3)
t = 9

Woah . . . yeah, they were totally right. grin


Ah, I see timonski has solved the next question.
Op, be kind to mention me when another question is posted. smiley
Ok teempakguy no problem. woow!!! This is Excellent.Am sure your teacher/lecturer use to give u extra mark, back in your school days.
Re: Can You Solve This Arithmetic? by delishpot: 11:37am On Sep 13, 2015
Oahray:
hmmm... Same answer here. A horse has twice as many legs as a man, and there are twice as many horses walking as there are walking men. So the ratio of horses legs to men legs is 4:1. Simply divide the total number of legs with the number of legs a man has. (70/2)

So the number of men would be = (1/5) × 35 = 7 men.

Number of horses would thus be 14.

I don't have your wisdom, so I had to solve it in my head cheesy
Efico!
Re: Can You Solve This Arithmetic? by delishpot: 11:53am On Sep 13, 2015
kstadaura:
In a forest 150 donkeys were caught, tagged with electronic markers,then released.A week later, 50 donkeys were captured in the same forest.Of these 50 donkeys, it was found that 5 had been tagged with the electronic markers.If the percentage of the tagged donkeys in the second sample approximates the percentage of tagged donkeys in the forest, and if no donkey had either left nor entered the forest over the preceding week, what is the approximate number of donkeys in the forest?

cc:
ebbybest,ksslib,teempakguy,llaykorn,horpeyemi18,delishpot,Engrczar,Oahray, and others.
3000 donkeys.


If 5% of all donkeys tagged were 150 that means 5% of 3000 is 150 so the foest has 3000 donkeys and out of them 150 are tagged which is 5% of the donkey poopulation.

Hope I gorrit.
Re: Can You Solve This Arithmetic? by kstadaura(op): 12:15pm On Sep 13, 2015
timonski:
Another one, pls
.
Re: Can You Solve This Arithmetic? by kstadaura(op): 12:17pm On Sep 13, 2015
delishpot:
3000 donkeys.


If 5% of all donkeys tagged were 150 that means 5% of 3000 is 150 so the foest has 3000 donkeys and out of them 150 are tagged which is 5% of the donkey poopulation.

Hope I gorrit.
NO.
Re: Can You Solve This Arithmetic? by delishpot: 12:25pm On Sep 13, 2015
kstadaura:
NO.
Haba! grin. Has anyone solved it yet? Let me see the answer
Re: Can You Solve This Arithmetic? by Nobody: 1:29pm On Sep 13, 2015
kstadaura:
Ok teempakguy no problem. woow!!! This is Excellent.Am sure your teacher/lecturer use to give u extra mark, back in your school days.
ironically, during my secondary school days, I sucked at maths. grin grin too much Nokia phone games. cheesy cheesy
I Wonder what happened. huh

kstadaura:
A sum of 690 consists of a certain number of ten Naira notes twice as many five Naira notes three times as many one Naira notes.How many of each note are there?
cc:ebbybest,ksslib,teempakguy,llaykorn,horpeyemi18,delishpot,Engrczar,Oahray,timonski, and others.
Let's do this! grin

Let the number of ten naira notes be x
Let the number of five naira notes be y
Let the number of one naira notes be z

Hence,

10 naira in x places plus 5 naira in y places plus 1 naira in z places. Equal 690.
Algebraically,

10x + 5y + z = 690 . . . . . 1

From the question, there are twice as many five naira notes for each ten naira and thrice as many one naira notes.

Hence,

y = 2x and z = 3x

Substituting these into the equation 1,

10x + 5(2x) + 3x = 690

10x + 10x + 3x = 690

23x = 690

x = 30

So there are 30 ten naira notes there.

y = 2x
y = 60

So there are 60 five naira notes there.

z = 3x
z = 90

So there are 90 five naira notes there.

smiley smiley
Re: Can You Solve This Arithmetic? by Oahray: 3:57pm On Sep 13, 2015
kstadaura:
In a forest 150 donkeys were caught, tagged with electronic markers,then released.A week later, 50 donkeys were captured in the same forest.Of these 50 donkeys, it was found that 5 had been tagged with the electronic markers.If the percentage of the tagged donkeys in the second sample approximates the percentage of tagged donkeys in the forest, and if no donkey had either left nor entered the forest over the preceding week, what is the approximate number of donkeys in the forest?

cc:
ebbybest,ksslib,teempakguy,llaykorn,horpeyemi18,delishpot,Engrczar,Oahray, and others.
just seeing this mention. 150 is 10% of 1500.

