Learned colleagues. Please help your bros.

Oh boi!

Nordicdon:
Learned colleagues. Please help your bros.

The operation * is in Mod6

e.g 2*3 = 2 × 3 = 6 == 0 (every multiple of 6 will be turned to zero.
The only numbers that can be in the table are 1,2,3,4,5,0..

1 will be 1,
2 will be 2,
3 will be 3,
4 will be 4,
5 will be 5,
6 will be 0,
7 will be 1,
8 will be 2,
9 will be 3,
10 will be 4,
11 will be 5,
12 will be 0,
13 will be 1,
14 will be 2,
15 will be 3,
16 will be 4,
17 will be 5,
18 will be 0,
e.t.c





Now, let me answer the questions:

31. a = 3*4 = 3 × 4 = 12 == 0 ('cos 12 is a multiple of 6)

32. b = 4*5 = 4 × 5 = 20 == 2

33. c = 5*3 = 5 × 3 = 15 == 3

34. d = 5*8 = 5 × 8 = 40 == 4

35. e = 6*5 = 6 × 5 = 30 == 0

You've saved me again Dejt4u. You are a genius. How did you decode that? Wow! this one pass me to be honest. A very big thank you. You are too much.