Triplee02's Posts
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What do i need to get a credit card from any nigeria bank. Pls tell of the banks that i can get this credit card from i only know GTB bank. Tanx |
I added this code to my smf forum index.template: <div class="ads"><?php include ("ads.php" <br/></div> ?> and immediately my site went blank. What went wrong? |
I own am smf forum and i want to really make money from it. I considered placing mobile ads on it but i discovered it does not display on a web browser. Pls advise me on how i can cool cash from the forum. |
Pls help me. My server is going crazy. How can i move it to another server without loosing my members and post. Also can i upgrade the forum and still retain my members. Am using simple machine forum 1.11. |
If you didnt get my mail report your email |
Ask it shall be given unto you |
Dats opera 5.0 beta 3, download it at sharemobile |
Check computer village. |
Fitzterun:tanx for the info, @all alway try 2 appreciate info |
Check your apn |
Use dis: 80.239.242.253:80 then simply put dis on your custom 1: wap.mtnonline.com without d server4.operamini.com:80 enjoy. Post testimony and bugs here. |
I gat no credit card, and i need a cheap .com domain name. Pls help! |
Thanx, get rid of d mysql_fetch_array()? Pls xplain i dnt understand. |
I only posted d code dat generated d error, dis d error comment: warning: mysql_fetch_array(): supplied argument is not valid mysql result resource in /www/zxq.net/m/w/a/mwap/htdocs/index.php on line 63. tanx 4 your help |
Pls help me correct dis code: $count = mysql_fetch_array(mysql_query("SELECT COUNT(*) FROM users WHERE hin >= '3'" );if($count[0]=="0" {echo "<div class='leftline'>"; echo "<img src='images/ran.gif' alt=''/>No Site Active Now"; echo '</div>'; }else{ $sql ="SELECT * FROM users WHERE hin '3' ORDER BY RAND() LIMIT 1"; $sites = mysql_query($sql); while ($site = mysql_fetch_array($sites)) { echo "<div class='leftline'>"; echo "<img src='images/ran.gif' alt=''/><a href='vsites.php?sid=$site[0]'>$site[4]</a><br/>"; echo '</div>'; } i ran it it generated errors pls help |
I used dis d below script while creating a mobile toplist and it generated error. Pls correct me: <?php header('Content-type: text/html; charset=utf-8'); header('Cache-Control: no-store, no-cache, must-revalidate'); echo "<?xml version=\"1.0\" encoding=\"ISO-8859-1\" ?>"; echo "<!DOCTYPE html PUBLIC \"-//WAPFORUM//DTD XHTML Mobile 1.0//EN\" \"http://www.wapforum.org/DTD/xhtml-mobile10.dtd\">"; echo "<link rel=\"StyleSheet\" type=\"text/css\" href=\"style.css\" />"; echo "<html xmlns=\"http://www.w3.org/1999/xhtml\">"; include_once("config.php" ;include_once("logics.php" ;connectdb(); echo "<title>$sn</title>"; echo "<head>"; ?> <? echo "<body>"; echo "<div class='center'>"; echo "Wed, 10 September 2008<br/>"; echo '</div>'; echo "<div class='image'>"; echo "<img src='images/logo.gif' alt=''/><br/>"; echo '</div>'; echo "<div class='center'>"; echo ' Bookmark Now!<br/> http://mtop.tk '; echo '<br/>'; echo "<a href=''>$adn</a><br/>"; echo "<a href=''>$adn2</a>"; echo '</div><br/>'; echo "<div class='left'>"; echo 'Interesting<br/>'; echo '</div>'; echo "<div class='leftline'>"; echo " <img src='images/top.gif' alt=''/> <a href='top10.php'>Top 10</a><br/>"; echo '</div>'; echo "<div class='leftlight'>"; echo " <img src='images/search.gif' alt=''/> <a href='search.php'>Search Engine</a><br/>"; echo '</div>'; echo "<div class='leftline'>"; echo " <img src='images/new.gif' alt=''/> <a href='newsites.php'>New Sites</a><br/>"; echo '</div>'; echo "<div class='left'>"; echo ' Random:<br/>'; echo '</div>'; $count = mysql_fetch_array(mysql_query("SELECT COUNT(*) FROM users WHERE hin >= '3'" );if($count[0]=="0" {echo "<div class='leftline'>"; echo "<img src='images/ran.gif' alt=''/>No Site Active Now"; echo '</div>'; }else{ $sql ="SELECT * FROM users WHERE hin '3' ORDER BY RAND() LIMIT 1"; $sites = mysql_query($sql); while ($site = mysql_fetch_array($sites)) { echo "<div class='leftline'>"; echo "<img src='images/ran.gif' alt=''/><a href='vsites.php?sid=$site[0]'>$site[4]</a><br/>"; echo '</div>'; } } echo "<div class='left'>"; echo "Categories:"; echo '</div>'; $css_row = 'odd'; $cats = mysql_query("SELECT * FROM cats" ;while($cat = mysql_fetch_array($cats)) { if($css_row == 'odd') { $css_row = 'even'; }else{ $css_row = 'odd'; } echo "<div class='$css_row'>"; echo "<img src=\"images/cube.gif\" alt=\"x\"/> <a href=\"vcats.php?cid=$cat[0]\">$cat[1]</a><br/>"; echo '</div>'; } echo "<br/><div class='left'>"; echo "Add/Edit Your Site<br/>"; echo '</div>'; echo "<div class='leftline'>"; echo "<img src='images/edit.gif' alt=''/> <a href='login.php'>Login/Edit</a><br/>"; echo '</div>'; echo "<div class='left'>"; echo "<img src='images/add.gif' alt=''/> <a href='reg_user.php?ac=reg'>Sign up</a><br/>"; echo '</div>'; echo "<div class='center'>"; echo "$sn ©"; echo '</div>'; echo "</body>"; echo "</html>"; ?> pls check d error here: http://fundisc.tk pls help me |
thanx it worked. My problem nw is connectin to my database. Is dis format correct <?php $con = mysql_connect("localhost","romeo",abc123" ; if (!$con) die('could not connect: '. mysql_error()); //some code mysql_close($con); ?> & i used my subdomain 4 d localhost, but i dont knw what to use 4 d user & password. Pls help! Thanx 4 ur help i do appreciate |
Am actually working on a mobile download site but my problem is displaying files on a php page. I want 2 know should i just store d file details on a database table and use mysql select statement or is there any other better way of doing it? I learnt people just upload & their files just arrange themselves. Pls help! |
1 2 (of 2 pages)
<br/></div> ?> and immediately my site went blank. What went wrong?