McWhillion Transports has acquired two trucks to carry different types of cargo. One costs #3,500,000; the other costs $5,200,000. The company expects that the first will last 400,050 km, after which it can be sold for salvage for about #1,000,000. The other will fetch the same salvage price, but will last 544,000 km. The two trucks convoy together, so they always show the same mileage readings.
If the value of each truck declines at different constant rates for every mile driven,
Calculate the rate of depreciation of each vehicle.
At what mileage reading will the residual values of the two trucks be equal?
At what mileage readings will both vehicles cost #500,000 each?

meryl4merit, UchihaMadara,
Obinoscopy, CarlOzeki, Snowland,
Tinkybabe, hopelink1 ,, vengeance, kobonaire,
Your attentions are needed.

Hmm....Na only 2 X 2 = 4 I know ooo

I=PRT/100

Linda puts money in two investments A and B which paid simple interest. If annual rate of investment of B is 1.5 times of A, what amount did Linda put into A?
a. Interest for 1yr is $50 for A and $150 for B.
b. Linda put twice the amount of A into B.


I'M KINDA CONFUSED, HELP!

DermalCarotene
CarlOzeki
McWhillion
kobonaire
Tinkybabe
Paranorman

Hmmmn

McWhillion: Linda puts money in two investments A and B which paid simple interest. If annual rate of investment of B is 1.5 times of A, what amount did Linda put into A?
a. Interest for 1yr is $50 for A and $150 for B.
b. Linda put twice the amount of A into B.


I'M KINDA CONFUSED, HELP!

DermalCarotene
CarlOzeki
McWhillion
kobonaire
Tinkybabe
Paranorman

this is simple now.. Just lookin at it, i think 'twill give you a simultaneous equation or so.. Though i am not sure and dont wanna jump into conclusion..

I'l answer ur questions when i get the time jare..

Kinda simple...but no PEN

McWhillion: Linda puts money in two investments A and B which paid simple interest. If annual rate of investment of B is 1.5 times of A, what amount did Linda put into A?
a. Interest for 1yr is $50 for A and $150 for B.
b. Linda put twice the amount of A into B.

This question may appear deceptively simple but is far from it from in my opinion. If A investment rate was X and investment amount Y it means for A : X*Y=50 and B: 1.5X*2Y=150 . We do not have enough information to solve for X, Y

kobonaire: This question may appear deceptively simple but is far from it from in my opinion. If A investment rate was X and investment amount Y it means for A : X*Y=50 and B: 1.5X*2Y=150 . We do not have enough information to solve for X, Y

Bro, that is what I thought and that is why I brought it here for you guys. I thought something was missing and you confirmed it.

@McWhillion I think I solved the 1st problem, but NairaLand Antispam bot did not like my use of the Naira symbol and so my account got temporarily suspended
See attached solution .....

TemporaryAcount: @McWhillion I think I solved the 1st problem, but NairaLand Antispam bot did not like my use of the Naira symbol and so my account got temporarily suspended
See attached solution .....

dat foolish anti spam sha
I cant see the solution clearly

McWhillion: dat foolish anti spam sha ..I cant see the solution clearly

Truck 1: N3500000, sells for N1000000 at 400050 km mileage
Truck 2: N5200000, sells for N1000000 at 544000 km mileage
Calculate the rate of depreciation of each vehicle:
Truck 1 => (3.5M -1M)/400050 = 6.249 N/km (approx)
Truck 1 => (5.2M -1M)/544000 = 7.721 N/km (approx)

At what mileage reading will the residual values of the two trucks be equal?
This is given in the question already .. 400050 and 544000 km??

At what mileage readings will both vehicles cost N500,000 each?
Truck 1: let that mileage be X => 3.5M - 6.249X = 0.5, solving for X=480,076 km
Truck 2: let that mileage be Y => 5.2M - 7.721X = 0.5, solving for Y=608,729 km

TemporaryAcount:
Truck 1: N3500000, sells for N1000000 at 400050 km mileage
Truck 2: N5200000, sells for N1000000 at 544000 km mileage
Calculate the rate of depreciation of each vehicle:
Truck 1 => (3.5M -1M)/400050 = 6.249 N/km (approx)
Truck 1 => (5.2M -1M)/544000 = 7.721 N/km (approx)

At what mileage reading will the residual values of the two trucks be equal?
This is given in the question already .. 400050 and 544000 km??

At what mileage readings will both vehicles cost N500,000 each?
Truck 1: let that mileage be X => 3.5M - 6.249X = 0.5, solving for X=480,076 km
Truck 2: let that mileage be Y => 5.2M - 7.721X = 0.5, solving for Y=608,729 km

Bro, this is quite trickish i tell u. It confused me too.
The 2nd question is talking about a unified reading ( don't forget they always show the same reading since they convoy together).
If there residual values are equal at the same reading, that value can't be #1m.
Think about it
(The other answers are right)

McWhillion: McWhillion Transports has acquired two trucks to carry different types of cargo. One costs #3,500,000; the other costs $5,200,000. The company expects that the first will last 400,050 km, after which it can be sold for salvage for about #1,000,000. The other will fetch the same salvage price, but will last 544,000 km. The two trucks convoy together, so they always show the same mileage readings.
If the value of each truck declines at different constant rates for every mile driven,
Calculate the rate of depreciation of each vehicle.
At what mileage reading will the residual values of the two trucks be equal?
At what mileage readings will both vehicles cost #500,000 each?

solved it here already, i shouldnt post it since some1 has already privided the solution.. The second question, i cant inteprete it. Since they have different depreciation rate and they convoy together, i dont think they will be a km/mileage when they will have the same residuals simulteneously...

