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Mathematicians Help Me Solve This Question by Timothy245(m): 8:11pm On Dec 27, 2017 |
1. X is partially constant and partially varies direct as Y when X=16, Y=2 When X=10, Y=5 (i)find the equation connecting X and Y (ii) X when y=8 (iii) Y when X=12. 2. In a class of 80 students, 30 offer Agric, 35 offer Agric, 40 offer chemistry. Given that 15 of them offer Agric and bio, 20 offer bio and chem. and 25 offer Agric and chem. (i)find the intersection of all the subjects. (ii) only 2 subjects (iii)chem & bio. |
Re: Mathematicians Help Me Solve This Question by Kylekent59: 8:16pm On Dec 27, 2017 |
Very easy question. |
Re: Mathematicians Help Me Solve This Question by respect80(m): 8:39pm On Dec 27, 2017 |
Kylekent59:Ar swear very easy kwesion |
Re: Mathematicians Help Me Solve This Question by Kylekent59: 11:17am On Dec 28, 2017 |
Timothy245: Check ur question 2. 30 offer agric,35 offer agric. Wrong? |
Re: Mathematicians Help Me Solve This Question by Matinoh: 5:01pm On Dec 28, 2017 |
I) the equation is X= a + by, .... equation (0). where a and b are constants. substituting values, x= 16 when y = 2 , and x= 10 when y=5 16 = a + 2b ................(1) 10 = a + 5b ................(2) subtract equation (2) from (1) will give, 6= -3b. divide both sides by -3 therefore b = -2 ... to get a, put b = -2 into equation (2), 10 = a + (-2×5), 10 = a -10 , 10+10=a, .. 20=a.. replace b = -2 and a = 20 into equation (0) therefore the required equation is X = 20 - 2y ..... equation (3). ii) x, when y = 8. just substitute into equation (3) I.e x = 20 - 2 ( 8 ) x= 20 - 16 x= 4. iii) same as above . y when x = 12 12= 20 - 2 y 12 - 20 = -2y -8 = -2y y = 4 ( divide both sides by -2).. I hope it was helpful |
Re: Mathematicians Help Me Solve This Question by Timothy245(m): 8:22pm On Dec 28, 2017 |
[quote author=Matinoh post=63687770]I) the equation is X= a + by, .... equation (0). where a and b are constants. substituting values, x= 16 when y = 2 , and x= 10 when y=5 16 = a + 2b ................(1) 10 = a + 5b ................(2) subtract equation (2) from (1) will give, 6= -3b. divide both sides by -3 therefore b = -2 ... to get a, put b = -2 into equation (2), 10 = a + (-2×5), 10 = a -10 , 10+10=a, .. 20=a.. replace b = -2 and a = 20 into equation (0) therefore the required equation is X = 20 - 2y ..... equation (3). ii) x, when y = 8. just substitute into equation (3) I.e x = 20 - 2 ( 8 ) x= 20 - 16 x= 4. iii) same as above . y when x = 12 12= 20 - 2 y 12 - 20 = -2y -8 = -2y y = 4 ( divide both sides by -2).. I hope it was helpful Thanks alot! |
Re: Mathematicians Help Me Solve This Question by Timothy245(m): 8:24pm On Dec 28, 2017 |
respect80:u Can't Solve It Noni |
Re: Mathematicians Help Me Solve This Question by Timothy245(m): 8:46pm On Dec 28, 2017 |
Kylekent59:that's how it was. |
Re: Mathematicians Help Me Solve This Question by respect80(m): 10:20pm On Dec 28, 2017 |
Timothy245:Abeggi. Dis simple kwesion mtcheeeew |
Re: Mathematicians Help Me Solve This Question by Timothy245(m): 4:46am On Dec 29, 2017 |
respect80:Then, prove urself by using another method to solve it. |
Re: Mathematicians Help Me Solve This Question by Timothy245(m): 4:49am On Dec 29, 2017 |
Matinoh, tanx alot. |
Re: Mathematicians Help Me Solve This Question by AlanTuringAI: 6:06am On Dec 29, 2017 |
Timothy245:You should know there's a mistake in what you type. How will you repeat Agric twice, that 30 offer Agric, 35 offer Agric again? It should instead going by the next sentence in the question be: 30 offer Agric, 35 offer Bio. |
Re: Mathematicians Help Me Solve This Question by Nobody: 8:14am On Dec 29, 2017 |
Timothy245: lol, calm down. If he says it's simple that's because it actually is. he may feel he is insulting himself by just solving it. some person just have this innate pride. I was once like that. you already have a solution by Timothy245, I'd av provided one for you. |
Re: Mathematicians Help Me Solve This Question by respect80(m): 10:46am On Dec 29, 2017 |
Timothy245: Don't worry I will solve it veeeeery soon |
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