Samuelfuta's Posts
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the sequence are a,ar,ar^2,ar^3..... square of the sequence a^2,a^2r^2,a^2r^4...... Cube of the sequence a^3,a^3r^3,a^3r^6..... Sum to infinity=a/r-1 S=a/r-1----------(1) 2S=a^2/r^2-1----------(2) (64/13)S=a^3/r^3-1------(3) Frm equation 2. 2S=a^2/(r-1)(r+1) 2S=(a/r-1)(a/r+1) a/r-1=S:- 2S=S(a/r+1)--------(4) From equation 3 (64/13)S=a^3/r^3-1 (64/13)S=a^3/(r-1)(r^2+r+1) (64/13)S=(a/(r-1))(a^2/r^2+r+1) (64/13)S=S(a^2/r^2+r+1)------4 By solving these simultaneously We will get S=4 And d first three term. 8/3,8/9,8/27 |
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