(1.)find the point of intersection of two lines: 2x-3y+1=0 and 4y+3x+2=0

(2.) 1/x^2+1, what's x at infinity?
thanks

To get the first one you simply solve both equations simultaneously....
Abeg wait let me go and get my pen

PhenomenalMorgan:
To get the first one you simply solve both equations simultaneously....
Abeg wait let me go and get my pen

thanks oo

Regiomontanus I need your help here oo

JESUSBOIY:
(1.)find the point of intersection of two lines:
2x-3y+1=0 and 4y+3x+2=0


(2.) 1/x^2+1, what's x at infinity?

thanks

1.simultaneous equation

JESUSBOIY:
(1.)find the point of intersection of two lines:
2x-3y+1=0 and 4y+3x+2=0


(2.) 1/x^2+1, what's x at infinity?

thanks

2x - 3y + 1 = 0 can be rewritten as y = ⅔x + ⅓
4y + 3x + 2 = 0 can be rewritten as y = -¾x - ½
Solving simultaneously for x we have
y = ⅔x + ⅓ = -¾x - ½
Solving for x we have
x = - 10/17
Substituting this value of x into anyone of the original equations, say y = ⅔x + ⅓ yields y= - 1/17.

The point of intersection is (-10/17, -1/17)

Regiomontanus:


2x - 3y + 1 = 0 can be rewritten as y = ⅔x + ⅓
4y + 3x + 2 = 0 can be rewritten as y = -¾x - ½
Solving simultaneously for x we have
y = ⅔x + ⅓ = -¾x - ½
Solving for x we have
x = - 10/17
Substituting this value of x into anyone of the original equations, say y = ⅔x + ⅓ yields y= - 1/17.

The point of intersection is (-10/17, -1/17)

thanks Bless you sir. Abeg what about the second one?

It's coming late. Sorry.

DesChyko:
It's coming late. Sorry.

God bless and increase you sir ,you are too much

Chai ....ppul sabi math o

For number 2 why is it equal to zero. What happened to the 1 that’s the numerator

DesChyko:
It's coming late. Sorry.

ibizgirl:
For number 2 why is it equal to zero. What happened to the 1 that’s the numerator

Generally, for a value like 1/b to be equal to infinity (where 1 is the numerator and b is the denominator), b is equal to 0.
Look at it this way
1/5 = 2
1/2 = 5
1/0.5 = 2
1/ 0.01 = 100
You can see that as the denominator gets closer to zero, the answer becomes larger and larger.
So it is when the denominator eventually gets to zero that it will give infinity as its answer.
That's why I equated the denominator to zero.

DesChyko:
It's coming late. Sorry.

deschyko, why is it necessary to multiply the first n second equation by 3 and 2? Question 1

DJHANDSOME:
deschyko, why is it necessary to multiply the first n second equation by 3 and 2? Question 1

To make the coefficient of one variable in both equations the same so that when you subtract one equation from the other, the variable will be eliminated and you can easily solve for the other variable (Elimination method)

In that case, I chose to eliminate variable 'x' so I multiplied the first equation with the coefficient of x in the second equation.. Then I multiplied the second equation with the coefficient of x in the first equation.

If I chose to eliminate y, I would use the coefficients of y to multiply instead so that when I subtract, y would be eliminated.

DesChyko:
It's coming late. Sorry.

deschyko, abeg EPP a student when you have the time


Find the center and radius of a circle with equation:
3x^2+3y-9x+12y-9=0

JESUSBOIY:
deschyko, abeg EPP a student when you have the time


Find the center and radius of a circle with equation:
3x^2+3y-9x+12y-9=0

This question appears incomplete. One of the y-variable should have a square. Let's assume it's 3y.

If that is not the case, holla.

DesChyko:


This question appears incomplete. One of the y-variable should have a square. Let's assume it's 3y.

If that is not the case, holla.

yes its 3y^2, my bad

JESUSBOIY:
yes its 3y^2, my bad

That's it then.