McWhillion: Linda puts money in two investments A and B which paid simple interest. If annual rate of investment of B is 1.5 times of A, what amount did Linda put into A?
a. Interest for 1yr is $50 for A and $150 for B.
b. Linda put twice the amount of A into B.


I'M KINDA CONFUSED, HELP!

insuffient data o..

paranorman:

solved it here already, i shouldnt post it since some1 has already privided the solution.. The second question, i cant inteprete it. Since they have different depreciation rate and they convoy together, i dont think they will be a km/mileage when they will have the same residuals simulteneously...

Dont forget that they don't have the same rate of depreciation.
Truck A will be sold off first before B.
Since they have same meter reading, at 400,050km, Truck A will be worth #1m while truck B should cost more but there would be a time the two will cost the same at the same mileage reading.

McWhillion:
Dont forget that they don't have the same rate of depreciation.
Truck A will be sold off first before B.
Since they have same meter reading, at 400,050km, Truck A will be worth #1m while truck B should cost more but there would be a time the two will cost the same at the same mileage reading.

i get ur point.. Lemme see if i can manipulate my way through..

McWhillion:
Dont forget that they don't have the same rate of depreciation.
Truck A will be sold off first before B.
Since they have same meter reading, at 400,050km, Truck A will be worth #1m while truck B should cost more but there would be a time the two will cost the same at the same mileage reading.

bros, i still do not think so o. I may b wrong though. They move together, they read same on mileage independtly. Second truck cost more than first.. We lookin for a mileage when they cost the same price..

For truck A,
3.5-6.25X=Y

for truck B,
5.4-7.72k=Y

where Y is the residual, and x and k are the respective distance each truck would have travalled so as to hav the same residuals.. Just thinkin out here.. Think it too bro.

@paranorman and kobonaire

Let’s look at it this way, the two trucks run simultaneously, also there odometers read the same figures at the same time but there rate of depreciation is different.
Let’s assume the following represents our rate of depreciation,
(V1-V2)/M
Where, V1 = first value of the truck, V2 = final value of the truck and M = mileage.
We’ve already determined the rate of depreciation for the two trucks as #6.249/km(R1) and #7.721/km(R2) respectively.
The question wants us to calculate for a period where the two trucks will read the same mileage and be worth the same value (i.e M and V2 are the same for both trucks)
If this is true, our equation becomes,
For truck 1---- (#3,500,000-V2)/m = 6.249
For truck 2---- (#5,200,000-V2)/m = 7.721
The above becomes,
3,500,000-V2=6.249M…(eq.1)
5,200,000-V2=7.721M…(eq.2)
Solving for both unknowns we get V2=
(-)#3,716,916,
and M= 1,154,891km
Although that answer is hypothetically impossible but mathematically right. If I had adjusted the values we would have gotten a positive answer.
The two equations can be likened on to two unparallel lines which must surely meet. The cordinates of that point where they meet is what we just calculated for

McWhillion:

Let’s look at it this way, the two trucks run simultaneously, also there odometers read the same figures at the same time but there rate of depreciation is different.
Let’s assume the following represents our rate of depreciation,
(V1-V2)/M
Where, V1 = first value of the truck, V2 = final value of the truck and M = mileage.
We’ve already determined the rate of depreciation for the two trucks as #6.249/km(R1) and #7.721/km(R2) respectively.
The question wants us to calculate for a period where the two trucks will read the same mileage and be worth the same value (i.e M and V2 are the same for both trucks)
If this is true, our equation becomes,
For truck 1---- (#3,500,000-V2)/m = 6.249
For truck 2---- (#5,200,000-V2)/m = 7.721
The above becomes,
3,500,000-V2=6.249M…(eq.1)
5,200,000-V2=7.721M…(eq.2)
Solving for both unknowns we get V2=
(-)#3,716,916,
and M= 1,154,891km
Although that answer is hypothetically impossible but mathematically right. If I had adjusted the values we would have gotten a positive answer.
The two equations can be likened on to two unparallel lines which must surely meet. The cordinates of that point where they meet is what we just calculated for

this is what i call 'manipulation' bro.. Good work bro. Two parralel line doesnt meet, do they?! Hehehe..

But come to think of it, we can always find the different mileage for the two trucks at the same residuals as long as they maintain their respective decay rate. Example of this is the last question. Accordint to ur solution(and you already affirm this), ur answer is logical but not realistic. So i dont think their will be ever be a M for which V2s are equal. I stand to be corrected though.

paranorman:
this is what i call 'manipulation' bro.. Good work bro. Two parralel line doesnt meet, do they?! Hehehe..

But come to think of it, we can always find the different mileage for the two trucks at the same residuals as long as they maintain their respective decay rate. Example of this is the last question. Accordint to ur solution(and you already affirm this), ur answer is logical but not realistic. So i dont think their will be ever be a M for which V2s are equal. I stand to be corrected though.

Of course I can formulate figures that can meet such a condition. The problem with the question I brought here is that I didn't solve it before pasting in here.

It is like forming a question like
A boy buys a pen and a book for #20, the book costs #25. How much costs the pen?
The kind of mistake you noticed above is the kind I committed when forming the values for the question.

Cool. Okay, i guess we both need to improve on our 'question-formin skills' ..
I is a statistician.. Who art thou?

paranorman: Cool. Okay, i guess we both need to improve on our 'question-formin skills' ..
I is a statistician.. Who art thou?

A petrochemist yet to define his career path.

McWhillion:
A petrochemist yet to define his career path.

you wan chop oyel money too abi? Hehehe. Time for work. Hv a nice day bro.

paranorman:
you wan chop oyel money too abi? Hehehe. Time for work. Hv a nice day bro.

Y not bro ,enjoy ur work.

@McWhillion @paranorman you guys have solid math/logic knowledge .... keep up the good work, I'm learning a few things.

busy now. later