₦airaland Forum

Hi all,

Please I want some help with the python program below. I started learning python programming late last year, December 2012. As an extra credit, I decided to practice my skill in writing functions, so I wrote a program to convert Celsius to Fahrenheit and vice versa. To me, the program looks ok as I have tried my best to fix all errors but this annoying error keeps coming up:

File "farcel.py", line 17
elif value == "2":
SyntaxError: invalid syntax


Here is the program:


print "******************************************************"
print " TEMPERATURE CONVERTER"
print "******************************************************"

def temp_conv():
print "This application converts Celsius to Farenheit and vice versa."
print "1. Press 1 if you want to convert Celsius to Farenheit."
print "2. Press 2 if you want to convert Farenheit to Celsius."

value = raw_input('> ')

if value == "1":
print "Please enter the value in Celsius you want to convert to Farenheit.\n"
cel_temp = raw_input('> ')
far = (1.8 * float(cel_temp)) + 32
print "The value in farenheit is: %r degree farenheit" % str(far)
elif value == "2":
print "Please enter the value in Farenheit you want to convert to Celsius.\n"
far_temp = raw_input('> ')
cel = 0.56 * (float(far_temp) - 32)
print "The value in celsius is: %r degree celsius" % str(cel)
else:
print "Please choose option 1 or 2."



temp_conv()


I appreciate every contribution to help me fix this bug.

Thank you.

upload a snapshot so we can see ur indents

Here it is. Hope you can make do with this





[img][/img]

Sorry about that. I'm finding it difficult to upload images on here. I copied the screenshot on Microsoft Word but can't upload it.

Try uploading the .py script.

Hey man,your syntax is invalid cos elif=="2" is wrong.it is elif variable==2:
#give four spaces then do stuff

Creatrixity: Hey man,your syntax is invalid cos elif=="2" is wrong.it is elif variable==2:
#give four spaces then do stuff

Hey man, thanks for your contribution.

Ummm...I don't see nothing wrong with that line.
I wrote:
elif value == "2":

'value' being the variable and "2" being the option entered.

I'm frustrated with trying to upload a snapshot of the code. It's a nightmare.

Hello nep2ra.
I copied your program, gave it the required indentations, and ran it on my linux machine and it worked fine. In fact without a single exception raised. It is likely then that the error you encountered has to do with indentation. I have tried to attach the correctly indented version, but if that doesn't work fine here is an information on the indentation I employed: (I used Tab for indentation):

def temp_conv(): ##No Indentation
print "This application converts Celsius to Farenheit and vice versa." ## A single Tab
print "1. Press 1 if you want to convert Celsius to Farenheit." ## A single Tab
print "2. Press 2 if you want to convert Farenheit to Celsius." ## A single Tab

value = raw_input('> ') ## A single Tab

if value == "1": ## A single Tab
print "Please enter the value in Celsius you want to convert to Farenheit.\n" ## Two Tabs
cel_temp = raw_input('> ') ## Two Tabs
far = (1.8 * float(cel_temp)) + 32 ## Two Tabs
print "The value in farenheit is: %r degree farenheit" % str(far) ## Two Tabs
elif value == "2": ## A single Tab
print "Please enter the value in Farenheit you want to convert to Celsius.\n" ## Two Tabs
far_temp = raw_input('> ') ## Two Tabs
cel = 0.56 * (float(far_temp) - 32) ## Two Tabs
print "The value in celsius is: %r degree celsius" % str(cel) ## Two Tabs
else: ## A single Tab
print "Please choose option 1 or 2." ## Two Tabs

temp_conv() ## No Tab


Have fun Pythrogramming!
jide

Hi jide,
Thanks for your contribution.
The original program has all the correct indentation. Copying and pasting the code on Nairaland is what makes it look like there's no indentation.
I will try your suggestion.

Thanks once again.

Have a good day.