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Nairaland Forum / Nairaland / General / Education / My First Math 111 Class. And It Confusing I Need Help (2163 Views)
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My First Math 111 Class. And It Confusing I Need Help by emmysolo2001(f): 9:13pm On Jan 21, 2020 |
Good evening nairaland please I need help with this math assignment 1.A bag contains 36 coins.the coins are a mixture of one dollar coin and 50 cents coins.the total value of the coins in the bag is $26.50.how many one dollar coin are there in the bag. 2.5 times a certain number take away 2 times another number gives 15.the sum of the two numbers is 6 and half.find the two numbers 1 Like 1 Share |
Re: My First Math 111 Class. And It Confusing I Need Help by iyke4(m): 9:36pm On Jan 21, 2020 |
on It |
Re: My First Math 111 Class. And It Confusing I Need Help by dejt4u(m): 9:40pm On Jan 21, 2020 |
emmysolo2001:1. There are 17 one dollar coins and 19 fifty cents coins 2. This is a simultaneous equation: 5x-2y=15.......eqn (1) x+y = 6½ .......eqn (2) Solving this, x=4 and y=2½ 2 Likes 1 Share |
Re: My First Math 111 Class. And It Confusing I Need Help by OutOfTheAshes(m): 9:47pm On Jan 21, 2020 |
Solution to question 1 100cents = 1 dollar. Let x represent the number of 50cent coins Let y represent the number of 1 dollar (100cent) coins Total coins = 36 x + y = 36............................ equation (1) Total value of coins = $26.50 $26.50 = 26 dollars + 0.50 dollar Convert$ 26.50 to cent = 26.50dollars * 100cents = 2650cents 100x + 50y = 2650 total value of 1 dollar coins plus 50 cent coins…............ equation (2) Using elimination method multiple equation (1) by 100 100x + 100y = 3600...................... equation (3) equation (3) minus equation (1) Taking it term by term from both equations (3) and (1) For x: 100x - 100x = 0 For y: 100y - 50y = 50y For the constant terms on the Right Hand Side of both equations: 3600 - 2650 = 950 Therefore 50y = 950 Divide both sides by 50 to get y (50y/50) = (950/50) y = 19 The number of 1 dollar coins is 19 Plug 19 into equation (I) to get x: x + 19 = 36 Subtract 19 from both sides of the equals sign to get x, x + 19 - 19 = 36 - 19 NB: +19 - 19 = 0 x = 17 16 Likes 2 Shares |
Re: My First Math 111 Class. And It Confusing I Need Help by OutOfTheAshes(m): 10:14pm On Jan 21, 2020 |
Solution to question 2. 5 times a certain number. Let that certain number be u so 5*u = 5u. 2 times another number. Let that another number be v so 2*v = 2v. So take away 2v from 5u = 5u -2v gives 15 Therefore 5u - 2v = 15............ equation (1) The sum of the two numbers ( u and v) is 6(1/2). Thus u + v = 6(1/2)................... equation (2) Convert 6(1/2) to a proper fraction = 13/2 Plug it back to equation (2) u + v = 13/2............ equation (3) Clear fraction in equation (3) by multiplying all the terms on both sides of the equals sign by 2. 2u + 2v = 13................. equation (4) Now we have 5u - 2v = 15…....... equation (I) 2u + 2v = 13............ equation (4) By method of elimination, add equation (I) and equation (4) For u terms: 5u + 2u = 7 u For v terms: -2v + 2v = 0 ( v is eliminated). For constant terms: 13 + 15 = 28 Thus, 7u = 28 Divide both sides by 7 to get u (7u/7) = 28/7 u = 4 Plug the value of u into equation (I) to get the value of v 5*4 - 2v = 15 20 - 2v = 15 Subtract 20 from both sides of the equals sign to get v, thus 20 - 2v - 20 = 15 - 20 20 - 20 - 2v = 15 - 20 -2v = -5 Divide both sides of the equals sign by (-2) (-2v/-2) = -5/-2 (-)at the numerator will cancel (-)at the denominator v = 5/2 or 2(1/2) 9 Likes |
Re: My First Math 111 Class. And It Confusing I Need Help by emmysolo2001(f): 10:43pm On Jan 21, 2020 |
OutOfTheAshes:sir please can you reduce to a simpler term I got lost in the first solution From taking it term by term from both eqn 3 and 1 where did 100x I got lost at that point And for the second I don't understand at all |
Re: My First Math 111 Class. And It Confusing I Need Help by eddyghali(m): 6:00am On Jan 22, 2020 |
emmysolo2001:Can u read it in ur native language? slow learners do that and its a sure banker to help them. How else will he explain again |
Re: My First Math 111 Class. And It Confusing I Need Help by FromZeroToHero(m): 6:16am On Jan 22, 2020 |
emmysolo2001:it's well explained. Meet any of your course mate. You guys should put head together |
Re: My First Math 111 Class. And It Confusing I Need Help by emmysolo2001(f): 7:00am On Jan 22, 2020 |
FromZeroToHero:OK thanks |
Re: My First Math 111 Class. And It Confusing I Need Help by sunshineV(f): 10:05am On Jan 22, 2020 |
Intelligent people dey NL but clowns plenty pass |
Re: My First Math 111 Class. And It Confusing I Need Help by lilachiever(m): 11:45am On Jan 22, 2020 |
OutOfTheAshes: Nice job you did there Sir, but you made a mistake while drafting out equation (2). According to you, x=50cents and y=100cents=1dollar. But you represented 50cents with y in eqn(2) and 100cents with x meanwhile it should have been the other way round. 1 Like |
Re: My First Math 111 Class. And It Confusing I Need Help by OutOfTheAshes(m): 5:09pm On Jan 22, 2020 |
lilachiever: Thanks for the correction. It's a mistake. The number of cent 50cent coins is x = 19 While the number of 1 dollar coins is y = 17 To whom it may concern take note and make the necessary corrections. 2 Likes |
Re: My First Math 111 Class. And It Confusing I Need Help by Ge0grapher(m): 6:31pm On Jan 22, 2020 |
I am not destined to pertake in this thread make i enter romance section 1 Like |
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