InvertedHammer: This is a programming question for beginners!

Nice try though

Omo elefo , who ask you ?

ekt_bear didn't ask whether it was for novices or superman, all he said was solve it !!!

Heh, funny that this made the front page several months after.

Javanian:

Everything on Planet Earth is Esoteric...

You realise i used the word 'very' right.
Besides front page topics should appeal to a wider range of audience.
If i come out ranting about my subspeciality in medicine, i wonder how many people will contribute.

jacob05: @lordZOUGA i hail ooooo
I'm Quite new to C/C++ but here is my lengthy version...

#include <string>
#include <vector>
#include <functional>
#include <iostream>
#include <algorithm>
#include <sstream>

using namespace std;

void split(const string& s, char c,
           vector<string>& v) {
   string::size_type i = 0;
   string::size_type j = s.find(c);

   while (j != string::npos) {
      v.push_back(s.substr(i, j-i));
      i = ++j;
      j = s.find(c, j);

      if (j == string::npos)
         v.push_back(s.substr(i, s.length( )));
   }
}

bool isIntergerFamily(string value){
      int myint =0;
      stringstream(value) >> myint;
      if (myint != 0){
          return true;
      }else{
          return false;
      }
}


template <class T>
void printOut(vector<T> temp ){
       for (int i = 0; i < temp.size( ); ++i) {
             cout << temp[i] << " ";
        }
}

template <class T>
void maskOrder(string type, vector<T> inputVector, vector<string>& maskVector ){
       stringstream ss;
       for (int i = 0,counter = 0; i < maskVector.size( ) && counter < inputVector.size() ; ++i) {
             if(type == "int" && isIntergerFamily(maskVector[i])){
                 ss.str("";
                 ss << inputVector[counter];
                 maskVector[i] =  ss.str();
                 counter++;
             }
             if(type == "string" && !isIntergerFamily(maskVector[i])){
                maskVector[i] = inputVector[counter];
                counter++;
             }
       }
}

int main( ) {
   vector<string> splittedString;
   vector<string> tempVector;
   vector<string> stringVector;
   vector<int> intergersVector;
   int myint;

   string inputString;
   cout << "Enter String :";
   getline(cin,inputString);
   split(inputString, ' ', splittedString);

   tempVector = splittedString;
   sort(tempVector.begin(),tempVector.end());

   for (int i = 0; i < tempVector.size( ); ++i) {
      if (isIntergerFamily(tempVector[i])){
          stringstream(tempVector[i]) >> myint;
          intergersVector.push_back(myint);
      }else{
          stringVector.push_back(tempVector[i]);
      }
   }
   maskOrder("string",stringVector,splittedString);
   maskOrder("int",intergersVector,splittedString);
   printOut(splittedString);
}

this code breaks if the input contains zero

pak: ekt_bear, I feel like punching you for depriving me of my sleep really. Saw this as I was about to hit the sack and couldn't blink until I cracked it.

My fav pastime is Python but since I dont us python in my day job, I've been terribly rusty.
Infact the stuff took me well over an hour considering I was even just installing the python executable on my new sis.

However, having lost out in the competition to be the fastest, I strove for the next glorious crown - to be the most elegant

Guess I achieved it. 19 lines of code

Prince actually did the stuff in 18 lines (with the white spaces stripped of) but the script didn't run when I tried it out. I guess he has to check out one or two stuffs in the code.

. . .and the Java solutions ? puleeeeeeeeaaaaaaaaaase. is that the code to calculate the GDP of Nigeria ?
Really, I appreciate you guys (the programmers) but its the lang that I detest.

To The C++ guy, I believe C++ can do better than that, That was actually my first love. but kudos though.



Check out my solution

http://pastebin.com/W3swZVfd

Well, thanks bro. My C++ version could have been 'elegant' as you claim your solution is if C++ had provided robust string processing classes like python does (li.split() ) and also a portable mechanism to check for type (s.isdigit() python provided). Guessed those took the glory . I'm still waiting for a better solution though

lordZOUGA:
this code breaks if the input contains zero

Nice catch boss! Fixed

#include <string>
#include <vector>
#include <functional>
#include <iostream>
#include <algorithm>
#include <sstream>
using namespace std;
void split(const string& s, char c,
           vector<string>& v) {
   string::size_type i = 0;
   string::size_type j = s.find(c);
   while (j != string::npos) {
      v.push_back(s.substr(i, j-i));
      i = ++j;
      j = s.find(c, j);
      if (j == string::npos)
         v.push_back(s.substr(i,
s.length( )));
   }
}
bool isIntergerFamily(string value){
      int myint =0;
      stringstream(value) >> myint;
 return ((myint != 0) || (value == "0"  )  ) ? true : false;
      
