Nairaland Mathematics Clinic - Education (203) - Nairaland
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| Re: Nairaland Mathematics Clinic by Hadampson(m): 9:36pm On Nov 10, 2015 |
A student walk 3km at a speed of vkm/hr.. Find the time taken, in the form of v?? Plz help me solve dis word problem, maths guruz! |
| Re: Nairaland Mathematics Clinic by Nobody: 10:20pm On Nov 10, 2015 |
Hadampson:Distance is 3km, and speed is distance / time taken. You were given speed as V. Time taken = distance /speed. Time = 3/V |
| Re: Nairaland Mathematics Clinic by agentofchange1(m): 1:18am On Nov 11, 2015 |
jackpot:yea, sure dear , wer u go hide all diz while , ur boy has been searching for his mama.. |
| Re: Nairaland Mathematics Clinic by agentofchange1(m): 1:20am On Nov 11, 2015 |
Karmanaut:oh..i see. .. n u didn't reply my mail sir, what i do ? |
| Re: Nairaland Mathematics Clinic by Hadampson(m): 6:06am On Nov 11, 2015 |
Tanx Karmanaut... D questn z nt complete. Dis is d final questn on dat word problem.. If d time taken for student to walk =35mins... Find d value of v? |
| Re: Nairaland Mathematics Clinic by agentofchange1(m): 6:21am On Nov 11, 2015 |
Hadampson:35/60 =3/v v=3*60/35 = 5hrs ( approx.) |
| Re: Nairaland Mathematics Clinic by Hadampson(m): 6:32am On Nov 11, 2015 |
A boy walks 8km at vkm/hr. He then cycles 15km at 2vkm/hr. In terms of v, write down the time taken in hours (a) when walking (b) when cycling (c) if the total time for the journey is 2hr 35mins, find the boy's walking speed.. |
| Re: Nairaland Mathematics Clinic by MathsChic(f): 7:03am On Nov 11, 2015 |
Hadampson:Time to walk = 8/v Time to cycle = 15/2v Total time is 2 + 35/60 = 2.583hr 8/v + 15/2v = 2 7/12 (1/v)(8 + 15/2) = 2 7/12 (1/v)(31/2) = 31/12 v.2/31 = 12/31 v = 6km/hr....walking speed |
| Re: Nairaland Mathematics Clinic by Hadampson(m): 8:03am On Nov 11, 2015 |
Tankx 2 u all.. I rili appreciate |
| Re: Nairaland Mathematics Clinic by Hadampson(m): 8:06am On Nov 11, 2015 |
Plz maths guruz in da house. I want to ask a question? D question is where can a mathematics graduate. Am tired of hearing that a mathematics graduate can work anywhere, anywhere as how? |
| Re: Nairaland Mathematics Clinic by MathsChic(f): 8:15am On Nov 11, 2015 |
Hadampson:The kind of work you get as a maths graduate ultimately depends on your productivity and creativity. A run-of-the-mill graduate will work anywhere basically, from selling insurance to punching keys at a bank. A more creative, intelligent graduate can easily get work with investment firms, financial houses and core finance firms, that'd be like Kakawa Discount House, e.g. Also as a consultant in a range of services from analysis to statistics. Finance houses, especially, realize the importance of mathematics as a modelling tool and will require the services of a maths graduate for this. Of cos, this is not to mention a whole field of opportunities for a graduate of applied mathematics, depending on where the "applied" is oriented. |
| Re: Nairaland Mathematics Clinic by ladokuntlad(m): 8:16am On Nov 11, 2015 |
Hadampson:Anywhere bro.. Why? Our brain has the ability to adapt into any field. Just have interest in it and u c yoursef excelling. Shell, chevron, Oil and gas, academics, medical worlds, banking , fashion designing, ICT... Just to mention a few. We can adapt easily because of the way we av been configured from unset.. Maths is life bro |
| Re: Nairaland Mathematics Clinic by Nobody: 9:28am On Nov 11, 2015 |
Hadampson:You can follow the wonderful advice given by the other members, but if you want to use your "powers for good then you should consider a career in academia. Because... https://quotesvalley.com/images/06/life-is-good-for-only-two-things-discovering-mathematics-and-teaching-mathematics.jpg |
| Re: Nairaland Mathematics Clinic by Nobody: 9:45am On Nov 11, 2015 |
agentofchange1:Turns out it had a series expansion. Maths Chic wrote the answer. n u didn't reply my mail sir, what i do ?Getting to that, cheers. |
| Re: Nairaland Mathematics Clinic by Hadampson(m): 9:49am On Nov 11, 2015 |
Tankx |
| Re: Nairaland Mathematics Clinic by Madmathecian(m): 9:55am On Nov 11, 2015 |
Hadampson:Lol |
| Re: Nairaland Mathematics Clinic by Nobody: 11:04am On Nov 11, 2015*. Modified: 12:11pm On Aug 13, 2016 |
. |
| Re: Nairaland Mathematics Clinic by agentofchange1(m): 11:57am On Nov 11, 2015 |
Karmanaut:ok boss.. |
| Re: Nairaland Mathematics Clinic by Hadampson(m): 2:15pm On Nov 11, 2015 |
masperano: |
| Re: Nairaland Mathematics Clinic by Hadampson(m): 2:16pm On Nov 11, 2015 |
masperano:tanx bro |
| Re: Nairaland Mathematics Clinic by Madmathecian(m): 5:31pm On Nov 11, 2015 |
Think through it.
