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Web Contractor: NEW PUZZLE
Given the array below,write a PHP conditional statement that returns 2,4,8,10

<?php

$even_numbers = array(2,4,6,8,10,12);

?>;

Difficulty Level: Intermediate
Hint:Use Loops

Edit: Remove the last Comma from your result

<?php

$even_numbers = array(2,4,6,8,10,12);

//using each value in even numbers array

foreach($even_numbers as $new)
{
    if (($new == 6) || ($new == 12))
     {   continue;
     }
        echo $new;
        if($new ==10)
{ break;
}
        echo ",";
}

?>

<?php
  $even_numbers = array('2','4','6','8','10','12');
 $arr = array(); 
 $out = array('6','12');
    foreach($even_numbers as $value) {
   if(!in_array($value, $out)){
   $arr[] = $value; 
}
} 
  $value = implode(",", $arr); 
  echo $value;

?>

ActiveMan: <?php
$even_numbers = array('2','4','6','8','10','12');

$remove_12_6_from_array = array_diff($even_numbers , array('6', '12'));

echo $even_numbers = implode ( "," , $remove_12_6_from_array );

?>

YOU DO NOT NEED ANY LOOP.

Gerardcole: I usually type on my android device so sorry for the errors. I didn't close a line with ;. Also I didn't close the if containing the in_array(), then I interchanged the position of the values in in_array. So editing the former post, here is the solution.


Okay. Since according to our puzzle provider, Judinho59 didn't get the required output, I ll provide my own solution. The puzzle is kinda tricky.

Given array('2', '4', '6', '8', '10', '12')
To return 2,4,8,10 (Removing 6 and 12 and the last comma that's supposed to appear after 10)

I'm also gonna attack in two methods.

1. Using PHP in_array()

<?php
/* First we set the values we do not want in an array */
$unwanted = array('6', '12');

/*Then we set a variable which will help in placing comma's */

$counter = 0;

/*Then to the code */
$ev = array('2', '4', '6', '8', '10', '12');

foreach($ev as $a)
{
if(!in_array($a, $unwanted))
/*Checks if $a is not in our unwanted list before proceeding*/
{
if($counter > 0)
/* Since we don't want it after our last value but after every other, we run this before the value. > 0 here explains that we don't want it before the first as our counter is still 0 before this line */
{
echo ', ';
}
echo $a;
$counter++;
/*In PHP ++ is same as +1 so whenever it gets to the line above, the counter is increased buly 1*/
}

}
?>

2. Using the modulus operator '%'

The modulus %, in PHP returns the remainder in a division operation. E.g 7 % 5 returns 2 (i.e 1 remaining 2), 10 % 5 returns 0 (i.e 2 remaining 0).

I wouldn't be explaining the lines I already explained in example 1 above.

<?php
$div = 6;
/* Since all the unwanted numbers are divisible by 6. */

$counter = 0; //As explained in e.g 1 above

$ev = array('2', '4', '6', '8', '10', '12');

foreach($ev as $a)
{
if($a % $div != 0)
/*Since it will return 0 for our unwanted 6 and 12*/
{
if($counter > 0)
{
echo ', '; //As explained in e.g 1 above
}
echo $a;
$counter++; //As explained in e.g 1 above.
}
}
?>


The above returns:
/*From E.g 1 */

2, 4, 8, 10

/*From e.g 2 */

2, 4, 8, 10

ActiveMan: <?php
$even_numbers = array('2','4','6','8','10','12');

$remove_12_6_from_array = array_diff($even_numbers , array('6', '12'));

echo $even_numbers = implode ( "," , $remove_12_6_from_array );

?>

YOU DO NOT NEED ANY LOOP.

