₦airaland Forum

A train is traveling down a straight track at 29 m/s when the engineer applies the brakes, resulting in an acceleration of −1.0 m/s2 as long as the train is in motion. How far does the train move during a 58-s time interval starting at the instant the brakes are applied?

urgent answer needed...

5.8m/s

ATMC: 5.8m/s

how sure are you?

s= ut + 1/2 at*sq. Ur ans wil be zero. Meaning d train would av stopped b4 dat time

S=ut + 1/2at^2
is the total distance covered by the train. . . .
S=ut - 1/2at^2
is the distance coverd after the brake was applied. . .
But if you are give a -ve acceleration i.e decceleration use the first one cuz it wil automatically change back the sign or use the 2nd one without observing the -ve sign in the retardation. . .

ATMC: 5.8m/s

not velocity bt distance is required

S=(29x58) + [1/2(-1x58^2)]

S=1682-1682
=0m
therefore, the train was brought to rest at the application of the brake by the Engineer. .

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