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Nairaland Forum / Nairaland / General / Education / Nairaland Jamb Tutorial Centre {mathematics Thread} (19646 Views)
2016 NAIRALAND JAMB TUTORIAL {the Physics Thread } / Nairaland 2016 Jamb Tutorial Classroon [mathematics Thread] / Nairaland Jamb Tutorial Centre. {NJTC} (2) (3) (4)
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Re: Nairaland Jamb Tutorial Centre {mathematics Thread} by factorial1(m): 10:42am On Dec 10, 2014 |
Oops... didn't went through the 1st page, there are tutors for this... hope I won't be banned for this? I'm really sorry generals. cc Dejt4u raayah logoDwhiz goofyone. |
Re: Nairaland Jamb Tutorial Centre {mathematics Thread} by LogoDWhiz(m): 12:04pm On Dec 10, 2014 |
factorial1: you're highly welcome here please. Feel free. |
Re: Nairaland Jamb Tutorial Centre {mathematics Thread} by VEVEDIHNO: 12:24pm On Dec 10, 2014 |
factorial1: U Guyz Ar So Good...Fankz Bro |
Re: Nairaland Jamb Tutorial Centre {mathematics Thread} by factorial1(m): 2:21pm On Dec 10, 2014 |
Re: Nairaland Jamb Tutorial Centre {mathematics Thread} by sammyomotola: 2:42pm On Dec 10, 2014 |
We need more question |
Re: Nairaland Jamb Tutorial Centre {mathematics Thread} by Adiwana: 12:05am On Dec 11, 2014 |
Profit[b][/b] And[b][/b] Loss[b][/b] profit&loss is all about finding the gain or loss made from selling a particular product/products..as we know it is SALES PRICE-BOUGHT PRICE determines whether profit or loss.so without wasting much time,all questions relating the topic should be posted&i will take care of it&anybody with different&faster solutions are also free to post thier solutions Am going to give a quick solution based on discount,, Discount is all about special money taken off a product bought..this is done usally in festive periods like Ramadan,Christmas,etc..we all know this,so without wasting any time,am going to give a quick soln concerning Discount 1)When you are asked to find the percentage paid on discount,this particular question takes a lot of time&requires you to find a lot before finding it but i will show you how to find it in less than 15secs.you can apply this in waec,neco and other exams that requires you to find such.infact it was in this years waec..Waec students can apply this formular in their rough work in theory as it makes the student to know the final ans before detailed solution Example[b][/b] 1). A shop-keeper marks his television set for sale at #36000 so as to make a profit of 20% on the cost price.When he sells it,he allows a discount of 5% off the marked price.Calculate percentage profit? to ans the above questions you are required to find a lot especially profit but using my MAGIC formular,you can know the percentage easily.so i)ratio of marked price to cost price=(100+20):100 ii)ratio of Cash price to Marked price=(100-5):100[cos is a discount of 5%,the consumer will pay 95%] Cash price=95% of marked price marked price=120% of cost price therefore the cash price=95/100x120/100 of the cost price so to apply the above formular just do this 1).100+inital percentage=100+20=120 2).100-ddiscount=100-5=95 3).120x95/100=114 just minus this price to the cost price ratio which is 100{114-100}=14% the ans is 14%..this should take less than 10secs if possible[note-i only worked with the percentage figure&i didnt use the amount that is #36000] for a detailed soln 1).Gain%=actual gain/cost price x 100 0.2=36000-y/y[note-20/100=0.2] 0.2y=36000-y 1.2y=36000 y=36000/1.2 y=#30000 discount=5% of #36000 =5/100 x 36000=#1800 New selling price=#(36000-1800)=#34200 gain=#(34200-30000)=#4200 gain%=4200/30000 x 100=14% same ans..so for jambites,this process is not needed..waec students can use my formular to get the correct ans before giving detail solutions..HOPE THIS HELPS..feel free to ask any question 1 Like |
Re: Nairaland Jamb Tutorial Centre {mathematics Thread} by Nobody: 8:08am On Dec 12, 2014 |
4 differentiation, calculus etc visit http://schoolinland.com |
Re: Nairaland Jamb Tutorial Centre {mathematics Thread} by lizzlix(m): 12:36pm On Dec 12, 2014 |
