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You seriously mean all these?

You ain't got a teacher.
You leave all what you should solve for people to do it online.

Discriminate=b2-4ac

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Impostorr:



Is better you don't comment if you don't want to contribute positively. Don't judge about what you see

He just told you that the discriminant in number 3aii is b²-4ac

Impostorr:
please help me solve this or any one you can help me solve there and help me snap and post it here please

Got to ask why you need answers to all those questions? Would have loved to help but dont want to be seen as encouraging cheating.

Tell me why you need answers to those questions. If cogent, I'll help.

men! mathematics nor get joy............

These questions are very simple. I dnt know how to post it here.


Very simple I must say.



Send me your what's app number so I can forward all the answers to you. Or let me see if I can post it here


No 6


6. Permutation means each of several possible ways in which a set or number of things can be ordered or arranged .While combination means selection of objects without regard to the order in which they are selected.
In permutation we arrange while in combination we select.

The difference is "ordering"
6ai.
Laboratory.

1 "L", 2 "a's", 1"b",2"o's",2"r's",1"t",1"y".
Total letters=10
So we have. 10! / 2!.2!.2!

10x9x8x7x6x5x4x3x2x1 / 2x1x2x1x2x1

=453600

6aii). Technology.
1"t", 1"e", 1"c",1"h"1"n",2"0's", 1"l",1"g",1"y".


Technology has 10 letters

So we have ,

10!/2!
10x9x8x7x6x5x4x3x2x1/2x1
=1814440

6B) total questions =6
No to ans =4


This has to do with combination.
n!/(n-r)!r!
Choices of choosing 4 out of 6 is

6!/(6-4)!4!
=6x5x4!/2!4!
=30/2 =15 choices



6bii) first and the last compulsory.


Take them both to be 2(first and last)


Now we have 6-2=4 remaining non-compulsory questions.

We are to choose 2non compulsory and 2 compulsory (which are the first and last)

Ways of choosing 2 non compulsory questions
Out of 6-2=4
4C2= 4!/(4-2)!2! Multiplied by(2x1)

4x3x2x1/2x1x2x1=6
Then the 2 compulsory ones is 2x1
6x2x1= 12 choices
6biii) the even numbered ?'s are 2,4,6

We have 3 compulsory and 3 non compulsory


We have 3C3 x 3CW
3!/(3-3)!3! X 3!/(3-1)!
3C3=1

3C1= 3

The ans is 3x1= 3 choices.


The rest of the questions are very simple, I just did no 6 cus it's a lil bit tough r

I used to tell my students
Nothing is hard its just d mind...
Pm me on 08033023247 and would send u answers

Running outta thread cos me and math no be friends.

In PMB's voice Lazy Nigerian youth

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