Express 1/(x^3-1) in partial fraction.:-(

1/(x^3-1) = 1/(x^-2)

= 1/1/x^2 = 1*x^2

= x^2 or x(squared)

Guy, you gonna pay me for this??

1/(x^3-1)=1/(x-1)^3

»»1/(x-1)^3=A/(x-1) +B/(x-1)^2 +C/(x-1)
^3•••••eqna1
Solve partially,
»»1=A(x-1)^2 +B(x-1) + C•••••eqn2

Let x=1

»»1=A(0)^2 +B(0) +C

»» There4 C=1

Also,frm eqn2,we expand

»»1=Ax^2 - 2Ax + A +Bx -1 +C

Comparing coefficients of x,

»»x^2[0] =A

Automatically,A=0

»»x[0]=-2A +B•••••eqn3

»»Constant[1] =A +C

Sub.A=0 into eqn3 to get B

Thus B=0.