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Magic Process :
This algorithm is a newly created algorithm which applies to both system of 2 or 3 linear equations. The algorithm involves series of steps to be observed, and it appears in matrix form. At the last stage( the last matrix) ,we then compute the determinant of 2 by 2 matrix contained in the 3 by 3 matrix ( assuming we are dealing with 3 linear equations) to have the value of the second variable, whereas the value of the first unknown is already in the 3 by 3 matrix. Then,the determinant of the whole matrix (3 by 3 in this case) yield us the value of the last or remaining unknown.

In the case of 2 linear equations, the determinant of the last matrix yields the value of the second variable whereas,one of the entry of the 2 by 2 matrix is the value of the first unknown.
Mr chinedu Makasi (b.s.c,economics) created this algorithm on the 27th day of November 2014.

See example in the mathematical capsule 1.1.

1.1

3X+2Y-Z=1
2X-2Y+4Z=-2
-X+0.5Y-Z=0

Now, going through my process, I have my final matrix below.


(0.666 0.333 -0.333)........R1
(1. 0.800. -1.400)........R2
(0. -2. 1. )........R3

This is the matrix that will yield all the values of the variables.
The second element of R3 is the value of Z. Thus Z=-2.

Now we take the determinant of the 2 by 2 matrix contained in the 3 by 3 matrix using the second and last elements of both R2 and R3. Thus we have,

Y =(0.(1) - (-2)(-1.4)=-2.

Then for x value,we compute the determinant of the whole matrix using sarrus rule or co- factor method which then gives us -1.
Then we multiply this determinant by a constant which is,+ or - 1. But we multiply by -1 in this case to have 1.
Thus, X=1.


You can check these answers using any other algorithm.

By Makasi Chinedu( b.s.c,economics)

I do not wish to show other processes since I have not published it yet. That last matrix performs so much magic and it is on that note that I nicknamed the method," Magic method.

makasimatics:
I do not wish to show other processes since I have not published it yet. That last matrix performs so much magic and it is on that note that I nicknamed the method," Magic method.

this is too rigorous

makasimatics:
Magic Process :
This algorithm is a newly created algorithm which applies to both system of 2 or 3 linear equations. The algorithm involves series of steps to be observed, and it appears in matrix form. At the last stage( the last matrix) ,we then compute the determinant of 2 by 2 matrix contained in the 3 by 3 matrix ( assuming we are dealing with 3 linear equations) to have the value of the second variable, whereas the value of the first unknown is already in the 3 by 3 matrix. Then,the determinant of the whole matrix (3 by 3 in this case) yield us the value of the last or remaining unknown.

In the case of 2 linear equations, the determinant of the last matrix yields the value of the second variable whereas,one of the entry of the 2 by 2 matrix is the value of the first unknown.
Mr chinedu Makasi (b.s.c,economics) created this algorithm on the 27th day of November 2014.

See example in the mathematical capsule 1.1.

1.1

3X+2Y-Z=1
2X-2Y+4Z=-2
-X+0.5Y-Z=0

Now, going through my process, I have my final matrix below.


(0.666 0.333 -0.333)........R1
(1. 0.800. -1.400)........R2
(0. -2. 1. )........R3

This is the matrix that will yield all the values of the variables.
The second element of R3 is the value of Z. Thus Z=-2.

Now we take the determinant of the 2 by 2 matrix contained in the 3 by 3 matrix using the second and last elements of both R2 and R3. Thus we have,

Y =(0.(1) - (-2)(-1.4)=-2.

Then for x value,we compute the determinant of the whole matrix using sarrus rule or co- factor method which then gives us -1.
Then we multiply this determinant by a constant which is,+ or - 1. But we multiply by -1 in this case to have 1.
Thus, X=1.


You can check these answers using any other algorithm.

By Makasi Chinedu( b.s.c,economics)

3X+2Y-Z=1
2X-2Y+4Z=-2
-X+0.5Y-Z=0

3 2 -1 x = 1
2 -2 4 y =-2
-1 0.5 -1 z =0

after writing the numbers in a matrix format like this then input the values of the constants in the column of each variable you want to look for and divide by the determinant of the original matrix

example: if you want to find the value of x then

1 2 -1
-2 -2 4
0 0.5 -1

find the determinant of the above matrix and divideby the determinant of

3 2 -1
2 -2 4
-1 0.5 -1


so will you do for y and z and replacing the column of the places the appeared with the constants

DEGREE2466:
3X+2Y-Z=1
2X-2Y+4Z=-2
-X+0.5Y-Z=0

3 2 -1 x = 1
2 -2 4 y =-2
-1 0.5 -1 z =0

after writing the numbers in a matrix format like this then input the values of the constants in the column of each variable you want to look for and divide by the determinant of the original matrix

example: if you want to find the value of x then

1 2 -1
-2 -2 4
0 0.5 -1

find the determinant of the above matrix and divideby the determinant of

3 2 -1
2 -2 4
-1 0.5 -1





so will you do for y and z and replacing the column of the places the appeared with the constants

What u just did was determinant over determinant. And that is cramas rule.

DEGREE2466:
this is too rigorous

It is not, only if u grasp the principle behind it. 4 processes were taken b4 the magic matrix was derived. The steps are what u will wish to know

makasimatics:
What u just did was determinant over determinant. And that is cramas rule.

yea crammers rule bro

makasimatics:
What u just did was determinant over determinant. And that is cramas rule.

good job , but you make it complex for beginner instead of using the long crammers rule why can't you use sarrus method or inverse method that quite explanatory.

team #habiz EEE

Habiz:
good job , but you make it complex for beginner instead of using the long crammers rule why can't you use sarrus method or inverse method that quite explanatory.

team #habiz EEE

I have a process for it. I just showed the conclusion. Do not worry, I will publish it soon. Thanks for the compliment.