Edit: oh... It's been answered.
Re: Can You Solve This Arithmetic? by kstadaura(op): 3:57pm On Sep 13, 2015
delishpot:
Haba! grin. Has anyone solved it yet? Let me see the answer
has been solved by timonski, the correct answer is 1500.
Re: Can You Solve This Arithmetic? by kstadaura(op): 4:04pm On Sep 13, 2015
Teempakguy:
ironically, during my secondary school days, I sucked at maths. grin grin too much Nokia phone games. cheesy cheesy
I Wonder what happened. huh



Let's do this! grin

Let the number of ten naira notes be x
Let the number of five naira notes be y
Let the number of one naira notes be z

Hence,

10 naira in x places plus 5 naira in y places plus 1 naira in z places. Equal 690.
Algebraically,

10x + 5y + z = 690 . . . . . 1

From the question, there are twice as many five naira notes for each ten naira and thrice as many one naira notes.

Hence,

y = 2x and z = 3x

Substituting these into the equation 1,

10x + 5(2x) + 3x = 690

10x + 10x + 3x = 690

23x = 690

x = 30

So there are 30 ten naira notes there.

y = 2x
y = 60

So there are 60 five naira notes there.

z = 3x
z = 90

So there are 90 five naira notes there.

smiley smiley
Well done

Re: Can You Solve This Arithmetic? by Nobody: 5:53pm On Sep 13, 2015
kstadaura:
Well done
thanks. cheesy
Re: Can You Solve This Arithmetic? by Ksslib(m): 9:16am On Sep 16, 2015
Oahray:
hmmm... Same answer here. A horse has twice as many legs as a man, and there are twice as many horses walking as there are walking men. So the ratio of horses legs to men legs is 4:1. Simply divide the total number of legs with the number of legs a man has. (70/2)

So the number of men would be = (1/5) × 35 = 7 men.

Number of horses would thus be 14.

I don't have your wisdom, so I had to solve it in my head cheesy
I wanted to point out the fact that the op's question was an ambiguous one,but i just say make I leave am.

He said AN EQUAL number of men and horses are going somewhere. If the number of horses equals men,then how come we have 14horses but 7men?

Secondly,when he said "70legs walking on the ground" was he refereeing to just the number of men who aint on their horses back, or legs in general,be it that of a horse or man?

If he was referring to legs in general,then he shouldn't have repeated the word "walking" twice,because having done that,walking automatically now refers to just men not riding horses.. Some of us actually read in between the lines. Anyway,I await your response. I might be the wrong one here.

@Kstadaura... Na wetin make me kuku stop dey solve cos i no dey like am wen I solve something finish,only to discover it's not correct because there was an error somewhere not on my part. The other naira kobo problem was one. Solved and solved for 40,000...then you change am to 40kobo.. Kept solving for 40kobo and knew something was wrong. Scrolled back up only to see that youve modified it to 0.40kobo.. Which levels na?
Re: Can You Solve This Arithmetic? by Oahray: 5:27pm On Sep 19, 2015
Ksslib:
I wanted to point out the fact that the op's question was an ambiguous one,but i just say make I leave am.

He said AN EQUAL number of men and horses are going somewhere. If the number of horses equals men,then how come we have 14horses but 7men?

Secondly,when he said "70legs walking on the ground" was he refereeing to just the number of men who aint on their horses back, or legs in general,be it that of a horse or man?

If he was referring to legs in general,then he shouldn't have repeated the word "walking" twice,because having done that,walking automatically now refers to just men not riding horses.. Some of us actually read in between the lines. Anyway,I await your response. I might be the wrong one here.
sorry this is coming late.

em... I actually was aiming at getting the number of horses by getting the number of men walking. I focused on the number of human legs on the ground, as against horses. An equal number of men are on horse back, which brings the total number of men to 14, same as the number of horses (each man has a horse).
Re: Can You Solve This Arithmetic? by Ksslib(m): 9:25am On Sep 21, 2015
Oahray:
sorry this is coming late.

em... I actually was aiming at getting the number of horses by getting the number of men walking. I focused on the number of human legs on the ground, as against horses. An equal number of men are on horse back, which brings the total number of men to 14, same as the number of horses (each man has a horse).
I took same approach too;get number of horses by getting number of men walking first. I guess the error came from reading too much meaning into the word "walking". So much for reading in between the lines,and the Op sef, didn't help matters at all.

Thanks.
1 2 Reply

Please Help Me Solve This Arithmetic.Can You Solve This Primary School QuantitativeWho Can Solve This Arithmetic?234

10 Funny Economic Way Most Nigerian Students Survive On FeedingKogi State University Freshers Registration Procedures.Schools Will Run Out Of Business Very Soon. This Is Why