}
template <class T>
void printOut(vector<T> temp ){
       for (int i = 0; i < temp.size( ); +
+i) {
             cout << temp[i] << " ";
        }
}
template <class T>
void maskOrder(string type,
vector<T> inputVector,
vector<string>& maskVector ){
       stringstream ss;
       for (int i = 0,counter = 0; i <
maskVector.size( ) && counter <
inputVector.size() ; ++i) {
             if(type == "int" &&
isIntergerFamily(maskVector[i])){
                 ss.str("" ;
ss << inputVector
[counter];
                 maskVector[i] =  ss.str();
                 counter++;
             }
             if(type == "string" && !
isIntergerFamily(maskVector[i])){
                maskVector[i] =
inputVector[counter];
                counter++;
             }
       }
}
int main( ) {
   vector<string> splittedString;
   vector<string> tempVector;
   vector<string> stringVector;
   vector<int> intergersVector;
   int myint;
   string inputString;
   cout << "Enter String :";
   getline(cin,inputString);
   split(inputString, ' ',
splittedString);
   tempVector = splittedString;
   sort(tempVector.begin()
,tempVector.end());
   for (int i = 0; i < tempVector.size
( ); ++i) {
      if (isIntergerFamily(tempVector
[i])){
          stringstream(tempVector[i])
>> myint;
          intergersVector.push_back
(myint);
      }else{
          stringVector.push_back
(tempVector[i]);
      }
   }
   maskOrder("string",stringVector,
splittedString);
   maskOrder("int",intergersVector,
splittedString);
   printOut(splittedString);
}

pastebin.com/rWhEvaYw

pak: ekt_bear, I feel like punching you for depriving me of my sleep really. Saw this as I was about to hit the sack and couldn't blink until I cracked it.

My fav pastime is Python but since I dont us python in my day job, I've been terribly rusty.
Infact the stuff took me well over an hour considering I was even just installing the python executable on my new sis.

However, having lost out in the competition to be the fastest, I strove for the next glorious crown - to be the most elegant

Guess I achieved it. 19 lines of code

Prince actually did the stuff in 18 lines (with the white spaces stripped of) but the script didn't run when I tried it out. I guess he has to check out one or two stuffs in the code.

. . .and the Java solutions ? puleeeeeeeeaaaaaaaaaase. is that the code to calculate the GDP of Nigeria ?
Really, I appreciate you guys (the programmers) but its the lang that I detest.

To The C++ guy, I believe C++ can do better than that, That was actually my first love. but kudos though.



Check out my solution

http://pastebin.com/W3swZVfd

My logic is undeniable! I can evn make it shorter....
Lmao @ GDP of Nigeria....

and then the contest turns to a test of code length..

omo_to_dun:

Haba! You removed all the empty lines and cheated your way to 19 lines. Well this is mine and it is 15 lines.

---

Haba! You removed all other lines leaving only the your method and cheated your way to 15 lines.

l =  "car truck 8 4 bus 6 1"
lint, lalph, lnew  = [],[],[]
for i in l.split():
    if i.isdigit():
        lint.append(i) 
    else:
        lalph.append(i)
lalph.sort(reverse=True)
lint.sort(reverse=True)        
for i in l.split():
    if i.isdigit():
        lnew.append(lint.pop()) 
    else:
        lnew.append(lalph.pop())
print " ".join(map(str, (lnew)))

another C++ implementation http://pastebin.com/KbgsKFiG

omo_to_dun: @PRINCE

I am not denying it. I was only making a point. I wanted to show that if we all removed the empty lines and made some clever adjustments, our code would be small.

owky...true that

lordZOUGA: and then the contest turns to a test of code length..

Not a big deal bro,

Many of the guys on the thread have already gotten the logic of the solution and prince did it in less than 30 mins to boot.

It was just a way of introducing more fun to the whole process. No biggie !


I don't know if you are a pythonista, so maybe just maybe you might not understand the intense pleasure of writing elegant minimalist code.


I got hooked on the whole concept bout four years back when I saw a contest on the web to write the shortest code to extract youtube videos as flv.

Definitely, Perl came first (with about just 2 lines or so), awk followed and Python was third.

omo_to_dun: @PRINCE

I am not denying it. I was only making a point. I wanted to show that if we all removed the empty lines and made some clever adjustments, our code would be small.

Bro, the reason why I didn't mention yours was cos as much as your logic might have been right. The code still didn't meet up with what ekt_bear specified, ability to receive input from stdin and output to stdout, for obvious reasons

l =  "car truck 8 4 bus 6 1"
lint, lalph, lnew  = [],[],[]
for i in l.split():
    if i.isdigit():
        lint.append(i) 
    else:
        lalph.append(i)
lalph.sort(reverse=True)
lint.sort(reverse=True)        
for i in l.split():
    if i.isdigit():
        lnew.append(lint.pop()) 
    else:
        lnew.append(lalph.pop())
print " ".join(map(str, (lnew)))

@Prince - cool bro - 15 lines,
now let me see how far I can refactor mine

I went on an overdrive and came up with a solution that will definitely take something special to beat.

6 lines !!!.

The only thing I can say is, PYTHON IS SWEET


You can check it out !

li = raw_input("enter ".split(' ')
intarr,wordarr,finalarr = [],[],[]
[intarr.append(elem) if elem.isdigit() else wordarr.append(elem) for elem in li ]
wordarr.sort()
intarr.sort()
print [intarr.pop(0)	 if elem.isdigit() else wordarr.pop(0) for elem in li ]

pak: I went on an overdrive and came up with a solution that will definitely take something special to beat.

6 lines !!!.

The only thing I can say is, PYTHON IS SWEET


You can check it out !

li = raw_input("enter ".split(' ')
intarr,wordarr,finalarr = [],[],[]
[intarr.append(elem) if elem.isdigit() else wordarr.append(elem) for elem in li ]
wordarr.sort()
intarr.sort()
print [intarr.pop(0)	 if elem.isdigit() else wordarr.pop(0) for elem in li ]

lool i have similar code (6lines) too...was just waitn for someone to up the limit ....but id give it to you as urs contained less characters