₦airaland Forum

phemmyfour:
The exercise is full of error. The samples are three different operations. There is/are suppose to be dot(s) inscribed in the "O" at the top to define the operator to use

O•
8 P 4 = 8 - 4 = 4

O••
10 P 6 = 10 + (2*6)= 22

O•••
15 P 6= (15*3)+ 6 = 51


Hence
1. 13 or 19 (1st or 2nd approach)

2. 7 (2nd approach)

3. 4 or 16 (1st or 2nd approach)

4. 26 (2nd approach)

5. 10 or 55 ( 1st or 2nd approach)

This question uses Highest Common Factor