GeneralShepherd:pls help with this.......In a fund-raising lottery,42% of the money collected is given as cash prizes. there are eight cash prizes altogether . the first prize winner gets #3500, the second gets #3100, the third #2700, and so on in arithmetic progression. a. How much money does the eight get? b. How much price money is there all together? c. How much money is raised for fund? |
Re: Nairaland Jamb Tutorial Centre {mathematics Thread} by GeneralShepherd(m): 4:35pm On Dec 12, 2014 |
lizzlix:I A. The eight person gets a + 7d Where a is the first term and D is the arithmetic difference between successive terms. D = 3100 - 3500 = - 400 Note that it is negative because the numbers are decreasing. Hence Term 8 = 3500 - 2800 = 700 I'll solve C before B C. Is sum of the a.P, Sn=N/2(a+l) Where n is number of terms which is 8 A is the first term 3500 and l is last term is 700. Sn= 8/2(3500+700) = 4(4200) = 16800. B. If 42% of total money is 16800 0.42X =16800 X =16800/0.42 = 40000 I hope this helps 1 Like |
Re: Nairaland Jamb Tutorial Centre {mathematics Thread} by sorbentcrooner(m): 11:58pm On Dec 13, 2014 |
GeneralShepherd: Well, I think money raised for the fund = #(40000 - 16800) = #23200. From the total money ganerned from the lottery, part (#16800) was raised as fund while the reminants was raised as funds. Tnks. Well, I think money raised for the fund = #(40000 - 16800) = #23200. From the total money ganerned from the lottery, part (#16800) was used as prizes while the reminants were raised as funds. Tnks. |
Re: Nairaland Jamb Tutorial Centre {mathematics Thread} by GeneralShepherd(m): 12:41am On Dec 14, 2014 |
sorbentcrooner: Very true, I failed that bit. Thanks |
Re: Nairaland Jamb Tutorial Centre {mathematics Thread} by sorbentcrooner(m): 8:18am On Dec 14, 2014 |
GeneralShepherd: Aii - u welcome. |
Re: Nairaland Jamb Tutorial Centre {mathematics Thread} by aptitudeexam: 1:42pm On Dec 14, 2014 |
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Re: Nairaland Jamb Tutorial Centre {mathematics Thread} by VEVEDIHNO: 3:08pm On Dec 14, 2014 |
Someshuld tackle diz Questions for me (1) 4x-3=3x+y=2y+5x-12 (2) The Ages Of Tosan and Isa Differ by 6 and the product of their ages is 187.Find Their Ages. Tanks In Advance. |
Re: Nairaland Jamb Tutorial Centre {mathematics Thread} by raayah(f): 3:53pm On Dec 14, 2014 |
VEVEDIHNO: Question 1. I dont know if its the right way to work it but here's what I did. Divide it into two parts 4x-3=3x+y--------- eq 1 and 3x+y=2y + 5x-12.--------eq 2 rearranging eq 1 4x-3x-y=3 x-y=3---------eq 3 rearranging eq 2 3x-5x+y-2y=-12 -2x -y =-12--------eq 4 solving eq 3 and 4 simultaneously x-y=3 -2x-y=-12 from eq 3, we can see x= 3+y, putting this back in eq 4 -2(3+y)-y=-12 -6-2y-y=-12 -6-3y=-12 -3y=-12+6 -3y=-6 y=2 and from x=3+y x=3+2 x=5 x=5 and y=2 check: 4x-3= 4(5)-3=20-3=17 3x+y=3(5)+2= 15+2=17 2y+5x-12=2(2)+5(5)-12 =4+25-12 =29-12 =17. There might be a shorter option but here's my method. 2 Likes |
Re: Nairaland Jamb Tutorial Centre {mathematics Thread} by raayah(f): 4:06pm On Dec 14, 2014 |
VEVEDIHNO: Question 2 Let Tosan age be x and Isa age be y.. from the question x-y=6------------- eq 1 and xy=187-------eq 2 x=6+y from equation 1 substituting into eq 2 (6+y)y=187 6y+y^2=187 rearranging y^2+6y-187=0 The only two numbers that can be added or subtracted and gives 6 and can also be multiplied to give -187 are minus 11 and 17. To get these numbers a bit of thinking might be involved!! back to solution y^2+6y-187=0 y^2+17y-11y-187=0 factorizing y(y+17)-11(y+17)=0 so (y-11) =0 or y+17=0 so y=-17 or y=11. Since y cannot be negative, age cannot be negative, y=11. Therefore Isa is 11 years. to get Tosan age we know that x-y=6 x-11=6 x=11+6 x=17. Therefore Tosan is 17 years. 1 Like |
Re: Nairaland Jamb Tutorial Centre {mathematics Thread} by sammyomotola: 9:50pm On Dec 14, 2014 |
raayah: U right guy |
Re: Nairaland Jamb Tutorial Centre {mathematics Thread} by VEVEDIHNO: 9:32am On Dec 15, 2014 |
raayah: fankz bro |
Re: Nairaland Jamb Tutorial Centre {mathematics Thread} by Nobody: 3:59pm On Dec 15, 2014 |