Judinho59:

<?php
  $even_numbers = array('2','4','6','8','10','12');
 $arr = array(); 
 $out = array('6','12');
    foreach($even_numbers as $value) {
   if(!in_array($value, $out)){
   $arr[] = $value; 
}
} 
  $value = implode(",", $arr); 
  echo $value;

?>

Result:
2,4.8,10

Gerardcole: <?php
/* First we set the values we do not want in an array */
$unwanted = array('6', '12');

/*Then we set a variable which will help in placing comma's */

$counter = 0;

/*Then to the code */
$ev = array('2', '4', '6', '8', '10', '12');

foreach($ev as $a)
{
if(!in_array($a, $unwanted))
/*Checks if $a is not in our unwanted list before proceeding*/
{
if($counter > 0)
/* Since we don't want it after our last value but after every other, we run this before the value. > 0 here explains that we don't want it before the first as our counter is still 0 before this line */
{
echo ', ';
}
echo $a;
$counter++;
/*In PHP ++ is same as +1 so whenever it gets to the line above, the counter is increased buly 1*/
}

}
?>

<?php
$div = 6;
/* Since all the unwanted numbers are divisible by 6. */

$counter = 0; //As explained in e.g 1 above

$ev = array('2', '4', '6', '8', '10', '12');

foreach($ev as $a)
{
if($a % $div != 0)
/*Since it will return 0 for our unwanted 6 and 12*/
{
if($counter > 0)
{
echo ', '; //As explained in e.g 1 above
}
echo $a;
$counter++; //As explained in e.g 1 above.
}
}
?>


The above returns:
/*From E.g 1 */

2, 4, 8, 10

/*From e.g 2 */

2, 4, 8, 10

Web Contractor:
N.B.I will not be responsible for any system malfunction during testing!

<?php
    for (;; ) {
        print "infinite loop!\n";
    }
?>

<?php
    while(1) {
        print "infinite loop!\n";
    }
?> 

Gerardcole: <?php
$cond = 1;
/*Sets a variable that will aid in looping.*/

$even = 2; //Even no's are divisible by 2 without remainder.

$number = 0; //First number

while($cond == 1)
/*Since is already 1, this condition will never end*/
{
if(($number % $even == 0) AND ($number != 0))
/* Since it will return same for 0 but we don't want 0 */
{
echo $number.', ';
}
$number++;
}
?>

if(($number % $even == 0) AND ($number != 0) && ($number <= 200)

*omni:
@ActiveMan
Please let's not get into the DB aspect now. I still think we just keep playing around with strings and integers. I wonder how many of them are even taking note. No questions yet. I guess we should allow for like up to 5 answers if possible to be sure that people are following up before we declare answers then put up a new puzzle. Some might just come along, see and copy solutions without even knowing how they were solved.

<?php
for($a = 1; $a <= 500;$a++){
if($a % 2 == 0) echo $a,',';
}
?>

<?php
$cond = 1;
/*Sets a variable that will aid in looping.*/

$even = 2; //Even no's are divisible by 2 without remainder.

$number = 0; //First number

while($cond == 1)
/*Since is already 1, this condition will never end*/
{
if(($number % $even == 0) AND ($number != 0) AND ($number <= 500))
/* Since it will return same for 0 but we don't want 0 */
{
echo $number.', ';
}
$number++;
}
?>

Web Contractor: NEW PUZZLE

Create an infinite loop of all even numbers.



You may post more than one answer.
N.B.I will not be responsible for any system malfunction during testing!

Gerardcole: <?php
/*
/*My eyes are already closing Henri saw this so less comments
/*Its same for loop you used above that would be applied with modulus.
*/
for($a = 1; $a >= 1000; $a++)
{
if($a % 7 == 0) echo $a.'<br>';
}
?>

/*Not Tested*/

*omni:
@Gerardcole, @Judinho59 Please ooooo... You should stop answering so the beginners will at least try out their hands on the questions before they are corrected with some methods of solving the puzzles. Let's give them a chance to try their hands on the puzzles

*omni:
I think we might continue with this to see how many people will along and play with codes but basically beginners except if the question level specifies otherwise.

Gerardcole: Can explain in words:

$a == $b; //$a and $b are equal. True.

$a !=== $b; //$a and $b are not identical. True

E.g:

<?php
$a = 0;
$b = 000;
if($a == $b)
{
echo '$a and $b are equal';
} else {
echo '$a and $b are not equal';
}
echo '<br>';
if($a === $b)
{
echo '$a and $b are identical';
} else {
echo '$a and $b are not identical';
}
?>

The code above will output:

$a and $b are equal
$a and $b are not identical