pls if there are any physics guru in the house please help me with this physics thanks
an object is rejected from a horizontal surface with a velocity of 100mper sec at an angle to the horiyontal if the total time of flight is 10sec
A. calculate the angle of projection
B. range of motion take g to b 10 m per sec
thanks pls i will really appreciate it here is my number just in case 07030594719

from, T=2usinP/g. where u is velocity, P is angle to the horizontal, g is 10m/s2. if we make P subject of formula, we get, P=arcsin(Tg/2u). so let us substitute the values of T, g, and U into the equation. this gives P=arcsin(10*10/2*100). this gives P=arcsin(100/200). P=arcsin(0.5). P=30 degrees.that gives the answer to A. then lets move to B.Range=U²sin2P/g. when we substitute, we get Range=100*100sin2(30)/10. Range=10000sin60/10. Range=1000sin60. Range=1000*0.8660=866metres. I hope u get it.

you are correct. physics student also.

@ poster am coming with my solution
just that my scanner is bad
so i wil go to a cafe to post the solution

@poster
Here is my own answer

I called u but ur no was'nt available