Please I Need Help Writing This Code - Programming

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Please I Need Help Writing This Code - Programming - Nairaland

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Please I Need Help Writing This Code by StevensJojo(f): 2:46pm On May 29, 2015

Hi guys,

I'm a digital marketer with a little knowledge of html and css.

Today I hit a brick wall. Iv got a task I need to execute but it's JavaScript- I'm clueless!

Here's the instructions I'm supposed to follow-

1. Code a JAvaScript

2. Put 3 blogpost urls in the JavaScript

3. Create a function that would open all the Web addresses in my browser

4. Make the function sleep for 3-4 minutes

5. When the JavaScript reaches the end, it'll automatically bounce and repeat.

Please help?!

Re: Please I Need Help Writing This Code by kudaisi(m): 4:37pm On May 29, 2015

Not necessarily the best method to go about it, but this should work.

<!DOCTYPE html>
<html>
	<head>
		<script>

			var urls =  [
				"http://www.yahoo.com/", 
				"http://www.outlook.com/", 
				"http://www.gmail.com/"
			];
			console.log("test";
			var length = urls.length;
			var i = 0
			function getUrl(){
				if(i==length - 1 ){i=0;}
				return urls[i];
			}

			function openUrl(url){
				console.log("Opening url: "+url);
				//window.open(url, "_self"//curent page
				//window.open(url, "_parent";// parent fame
				window.open(url, "_blank"//new window (default)
				//window.open(getUrl(), "_top";// replaces frameset
				i++;
			}
			
			function sleep() {
    				setTimeout(function () {
					openUrl(getUrl());
					sleep();
			    	}, 10000);
			}
			
			sleep();
		</script>
	</head>
	<body>
	</body>
</html>

Re: Please I Need Help Writing This Code by StevensJojo(f): 5:11pm On May 29, 2015

Thanks!

kudaisi:
Not necessarily the best method to go about it, but this should work.

<!DOCTYPE html>
<html>
	<head>
		<script>

			var urls =  [
				"http://www.yahoo.com/", 
				"http://www.outlook.com/", 
				"http://www.gmail.com/"
			];
			console.log("test";
			var length = urls.length;
			var i = 0
			function getUrl(){
				if(i==length - 1 ){i=0;}
				return urls[i];
			}

			function openUrl(url){
				console.log("Opening url: "+url);
				//window.open(url, "_self"//curent page
				//window.open(url, "_parent";// parent fame
				window.open(url, "_blank"//new window (default)
				//window.open(getUrl(), "_top";// replaces frameset
				i++;
			}
			
			function sleep() {
    				setTimeout(function () {
					openUrl(getUrl());
					sleep();
			    	}, 10000);
			}
			
			sleep();
		</script>
	</head>
	<body>
	</body>
</html>

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