(it was given at a math contest for ten year olds and apparently many math teachers couldn't figure out a solution):

We have numbers 1, 3, 4 and 6. Create an expression using any elementary operators (+, -, *, /), containing only these numbers, exactly once each, such that the result is 24, you can also include parens ( and ).

I felt the problem itself is inappropriate for 10 y.o. kids and irrelevant for a maths contest; but it seemed like a good programming exercise

So come up with a program to give the solution(s).

Use any Language you feel comfortable with

My Brute force approach, would be to loop through all the number, then check which if the operators would sum to 24.

FrankLampard:
My Brute force approach, would be to loop through all the number, then check which if the operators would sum to 24.

Talk's cheap, show us code

Kodejuice:


Talk's cheap, show us code

OK

You mean the statement to executed should only contain unique operands(the numbers) that cannot be repeated, but the set (1, 3, 4, 6) may not be exhausted. You may use all operators, combine or just a single one?

paranorman:
You mean the statement to executed should only contain unique operands(the numbers) that cannot be repeated, but the set (1, 3, 4, 6) may not be exhausted. You may use all operators, combine or just a single one?

You may combine the operators, but use the numbers once

Kodejuice:


You may combine the operators, but use the numbers once

Must the four numbers be used?

If yes, here's my answer on python 2.7

from __future__ import division

numbers=[1,3,4,6]
result = int(numbers[3] / (numbers[0] - (numbers[1] / numbers[2])))
print(result)

Jolliano:


Must the four numbers be used?

If yes, here's my answer on python 2.7

from __future__ import division

numbers=[1,3,4,6]
result = int(numbers[3] / (numbers[0] - (numbers[1] / numbers[2])))
print(result)

LoL, BULLCRAP... This is not a solution.
SHow the code that computed the value '6/(1-(3/4))'

Jolliano:

Must the four numbers be used?
If yes, here's my answer on python 2.7
from __future__ import division
numbers=[1,3,4,6] result = int(numbers[3] / (numbers[0] - (numbers[1] / numbers[2]))) print(result)

LOL

i dnt knw how use recursion(method dt calx itslf) very wel buh it x perfect 4 dx