₦airaland Forum

ShyNeptune:
@mathefaro Geofavor

If one of the roots of the equation px² +qx+r=0 is twice the other root, find a relationship relating p, q and r

let alpha=u, beta=v.
u=2v.
u+v=-q/p.
uv=pr.
3v=-q/p.

Geofavor:
honestly that question looked "alienated" when I saw it; I don't know the topic it was coined out from.
So I just did a bit of coordinate geometry: length = sqrt( (x2 - x1)² + (y2 - y1)² )

then I squared the result. I got what you got: 16

Lolz..... alright.

thankyouJesus:
let alpha=u, beta=v.
u=2v.
u+v=-q/p.
uv=pr.
3v=-q/p.

Thanks for the tip.....

Pls i'm getting (8 -3t)/4
The mean of 2-t, 4-t, 3-2t and t-1 is A) t B) -2. C) 2. D) -t
thankyoujesus, shyneptune

Geofavor:
Pls i'm getting (8 -3t)/4

The mean of 2-t, 4-t, 3-2t and t-1 is A) t B) -2. C) 2. D) -t

thankyoujesus, shyneptune

Same here

Well done guys, I believe all the questionshas been answered

If y = sin(-4x) dy/dx is A) -12cos(-4x). B) -12 x cos(-4x). C) 12 x cos(4x). D) 12sin(-4x)

Geofavor:
If y = sin(-4x) dy/dx is A) -12cos(-4x). B) -12 x cos(-4x). C) 12 x cos(4x). D) 12sin(-4x)

-4x=U
y=sin U
dy/du=CosU
du/dx=-4
dy/dx=-4×CosU
dy/dx=-4cos(-4x)

Geofavor:
If the end point of one side of square RSTU are R(-1, -1) and (3, -1) find the area of the square.

Mathefaro, umartins1, thankyoujesus, oxytocin etc.

still pending...

Oxytocin:
-4x=U y=sin U dy/du=CosU du/dx=-4 dy/dx=-4×CosU dy/dx=-4cos(-4x)

this means there was an error in the question. Thanks

Hehehe....
I seriously didn't know there was a maths thread
So una no fit call person abi
Diaris God oo..

ShyNeptune:
Same here

erroneous question i suppose. These questions are from Last year's exam: jamb 2015

Geofavor:
this means there was an error in the question. Thanks

Hmm... This same question.??
***modified ***
The options right, yh there is a mistake there.

Geofavor:
erroneous question i suppose. These questions are from Last year's exam: jamb 2015

how did you gain access to last year's jamb questions?

Oxytocin:
Hmm... This same question.??
***modified ***
The options right, yh there is a mistake there.

You're offering maths too?

Geofavor:
still pending...

Find the length of the side using the given coordinates, then square it.
NB, dist b2 2 points (x1, y1) and (x2 and y2) = sqrt((x2-x1)² + (y2-y1)²)

thankyouJesus:
let alpha=u, beta=v.
u=2v.
u+v=-q/p.
uv=pr.
3v=-q/p.

Expatiate bro

ShyNeptune:
how did you gain access to last year's jamb questions?

I bought the past questions booklet.

ShyNeptune:
You're offering maths too?

Abi nau..
If not maths, what else??

mathefaro:
Find the length of the side using the given coordinates, then square it.
NB, dist b2 2 points (x1, y1) and (x2 and y2) = sqrt((x2-x1)² + (y2-y1)²)

yes. This will give 16. And I think it's the answer. I don't know why they have the answer to be 36 here. Thanks.

Geofavor:
I bought the past questions booklet.

Oh...... You're really prepared to slaughter this exam oh

Oxytocin:
Abi nau..
If not maths, what else??

Hahaha... yeah.

In how many ways can 7 directors sit round a table
a) 720
b) 120
c) 24
d) 5040
shyneptune, oxytocin

Geofavor:
still pending...

The answer is 16 using graph analysis. Try this, draw out your x and y axes, label with -3,-2,,,,,,,,2,3.
Consider the points as co-ordinate(x,y), locate the points on the graph.
Hint: all sides are equal

Geofavor:
In how many ways can 7 directors sit round a table

a) 720

b) 120

c) 24

d) 5040

shyneptune, oxytocin

cyclic arrangement=(n-1)!

ShyNeptune:
Oh...... You're really prepared to slaughter this exam oh

Lols

ShyNeptune:
Oh...... You're really prepared to slaughter this exam oh

Lols

Oxytocin:
Expatiate bro

u=2v. u+v=-q/p. uv=r/p. From 1 and 2. 3v=-q/p. From 1 and 3. 2v^2=r/p. You should be able to continue from here by manipulating to equate the two "v".

thankyouJesus:
cyclic arrangement=(n-1)!

6! Right? The booklet I bought contains too many errors even after burning the former one

Geofavor:
6! Right? The booklet I bought contains too many errors even after burning the former one

It is well

Geofavor:
6! Right? The booklet I bought contains too many errors even after burning the former one

Lol....... Most of the editors of these past questions are just random guys in need of money..... They do not really know what they do.
Lamlard remains the real deal.

Guys, I'm ever loyal. Please, don't be upset with my absence and negligence. It's been stress and stress here in Akoka. I do get the mentions but before I show up, the questions are already solved by equally respected gurus.


You guys are doing a wonderful job here. And I'm confident that, with God's blessings on your side, you shall go places.