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Billionaire Offers $1million To Solve This Maths Problem by Nobody: 7:12pm On Jun 06, 2013 |
[b] He dropped out of Baylor University , but Texas billionaire D. Andrew Beal has always been fascinated by numbers and the theories behind them. Now Beal, who, with a net worth of $8 billion ranks 43 rd on the Forbes list of U.S. billionaires, is offering a $1 million reward to anyone who can solve a math problem - now dubbed the Beal Conjecture - that Beal has been trying to solve since 1993. The long-running reward started at $5,000 in 1997, and bumped up to $100,000 in 2000, where it remained for 13 years. Now the money has hit nine figures. It all started with Beal's determination to solve the 350-year-old mystery of Fermat's Last Theorem - the idea that Ax + By = Cz. Beal realized that there could only be solutions to the equation when A, B, and C have a common numerical factor. "Others have looked at other closely related problems, but I believe Beal was the first to express it in that way," Don McClure, the executive director of the American Mathematical Society , which announced the $1 million prize, told ABC News Beal took his Fermat's Last Theorem findings to R. Daniel Mauldin , then a mathematics professor at the University of North Texas, who came up with the idea to offer a prize to anyone who could prove the theory. Jordan Ellenberg, a mathematician at the University of Wisconsin, said confirming the theory could revolutionize the field. "Any solution to this problem would signal a real new idea and not minor progress," he said. Mauldin, who was part of a committee that has reviewed hundreds of proposed solutions over the years, said none ever worked. [/b] Continue reading here: www.gma.yahoo.com/blogs/abc-blogs/billionaire-offers-1-million-solve-math-problem-153508422.html |
Re: Billionaire Offers $1million To Solve This Maths Problem by ATMC(f): 7:28pm On Jun 06, 2013 |
I think this is a 3-dimensional problem. It can only be solved using matrixes for one linear equation with 3 variables cannot be solved alone therefore 2 more linear equations are needed. 1 Like |
Re: Billionaire Offers $1million To Solve This Maths Problem by kponkedenge(m): 7:36pm On Jun 06, 2013 |
ATMC: I think this is a 3-dimensional problem. It can only be solved using matrixes for one linear equation with 3 variables cannot be solved alone therefore 2 more linear equations are needed.Stop ur rambling n solve it so we can share d money 2geda. I nor go skol if not I for don solve am tay tay collect d moni. |
Re: Billionaire Offers $1million To Solve This Maths Problem by ATMC(f): 7:39pm On Jun 06, 2013 |
kponke denge:are you sick? |
Re: Billionaire Offers $1million To Solve This Maths Problem by ATMC(f): 7:41pm On Jun 06, 2013 |
...a constant would have made this a bit easier *thinking* 1 Like |
Re: Billionaire Offers $1million To Solve This Maths Problem by Nobody: 9:20pm On Jun 06, 2013 |
ATMC: ...a constant would have made this a bit easier *thinking*Please remember I gave you the info when you solve it ooo, so 10% is mine. 1 Like |
Re: Billionaire Offers $1million To Solve This Maths Problem by ATMC(f): 9:30pm On Jun 06, 2013 |
Try too...you don't have straws up there |
Re: Billionaire Offers $1million To Solve This Maths Problem by Nobody: 9:49pm On Jun 06, 2013 |
. |
Re: Billionaire Offers $1million To Solve This Maths Problem by Nobody: 3:47pm On Jun 08, 2013 |
The offer still stands...this is a cool $1 million dollars begging to be earned. Where are our maths professors and straight A students? |
Re: Billionaire Offers $1million To Solve This Maths Problem by panafrican(m): 6:46pm On Jun 08, 2013 |
Pipsland78: The offer still stands...this is a cool $1 million dollars begging to be earned. Where are our maths professors and straight A students?It took more than 350 years to prove Fermat's conjecture, so chill. |
Re: Billionaire Offers $1million To Solve This Maths Problem by Nobody: 8:48am On Jun 11, 2013 |
