₦airaland Forum

Please I need a C or preferably, Java code that could scan through a text file (a file contaning string of numbers stored in a notepad. The file contains something like 534135635652652663346.....). The code will store two numbers at a time in an integer variable, the code will then find the average of the cumulative number.
Thanks in anticipation of your help.

/*
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* and open the template in the editor.
*/
package pdf;

import java.io.File;
import java.io.FileNotFoundException;
import java.util.Iterator;
import java.util.LinkedList;
import java.util.Scanner;

/**
*
* @author naija_swag
*/
public class NumberScanner {

public static void main(String[] args) throws FileNotFoundException {
//use the attached picture to see the location of file for the file string
File file = new File(System.getProperty("user.dir"
+ "/src/pdf/input.in";

//read in your file
Scanner s = new Scanner(file);

String str = null;

//if it is only the average that is needed
double average = 0;
int count = 0;

//if you need to print the numbers, we keep them here
LinkedList<Integer> listNum = new LinkedList<Integer>();
Integer num = null;

//loop through the file reading one line at a time
while (s.hasNext()) {

str = s.nextLine();

//split the string read so we can loop thru and pair numbers
String[] arr = str.trim().split("";

String sss = "";
//loop through array of strings
for (int i = 1; i < arr.length; i++) {
sss += arr[i];

//does the magic of making sure we pick out two consecutive numbers
//uses modulus for that purpose
if (i % 2 == 0) {
num = Integer.parseInt(sss);

average += num;
count++;

listNum.add(num);
sss = "";

} else if (i % 2 != 0 && i == arr.length - 1) {
num = Integer.parseInt(sss);
listNum.add(num);
count++;
}





}
}


Iterator itil = listNum.iterator();

double num2 = 0;
while (itil.hasNext()) {
num2 += (Integer) itil.next();
}


System.out.printf("Our Average is %.3f %n", num2 / listNum.size());

System.out.printf("Our Average is %.3f", average / count);

}
}

Thanks Bros, I will try it and report back.