|
| Re: Nairaland Mathematics Clinic by Madmathecian(m): 11:20pm On Nov 11, 2015*. Modified: 12:01am On Nov 12, 2015 |
On some planet, there are 2N countries (N>= 4). Each country has a flag N units wide and one unit high composed of N fields of size 1 x 1, each field being either yellow or blue. No two countries have the same flag. We say that a set of N flags is diverse if these flags can be arranged into an N x N square so that all N fields on its main diagonal will have the same color. Determine the smallest positive integer M such that among any M distinct flags, there exist N flags forming a diverse set. |
| Re: Nairaland Mathematics Clinic by ladokuntlad(m): 11:22pm On Nov 11, 2015 |
| Re: Nairaland Mathematics Clinic by MathsChic(f): 11:40pm On Nov 11, 2015 |
masperano:This is beautiful. Question answered! |
| Re: Nairaland Mathematics Clinic by Madmathecian(m): 11:54pm On Nov 11, 2015 |
ladokuntlad:Lol. No Sir. Try again. |
| Re: Nairaland Mathematics Clinic by MathsChic(f): 11:10am On Nov 12, 2015 |
Madmathecian:This is more of a puzzle than it is a maths problem. And some fundamental assumptions must be made in order to move forward. If Cheryl told Albert and Bernard the month and date separately, then she only could have told Albert any of the set (May, June, July, August) and Bernard any of the set (14, 15, 16, 17, 18, 19). From the first sentence, Albert claims "I don't know what Cheryl's birthday is, but I know that Bernard doesn't know too". Since Bernard doesn't know too and only knows the date, then the date can't be (18,19), merely because if it were any of the two then Bernard would know for sure what Cheryl's bday is. 18 or 19 would simply mean June 18 or May 19. So, set of possible values Cheryl could have told Bernard is (14, 15, 16, 17). Albert's conclusion is based on a blanket assumption that Bernard is able to figure this out. Not so good. Albert would also have been told July or August for him to be convinced Bernard doesn't know Cheryl's bday, because if he was told May or June he would have doubts about whether Bernard knows or not. From the second sentence, Bernard claims "at first, i didn't know what Cheryl's birthday is, but now i know". This can only mean that Bernard has figured out that Albert has only July & August as months. Since he couldn't have had May or June which would have given away the answer long before. But since Bernard has a date already, it means he now knows Cheryl's bday as July 16, the only possible cross between the two available sets. It couldn't have been July or Aug 14, as Bernard then would still not have known what Cheryl's bday is. From third sentence, Albert now knows Cheryl's bday too, because he has the month. He didnt have the day, but July 16 is the only date he could have, as Aug 15 or 17 would mean he still doesn't know what the bday is. So, answer is July 16. But seriously, you are the only one doing the thinking here, not Albert or Bernard. I don't think this is a clear puzzle. |
| Re: Nairaland Mathematics Clinic by Madmathecian(m): 1:29pm On Nov 12, 2015 |
MathsChic:You got it right. |
| Re: Nairaland Mathematics Clinic by Nobody: 4:21pm On Nov 12, 2015*. Modified: 4:38pm On Nov 12, 2015 |
Solve for (9!/3! -n!) * 0! - 3! when n = 8. |
| Re: Nairaland Mathematics Clinic by ladokuntlad(m): 4:58pm On Nov 12, 2015 |
all4naija:is it (9!/(3!-n!))*(0!-3!) or (9!/(3!-n!))*0!-3! or (9!/3!-n!)*(0!-3!) or ur question as stated? |
| Re: Nairaland Mathematics Clinic by Nobody: 5:09pm On Nov 12, 2015 |
ladokuntlad:As stated. Thank you. |
| Re: Nairaland Mathematics Clinic by ladokuntlad(m): 6:14pm On Nov 12, 2015 |
all4naija:20,154 9!/3!=60,480 8!=40,320 (9!/3!-8!)=60,480-40,320=20,160 0!=1 (9!/3!-8!)*0!=20,160*1=20,160 3!=6 (9!/3!-8!)*0!-3!=20,160-6 =20,154 |
| Re: Nairaland Mathematics Clinic by bolkay47(m): 6:18pm On Nov 12, 2015 |
all4naija:20154 |
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