Kennybix: @ade, can you handle structures? You can use it to 'hold' fractions, and pass it as an argument to functions. It can even be used as a return type!

struct fraction {
int numerator;
int denominator;
};

fraction add(fraction a, fraction b)
{
fraction result;
result.denominator = a.denominator * b.denominator;

result.numerator= (a.numerator * b.denominator) + (b.numerator *a.denominator) ;
return result
}

quadrangle: here is my code.
//Program: checkbook.cpp
//This program updates a checkbook
#include <iostream>
#include <iomanip>

using namespace std;

int main ()
{
char trans_type;
double start_bal, trans_amt, end_bal;
//Module for getting data
cout << "Enter your starting balance and press <Enter>" <<endl;
cin >> start_bal;
cout << "Enter your starting balance and press <Enter>" <<endl;
cin >> trans_amt;
cout << "Enter your trans_type 'W' (withdrawal) or 'D' (Deposit) and press <Enter>" <<endl;
cin >> trans_type;

// Perform computation
if(start_bal == 'w')
{
end_bal = start_bal - trans_amt;
}
else
{
end_bal = start_bal + trans_amt;
}
//Print result
cout << "Starting balance is " << start_bal << endl;
cout << "Transaction amount is " << trans_amt << setw(2) << trans_type << endl;
cout << "Ending balance is " << end_bal << endl;
}

techwizard: #include <iostream>
#include <windows.h>
using namespace std;
int main(void){
start:
cout << "Welcome to coded admin login\n" << endl;
cout << "Login using your administrator password:" << endl;
string login;
getline (cin, login);
if (login == "yourPassword"{
ShellExecute(NULL, "open", "http://www.highlycoded.com",
NULL, NULL, SW_SHOWNORMAL);
return 0;
}
else
{
cout << "Login failed" << endl;
goto start;
}

cin.get();
return 0;
}

adelolaa: screenshots

raynold: I kinda(not like a pro) knw c, c++ and java
I dislike arrays and pointers

Olyboy16:
just like saying u ar a footballer but you dont like scoring!

iamDemigod: #include <iostream>
#include <cstdlib>
#include <string>
#include <ctime>
using namespace std;
int usernum, compnum, playagain;
void gamestart(){
int quit, level;
cout << endl;
cout << " GUESSING GAME!!! " << endl<<endl;
cout << " to continue press 1 " << endl;
cout << " to end the game press 2 " << endl;
cin >> quit ;
if (quit == 2){
cout << " gooood byee " ;
}

if (quit == 1){
cout << endl;
cout << " enter any difficulty level btw 1 and 1000" << endl;
cin >> level;
cout << endl;
cout << " hmmm... level " << level << " selected , let the game begin!! " <<endl<<endl;
cout << " computer is thinking of a number btw 1 and " << level << endl;
cout <<" try and guess what number it is " << endl;
cin >> usernum;
compnum = rand()% level;
}

}
void game (int usernum, int compnum){
while (usernum!=compnum){
if (usernum < compnum ){
cout << " your guess is to low , please try again " << endl<< endl;
cout << ">> ";
cin >> usernum;
}
if ( usernum > compnum ) {
cout << " your guess is to high , try again " << endl<< endl;
cout << ">> ";
cin >> usernum;
}
}
if (usernum == compnum){
cout << " congrats , you win!!! " << endl;
cout << " press 1 to play again " << endl;
cout << " press 2 to quit " << endl;
cin >> playagain ;
}
if(playagain == 1){
gamestart();
game (usernum, compnum);
} else { cout << " gooood byee " ;
}

}
int main (){
srand(time(NULL));
gamestart();
game (usernum, compnum);
}

Artorius: Hello guys, well the thread is in hibernation; sorry to disturb I'm learning c++, and I'm wondering how I can execute c++ codes on my android device. Yea I saw one or two posts on the thread about using c4droid, after installing I was directed to also install gcc and sdl which I also did. But it's as if the gcc app isn't integrated into the c++ or something like that. Even when I try to fix that in the c4droid preferences, I'm still directed to install the gcc plugin which I have already! Can somebody please give me tips on how to fix this? I'll be most grateful, and I'll sure be coming back to ask more questions, thanks.

raynold: download the c4droid from the playstore(payed tho)..

adelolaa: /********************************

Assignments: (if, else if and else statement)

HOD: ALEX ALLAIN

STUDENT: XARMZON

COURSE: JUMPING INTO C++

Q1: Ask the user for two user's ages, and indicate who is older, behave differently if both are over 100.

Q2: Implement a simple "password" system that takes a password in the form of a number. Make it so that either of the two numbers are valid, but use only one if statement to do the check.

Q3: Write a small calculator that takes as input one of the four arithmetic operations, the two argument to those operation, and then print out the result.

Q4: Expand the password checking program from earlier in this chapter and make it multiple usernames. Each with their own password and provide the ability to prompt user's again if the first attempt failed. Think about how easy(or hard) it is to do this for a lot of usernames and password.


SOLUTION TO Q1:

********************************/

#include <iostream>

#include <string>

using namespace std;


int main()
{
int firstAge;
int secondAge;

cout << "Enter the first and second person age " << endl;
cin >> firstAge >> secondAge;

if (((firstAge && secondAge) < 100) && ((firstAge && secondAge) >= 1))

{

if (firstAge > secondAge)
{
cout << " First person is older than second person" << endl;
}
if (firstAge < secondAge)
{
cout << "Second Person is older than first person" << endl;
}

}

if (firstAge && secondAge >= 100)
{
cout << "Both ages is 100 or greater than 100" << endl;
}
else
{
cout << "Invalid Ages" << endl;
}



}

wisemania:

http://mirror7.meh.or.id/Magazines/hakin9/Packtpub.Metasploit.Penetration.Testing.Cookbook.Jun.2012.pdf

http://adrem.ua.ac.be/sites/adrem.ua.ac.be/files/sqlinjbook.pdf

http://library.back2hack.cc/books/Hacking/Syngress_-_XSS_Attacks_[]_(2007)_en.pdf

http://mirror7.meh.or.id/ebooks/11_TheWeb%20Application%20Hackers%20Handbook.pdf

dizzzz books r basically about web hacks and security.....i hope it wont prevent u 4rm fulfillin ur Android/iOS dev ..... Stil av mor...bt download dizzzz first....i av on objective-c aswell.....objective-c codes r lovely and lighter dan java u kw....