<?php
$string = "15,000";
$int = 15000;

echo $string *2; /// 30
echo "<br />";
echo $int *2; /// 30000
?>

ActiveMan:

<?php
$string = "15,000";
$int = 15000;

echo $string *2; /// 30
echo "<br />";
echo $int *2; /// 30000
?>

no

ogzille: Bros, I can answer shebi?

ediko5: Please How can i get information posted by my site users on my site(for instance the contact form) either through email or any any other available method.

ActiveMan:

<?php
$string = "15,000";
$int = 15000;

echo $string *2; /// 30
echo "<br />";
echo $int *2; /// 30000
?>

no

echo (15000 > '15,000') ? true : false;

babihouse: NO
<?php
$v = 15,000;
$p = 15000;

echo $v; $p;
?>
output
15,000 ; 1500

i am a learner, i just felt like trying

*omni:

This is off topic please. Create a new thread for it please.


Instead of multiplying, you can simple just compare the two variables. You already understood the difference that 15000 is an INTEGER while 15,000 is a mixture of NUMBERS & a CHARACTER. A simple code could be

echo (15000 > '15,000') ? true : false;

If the output is 1 then it's true while if 0 it's false.

You can play around with this to see more examples.

$a = "15,000";
$b = "1,500,000";


Nice try. Keep attempting and you'll get used to it along the line.

echo (15000 > '15,000') ? true : false;

*omni:
@ActiveMan

echo (15000 > '15,000') ? true : false;

^^^ Is an IF/ELSE statement. Just call it Tenary operator.

http://php.net/manual/en/language.operators.comparison.php

<?php
$a = 15000;
$b = "15,000";
//calling the function variable dump
var_dump($a);
var_dump($b);
?>

$a = 1;
$b = "1";

$a == $b;
$a !=== $b;

Web Contractor: Geraldcole.perfect solution.use comments so beginner can follow.

I have received many requests from people who want to learn PHP Programming.

This is a good avenue to learn.So lets keep this thread alive.Ask any questions if you re confused at any point.will be posting more puzzles.Cheers.

*omni:

Thanks so much for loving to help the beginners. Let's write more codes for them so they can learn from. Issue is many are scared of writing the wrong codes and getting corrected but the truth is, when you write them poorly or wrongly, others put you in the right direction. Your coding structure and actual codes improve. Let's keep it alive here.

More confusions, puzzles or questions coming. I'll post mine here as well for help.

Cheers!

Snippets: @ WebContractor - Can U Please gimme links as to where I can get php based puzzles that I can solve and improve my coding experience.
Thanks

Gerardcole:

2. Outputting variables directly.
<?php

echo 'Example 2';

$ev = array('2', '4', '6', '8', '10', '12');

/* Its still the same foreach() function */

foreach($ev as $a)
{
echo $a . '<br>';
}
?>

<?php
foreach($array as $value){
statement;
}
?>

<?php
$out = '12';
$even_numbers = array('2','4','6','8','10','12'); 

   foreach($even_numbers as $number) {
    if($number !== $out) { 
   echo $num.","; } }
?>

Gerardcole:
I would love a puzzle on removing the last comma after 10 as it is not prof. to leave it there.

Judinho59:

<?php
$out = '12';
$even_numbers = array('2','4','6','8','10','12'); 

   foreach($even_numbers as $number) {
    if($number !== $out) { 
   echo $num.","; } }
?>

Web Contractor:

Good Job.But Please remove the last comma.Also from the array,you are to return 2,4,8,10 only.So Take away 6 from your result

<?php
$out = array('6','12');
$even_numbers = array(2,4,6,8,10,12); 
$result = '';

   foreach($even_numbers as $number) {

    if(!in_array($number, $out)) { 
  $result .= $num.',';
 } 
}
    echo rtrim($result, ',');

Gerardcole: Okay. Since according to our puzzle provider, Judinho59 didn't get the required output, I ll provide my own solution. The puzzle is kinda tricky.

Given array('2', '4', '6', '8', '10', '12')
To return 2,4,8,10 (Removing 6 and 12 and the last comma that's supposed to appear after 10)

I'm also gonna attack in two methods.

1. Using PHP in_array()

<php
/* First we set the values we do not want in an array */
$unwanted = array('6', '12');

/*Then we set a variable which will help in placing comma's */

$counter = 0;

/*Then to the code */
$ev = array('2', '4', '6', '8', '10', '12');

foreach($ev as $a)
{
if(!in_array($unwanted, $a)
/*Checks if $a is not in our unwanted list before proceeding*/
{
if($counter > 0)
/* Since we don't want it after our last value but after every other, we run this before the value. > 0 here explains that we don't want it before the first as our counter is still 0 before this line */
{
echo ', ';
}
echo $a;
$counter++;
/*In PHP ++ is same as +1 so whenever it gets to the line above, the counter is increased buly 1*/
}

}
?>

2. Using the modulus operator '%'

The modulus %, in PHP returns the remainder in a division operation. E.g 7 % 5 returns 2 (i.e 1 remaining 2), 10 % 5 returns 0 (i.e 2 remaining 0).

I wouldn't be explaining the lines I already explained in example 1 above.

<php
$div = 6;
/* Since all the unwanted numbers are divisible by 6. */

$counter = 0; //As explained in e.g 1 above

$ev = array('2', '4', '6', '8', '10', '12');

foreach($ev as $a)
{
if($a % $div != 0)
/*Since it will return 0 for our unwanted 6 and 12*/
{
if($counter > 0)
{
echo ', '; //As explained in e.g 1 above
}
echo $a
$counter++; //As explained in e.g 1 above.
}
}
?>


The above returns:
/*From E.g 1 */

2, 4, 8, 10

/*From e.g 2 */

2, 4, 6, 10

Judinho59:

Thanks. I didnt see 6 missing out.

@Gerardcole: Nice Explanation there..

<?php
$out = array('6','12');
$even_numbers = array(2,4,6,8,10,12); 
$result = '';

   foreach($even_numbers as $number) {

    if(!in_array($number, $out)) { 
  $result .= $num.',';
 } 
}
    echo rtrim($result, ',');