The question is still open up fall all to try we now know the answer is 6square unit
Let see the first person to come up with basic solution to it

ifada123:

Sir we will appreciate if you can still solve it for us useing basic maths.

I will try. The integration method was what came to head immediately.

ifada123:
The question is still open up fall all to try we now know the answer is 6square unit
Let see the first person to come up with basic solution to it

9 sq units

femi4:
9 sq units

Try it out again sir

More shape questions coming
From your shape lover
Mr shape

ifada123:

Try it out again sir

Area of the square - Area of the unshaded 4 triangles - 4 unshaded unit squares

That's 5²- 4(1/2 *3*2.5) - 4

25 -15 - 4 = 6 sq units

ifada123:
The question is still open up fall all to try we now know the answer is 6square unit
Let see the first person to come up with basic solution to it

I made a mistake at the last stage of the answer I uploaded. I've traced the mistake and I've corrected it

The area of the square around the pinwheel is 25. The area of the pinwheel is equal to {the square } - the white space.} Each of the four triangles have a base of 3 units and a height of 2.5 units, and so their combined area is 15 units squared. Then the unshaded space consists of the four triangles with total area of 15, and there are four white corner squares. Therefore the area of the pinwheel is $25-(15+4)$ which is 6

Na wa o. Una don really chop belefull

vince001:
My answer:
16x²√(2x²)
Where x is the length of a small square.

Joystark:
Na wa o. Una don really chop belefull

Alhajiemeritus:
The area of the square around the pinwheel is 25. The area of the pinwheel is equal to {the square } - the white space.} Each of the four triangles have a base of 3 units and a height of 2.5 units, and so their combined area is 15 units squared. Then the unshaded space consists of the four triangles with total area of 15, and there are four white corner squares. Therefore the area of the pinwheel is $25-(15+4)$ which is 6

femi4:
Area of the square - Area of the unshaded 4 triangles - 4 unshaded unit squares

That's 5²- 4(1/2 *3*2.5) - 4

25 -15 - 4 = 6 sq units

Martinez39:
I will try. The integration method was what came to head immediately.

This is my analysis

Following

Thank you O.P for adding to my knowledge

Martinez39:
with a = 1 units.

Or solve it simply by summing up of areas of the four un-shaded triangles you see within the circle, added to the four un-shaded squares and subtract from area of entire square. You get same answer. 6 sq units

mexyk:


Or solve it simply by summing up of areas of the four un-shaded triangles you see within the circle, added to the four un-shaded squares and subtract from area of entire square. You get same answer. 6 sq units

Genius!

Chai... Na now I know say I no Sabi maths.

More shape coming
I remain your shape lover
Mr shape