raayah: For anyone who gets a question like this in JAMB (and it does seem like a very likely JAMB question), it would help you a lot not to bother with all the calculations. Don't get me wrong! The calculation is cool and good to know. But in a situation where you need to be time-conscious, like in JAMB, you need all the awareness you can get. If the options is comprised of just integers, then it would help if you knew that the number 187 is not divisible by any other numbers except 11 & 17. Those are the only two numbers that can multiply to give you 187. Both are primes and 187 is a product of those two primes. If you knew that, you are well on your way to the answer to this question. |
Re: Nairaland Jamb Tutorial Centre {mathematics Thread} by raayah(f): 5:50pm On Dec 15, 2014 |
goofyone: These questions did not come with options.I had to solve it the long way. You can tell the people posting questions to add the options in the questions also. Of course, it would seem easier to plug in the variables and work your way back. But w/o options given, what was I supposed to do. Hopefully, someone learned something from my calculations and you don't have to be so rude. |
Re: Nairaland Jamb Tutorial Centre {mathematics Thread} by Nobody: 6:25pm On Dec 15, 2014 |
raayah: Hey, come on! I understand. Not trying in any way to say you didn't or haven't done a good job. Easy now. Just offering another insight into a solution. Thanks anyways. And sorry if I came off as rude. |
Re: Nairaland Jamb Tutorial Centre {mathematics Thread} by Adiwana: 8:19pm On Dec 15, 2014 |
goofyone:guy abeg where you go..youve kept me in the dark..pls post questions and faster answers..thanks in advance |
Re: Nairaland Jamb Tutorial Centre {mathematics Thread} by Dacronym(m): 3:42pm On Dec 16, 2014 |
Y = tan x-x. Find dy/dx. Anyone who can try ASAP. |
Re: Nairaland Jamb Tutorial Centre {mathematics Thread} by 2muchopoTBdope(m): 4:42pm On Dec 16, 2014 |
Dacronym:y = tan x - x dy/dx = Sec^2x - 1. because ; Differentiating tan x gives sec square x and differentiating x gives 1. |
Re: Nairaland Jamb Tutorial Centre {mathematics Thread} by factorial1(m): 9:54am On Dec 17, 2014 |
2muchopoTBdope:maybe you should explain how the derivative of tanx is sec²x. |
Re: Nairaland Jamb Tutorial Centre {mathematics Thread} by dejt4u(m): 11:27am On Dec 17, 2014 |
factorial1: tan x = (sin x)/(cos x), d/dx (tan x) = ? Using quotient rule, dy/dx = (vdu/dx - udv/dx) / v², . . . fill in the spaces, then derivative of tan x = sec²x |
Re: Nairaland Jamb Tutorial Centre {mathematics Thread} by factorial1(m): 12:00pm On Dec 17, 2014 |
dejt4u:not that I didn't know it... I just want him to give full explanation... As a matter of fact, I'm not the one that asked the question. The thing is... it would be more better for anyone that would be answering questions here to be giving the full solution, so that the aim of this thread can be achieved. |
Re: Nairaland Jamb Tutorial Centre {mathematics Thread} by dejt4u(m): 12:25pm On Dec 17, 2014 |
factorial1:bros bros.. I wont underate you now.. I know you and i knw your ability.. I only did that for the jambites here! |
Re: Nairaland Jamb Tutorial Centre {mathematics Thread} by factorial1(m): 12:29pm On Dec 17, 2014 |
dejt4u:Lol.. oga mi, I get that jare... just to let the "question solvers" know ni. |
Re: Nairaland Jamb Tutorial Centre {mathematics Thread} by 2muchopoTBdope(m): 5:49pm On Dec 17, 2014 |
factorial1:Aite,I will. Tan x = Sin x/Cos x Using quotient rule d(u/v)/dx = (Vdu/dx - udv/dx)/v^2 In this case, u = sin x and v = cos x du/dx = cos x and dv/dx = -sin x then using the quotient rule above we have; [cos x(cos x) - sin x(-sin x)]/(cos x)^2 >>>>>> [cos^2 x + sin^2 x]/ cos^2 x......equation1 From elementary trigonometry,we all know that cos^2 x + sin^2 x = 1 from equation 1,we then ve >>>>>>. 1/cos^2 x = sec^2 x cos we all know that sec x = 1/cos x. So this is hw the derivative of tan x gives sec^2 x. |
Re: Nairaland Jamb Tutorial Centre {mathematics Thread} by Doctor20002(f): 6:05pm On Dec 17, 2014 |
any unilorin aspirant click dis link nd ask any information concerning unilorin admission processing... wish u success https://www.nairaland.com/2043020/unilorin-utme-2015-2016-aspirants#28851553 |
Re: Nairaland Jamb Tutorial Centre {mathematics Thread} by lizzlix(m): 10:01pm On Dec 21, 2014 |
GeneralShepherd:Yeah, a lot ....thanks big time . I will drop more. |
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