Always be very free to post ur questions in any subject for the house to help u out,

Please help me explain threshold frequency and work-function in photoelectricty.

This is it:
photoelectricity talks about ejection of electrons from a metal surface when they got illuminated.
The process of that is called photoelectric effect, ie the emission of electrons out from a metal surface when light beam(photons) strikes on them. But the beam of light must posses a minimum amount of energy for photoelectric effect to occur, this energy is called the work function,w. This w will be sufficient enough to EJECT the electrons out and aswell give them KINETIC energy(k).the w depends on the type of metal, i.e w varies for d/f metals.therefore w=h¥, h is placks constant,¥ is the threshold frequency which is minimum freq the photon must posses for the process to occur.
The topic is a very good one, jst read and understand, and God must surely see u through,

This is it:
photoelectricity talks about ejection of electrons from a metal surface when they got illuminated.
The process of that is called photoelectric effect, ie the emission of electrons out from a metal surface when light beam(photons) strikes on them. But the beam of light must posses a minimum amount of energy for photoelectric effect to occur, this energy is called the work function,w. This w will be sufficient enough to EJECT the electrons out and aswell give them KINETIC energy(k).the w depends on the type of metal, i.e w varies for d/f metals.therefore w=h¥, h is placks constant,¥ is the threshold frequency which is minimum freq the photon must posses for the process to occur.
The topic is a very good one, jst read and understand, and God must surely see u through,

You can go on with the calculations, jst try to understand the question. [color=#990000][/color]

Ozor, thanks very much. In that same topic there is this calculation, check if u can help me out, Caesium has a work function of 1.9electronvolts. Find (a)its threshold wavelenght(b)the maximum energy of the liberated electrons when the metal is illuminated by light of wavelenght 4.5x10^-7)meters (c)the stopping potential .i need a little explanation on that stopping potential.

[color=#550000][/color]
(a) Note that some constant will be given:c=speed of light(3x10^m/s,h=placks const,h,(6.6x10^-34)Js, 1electron volt,P=(1.6x10^-19)joules. Caesium is a metal of workfntn=1.9xP,let threshold wavelenght=L=c/f,W=hf, L=ch/W, Substitue correctly to have (6.5x10^-7)m.
(b)max energy of liberated electrons=hf-W=(hc/L)-W, on correct substitution (1.4x10^-19)J is the max energy.
(c) the stopping pd(V) needs a diagramatic analogy 4u to understand. Post ur mail address here so can send u a material that will help u.

Wait 4 my questions. They are coming in loads.

Continental issues as cult butchers final year student.
Details at www.educationigeria..com and like group at www.facebook.com/pages/Voice-of-the-Nigerian-Tertiary-InstitutionsVNTI/362095437154273

Don't miss that news. Invite your friends and swell the community.