Easy problem.. Cnt blv no1 has crackd it yet.. Smh |
Re: Billionaire Offers $1million To Solve This Maths Problem by Nobody: 9:37am On Jun 11, 2013 |
^^^ At last we have someone smart enough to crack the case and solve the problem. But remember 20% is mine. |
Re: Billionaire Offers $1million To Solve This Maths Problem by Nobody: 9:42am On Jun 11, 2013 |
Pipsland78: ^^^ At last we have someone smart enough to crack the case and solve the problem. But remember 2% is mine.2% cheiii that's nothing I'll even make it 3 1 Like |
Re: Billionaire Offers $1million To Solve This Maths Problem by Inik(m): 3:19pm On Jun 11, 2013 |
I wish i was a maths guru 1 Like |
Re: Billionaire Offers $1million To Solve This Maths Problem by digitite: 11:59am On Jun 13, 2013 |
I can try. Let me see what I can come up with. |
Re: Billionaire Offers $1million To Solve This Maths Problem by digitite: 4:29pm On Jun 13, 2013 |
I came up with this... A x + By = Cz If A = 1, B= 2, C = 7 then x = 3, y = 5, z = 6 therefore; Ax + By = Cz 13+ 25= 76 That's my 10cent. 1 Like |
Re: Billionaire Offers $1million To Solve This Maths Problem by digitite: 4:46pm On Jun 13, 2013 |
Pipsland78: When we win the prize, I will give you 10%. Make sure it gets to the right source and follow up the news. Keep me posted on any new development. One Love . 1 Like 1 Share |
Re: Billionaire Offers $1million To Solve This Maths Problem by Nobody: 5:13pm On Jun 13, 2013 |
digitite:I sure will follow it up...let me forward it to the right source. 1 Like |
Re: Billionaire Offers $1million To Solve This Maths Problem by Amujale(m): 10:30pm On May 22, 2019 |
Awesome thread. Well in Op |
Re: Billionaire Offers $1million To Solve This Maths Problem by Amujale(m): 10:42pm On May 22, 2019 |
digitite: On my mind you get 10 x 10 per-cent for your effort. I don’t know for certain if your answer is what the moguls are seeking however , for me, your mathematics is gorgeous and transparent. |
Re: Billionaire Offers $1million To Solve This Maths Problem by pacino26(m): 11:06pm On May 26, 2019 |
digitite: Review your laws of indices and revisit this your 10cent |
Re: Billionaire Offers $1million To Solve This Maths Problem by panafrican(m): 4:44am On May 27, 2019 |
digitite: I will make less effort than you and get more money Here is how : Let's set A=B=C = 0 and suppose x, y, z are exponents. then any (x, y, z) is a solution provided none of x, y, z is less than or equal to zero. 2 Likes 2 Shares |
Re: Billionaire Offers $1million To Solve This Maths Problem by TAO11(f): 8:09pm On May 28, 2019 |
panafrican: Hahaha ... Baba, No serious mathematician will take you seriously for coming up with that --- Not even an amateur mathematician. That's known technically as a "trivial solution." If that was allowed I would have long claimed to have PROVEN at least one case of Fermat's Last Theorem, lol! Las las na one case a whole Euler Leonhard prove! I would simply have said I have proven true the non-equality: an + bn ≠ cn at n= 0. Shebi 1+1 ≠ 1 But sadly "trivial solutions" doesn't count. These guys should "dash" money if they really want to. Must they drive people mad first? 1 Like 2 Shares |
Re: Billionaire Offers $1million To Solve This Maths Problem by panafrican(m): 3:11am On May 29, 2019 |
Trivial solutions are like the devil in the details in mathematics , one reason why there is a need to well define the restrictions within which a theorem or a postulate is stated, otherwise things can collapse easily like a castle built on the sand For instance had Fermat not stated that n be greater than or equal to 3, his last theorem would have been easily defeated by a simple addition 1^1 + 1^1 = 2^1 Or by any Pythagorean triple, for instance (3, 4, 5 ) because 3^2 + 4^2= 5^2 ; ( 5, 12, 13) because 5^2 + 12^ 2 = 13^2 etc. 1 Like 1 Share |
Re: Billionaire Offers $1million To Solve This Maths Problem by digitite: 12:18pm On Jun 11, 2019 |
Amujale: Thank you Sir. In fact, if you have any mathematical problem, table it. 1 Like |
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