ijezie has twice as many apples as Mohammed,and Mohammed has three times as many apples as bamidele. if the three men have a total of 360 apples,find the number owned by Mohammed.

Nelsonmoney:
ijezie has twice as many apples as Mohammed,and Mohammed has three times as many apples as bamidele. if the three men have a total of 360 apples,find the number owned by Mohammed.

Let ijezie's apples be represented as i, Mohammed's rep. as m and bamidele's as b

from the first expression;
i = 2m ..........*

second expression;
m = 3b,
therefore, b = m/3 .........**

third expression;
i + m + b = 360 .........***

putting eqn* and eqn** in eqn***:
i + m + b = 360 .........***
2m + m + m/3 = 360,
3m + m/3 = 360,
(9m + m)/3 = 360,
10m / 3 = 360,
10m = 360 × 3,
10m = 1080,

dividing both sides by 10;
m = 108

therefore, Mohammed has 108 apples

dejt4u:

Let ijezie's apple is represented by i, Mohammed's rep. by m and bamidele's by b

from the first expression;
i = 2m ..........*

second expression;
m = 3b,
therefore, b = m/3 .........**

third expression;
i + m + b = 360 .........***

putting eqn* and eqn** in eqn***:
i + m + b = 360 .........***
2m + m + m/3 = 360,
3m + m/3 = 360,
(9m + m)/3 = 360,
10m / 3 = 360,
10m = 360 × 3,
10m = 1080,

dividing both sides by 10;
m = 108

therefore, Mohammed has 108 apples

Thank you

Above poster is correct...

Nelsonmoney:
Thank you

you're welcome

[quote author=dejt4u post=72164884]
Let ijezie's apple is represented by i, Mohammed's rep. by m and bamidele's by b

from the first expression;
i = 2m ..........*

second expression;
m = 3b,
therefore, b = m/3 .........**

third expression;
i + m + b = 360 .........***

putting eqn* and eqn** in eqn***:
i + m + b = 360 .........***
2m + m + m/3 = 360,
3m + m/3 = 360,
(9m + m)/3 = 360,
10m / 3 = 360,
10m = 360 × 3,
10m = 1080,

dividing both sides by 10;
m = 108

According to his textbook your answer is correct, but i was wondering if there's diff.or another method I mean simple solution to this please

Assume the quantity of apple each has is X, there for

BIMEDELE HAS X

Mohammmed has 3 time X of Bamidele = 3X

Ijezie has 2 (3X) of Mohammed = 6X

total apples is 360

there
X+3X+6X = 360
10X= 360

x= 360/10
x= 36

Mohammed is 3* (36)= 108

sexy74:
Assume the quantity of apple each has is X, there for

BIMEDELE HAS X

Mohammmed has 3 time X of Bamidele = 3X

Ijezie has 2 (3X) of Mohammed = 6X

total apples is 360

there
X+3X+6X = 360
10X= 360

x= 360/10
x= 36

Mohammed is 3* (36)= 108

Less complex Thanks

All these Emmanuella’s Uncle

dejt4u:

Let ijezie's apples be represented as i, Mohammed's rep. as m and bamidele's as b

from the first expression;
i = 2m ..........*

second expression;
m = 3b,
therefore, b = m/3 .........**

third expression;
i + m + b = 360 .........***

putting eqn* and eqn** in eqn***:
i + m + b = 360 .........***
2m + m + m/3 = 360,
3m + m/3 = 360,
(9m + m)/3 = 360,
10m / 3 = 360,
10m = 360 × 3,
10m = 1080,

dividing both sides by 10;
m = 108

therefore, Mohammed has 108 apples

I duff my hat for u

Simple tin. I got close my eyes solve am sef

OneCorner:
Simple tin. I got close my eyes solve am sef

Prove your words! solve the question with a different method.

sexy74:
Assume the quantity of apple each has is X, there for

BIMEDELE HAS X

Mohammmed has 3 time X of Bamidele = 3X

Ijezie has 2 (3X) of Mohammed = 6X

total apples is 360

there
X+3X+6X = 360
10X= 360

x= 360/10
x= 36

Mohammed is 3* (36)= 108

Maths made easy! Nice

I need an app programmer

40

I rembered I was solving maths for people back then in secondary school and people were hailing me but now I can see that those mathematics I solved then couldn't fetch me money now so what's the need?

Nelsonmoney:
ijezie has twice as many apples as Mohammed,and Mohammed has three times as many apples as bamidele. if the three men have a total of 360 apples,find the number owned by Mohammed.

My approach is thus:

Let Mohammed apples = x
:. Ijezie's apples = 2x. (Ijezie has twice as many apples as Mohammed)
:. Bamidele's apples = x/3 (Mohammed has 3 times as many apples as Bamidele)

Since the the sum of their apples = 360

:. X + 2x + x/3 = 360
Multiply throughout by 3 to rationalise the equation

-> 3x + 6x + x = 1080
:. 10x = 1080
Divide through by 10
:. X = 108

Therefore, Mohammed share of apples = 108

Mankosi:
I rembered I was solving maths for people back then in secondary school and people were hailing me but now I can see that those mathematics I solved then couldn't fetch me money now so what's the need?

Bros I know of a man that tutors people's children math only and he is living fine with family and a nice ride. Math teachers are needed any day any time it's just that you have to present your self where they are needed

Mankosi:
I rembered I was solving maths for people back then in secondary school and people were hailing me but now I can see that those mathematics I solved then couldn't fetch me money now so what's the need?

Solving maths or any subject generally does not necessarily means it's gonna bring funtune to your bank account but of course to some persons it does. I'm come to realise that all courses are of paramount use in our day to day lives especially mathematics. And again it's widen our horizon.

Festy4u:




My approach is thus:

Let Mohammed apples = x
:. Ijezie's apples = 2x. (Ijezie has twice as many apples as Mohammed)
:. Bamidele's apples = x/3 (Mohammed has 3 times as many apples as Bamidele)

Since the the sum of their apples = 360

:. X + 2x + x/3 = 360
Multiply throughout by 3 to rationalise the equation

-> 3x + 6x + x = 1080
:. 10x = 1080
Divide through by 10
:. X = 108

Therefore, Mohammed share of apples = 108

I'm not sure your workings is accurate. when you multiply by 3, you left out x/3

The great one.i don't know if you are getting it or not ooo but you kinda taking me back memory lane.my secondary school old days.

Nelsonmoney:
I'm not sure your workings is accurate. when you multiply by 3, you left out x/3

It's accurate! When you multiply the ratio (x/3) by 3, you get x.

i.e. X/3 x 3 = x

Festy4u:


It's accurate! When you multiply the ratio (x/3) by 3, you get x.
i.e. X/3 x 3 = x

Y did you multiply the equation by 3?

Nelsonmoney:
Y did you multiply the equation by 3?

I did to take off the fractional term (x/3)

NB: When solving equations involving fractions, it's simpler multiplying throughout the equation by the denominator value (in this case 3). In that way, you will rationalise the equation and make it easier to solve.

Festy4u:



I did to take off the fractional term (x/3)

NB: When solving equations involving fractions, it's simpler multiplying throughout the equation by the denominator value (in this case 3). In that way, you will rationalise the equation and make it easier to solve.

Noted Thank you

Nelsonmoney:
Noted Thank you

You are welcome!