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Who Can Attempt This Math Question? by Miracle911(m): 7:18pm On Jul 10, 2020 |
Mathematics Gurus in the house please try
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Re: Who Can Attempt This Math Question? by Nobody: 7:28pm On Jul 10, 2020 |
Yes. There are so many X's there, which one should I find? |
Re: Who Can Attempt This Math Question? by meum: 9:21pm On Jul 10, 2020 |
Bro this is easy na. Lemme casually solve it 4 u **Grabs pen and paper** Done. Lemme upload the answers I Don slove maths tire 4 dis nairaland.lol Mathematics class for a fee. Send me an email let's start that online maths class. 1 Like |
Re: Who Can Attempt This Math Question? by meum: 9:53pm On Jul 10, 2020 |
I don't know if you can see it(I've taken down the image of the solution & decided to solve it here so you can see it well). U fit ask questions if you don't understand. Solution: The sum of the angles in a triangle always adds up to 180° So, (5x)°+ (x+6)°+(2x-2)°=180° (5x+x+6+2x-2)°=180° 5x+x+6+2x-2 = 180 Collecting like terms: 8x+4=180 Subtracting 4 from both sides we have 8x=180-4 8x = 176 Therefore, x =22 Substitute the value of x into each expression (5x)° = (5 x 22)°= 110° (x+6)°= (22+6)° = 28° (2x-2)°= [(2 x 22) - 2]° =[44 - 2]° = 42° Therefore,m<U = 28°, m<V=42° and m<W=110° Notice that the sum of m<U, m<V and m<W sums up to 180°(sum of angles in a triangle) ie. 28°+42°+110° =180° Mathematics class for a fee. Send me an email let's start that online maths class. Tell some1 you know he/she might need it 3 Likes 1 Share |
Re: Who Can Attempt This Math Question? by dejt4u(m): 10:24pm On Jul 10, 2020 |
Answer to the second question is 1.8 hours 1 Like |
Re: Who Can Attempt This Math Question? by dejt4u(m): 10:27pm On Jul 10, 2020 |
Re: Who Can Attempt This Math Question? by Miracle911(m): 10:32pm On Jul 10, 2020 |
meum: Got it bro.... thanks.. |
Re: Who Can Attempt This Math Question? by Miracle911(m): 10:34pm On Jul 10, 2020 |
dejt4u: Thanks man.. I’d love to see how you arrived at 1.8hrs |
Re: Who Can Attempt This Math Question? by meum: 10:36pm On Jul 10, 2020 |
Miracle911:Glad I could help. Next time u go pay lesson fee. **smiles** |
Re: Who Can Attempt This Math Question? by Miracle911(m): 10:43pm On Jul 10, 2020 |
Re: Who Can Attempt This Math Question? by dejt4u(m): 10:53pm On Jul 10, 2020 |
Miracle911:the first train travels faster. Their speed is in the ratio 95:75 Using that ratio for their respective distances each of them will cover before they meet; the faster train will cover 171 miles (i.e 95/170 × 306miles) and the second train will cover 135 miles (i.e 75/170 × 306miles) Using the formula, time = distance ÷ speed 1st train, time = 171miles ÷ 95 miles per hour = 1.8 hours 2nd train, time = 135miles ÷ 75 miles per hour = 1.8 hours Each of the will therefore travel for 1.8hours before the meet |
Re: Who Can Attempt This Math Question? by meum: 11:17pm On Jul 10, 2020 |
Miracle911: Solution: the distance between the two trains is 306miles. This is the total distance the trains will cover in order for them to meet. Let the two trains be A & B Recall that distance = rate x time ie D=RT. Now let's calculate or express the distance traveled by both trains A & B Since Train A is moving at 95miles in T hours, it will cover a distance of 95 x T miles Also, since Train B is moving at 75 miles in T hours it will cover a distance of 75 x T miles Together the two trains A & B will cover a distance of 95T + 75T From the question we know that the distance between them is 306 miles, we can express this in algebraic equation thus: 95T + 75T = 306 Solving the above equation we have: 170T = 306 Therefore, T = 1.8hours This shows that the two trains will meet in 1.8hours. |
Re: Who Can Attempt This Math Question? by Miracle911(m): 11:41pm On Jul 10, 2020 |
Thanks brothers... Really appreciate your help |
Re: Who Can Attempt This Math Question? by meum: 11:48pm On Jul 10, 2020 |
Profit from sale of each Mp3 =$35 Profit from sale of each DVDplayer = $18 Total items sold = 119 Number of Mp3 players sold = x Number of DVD players sold = total number of items sold - number of Mp3 players sold ie (119-x) Therefore, total profit = $35x + $18(119-x) = $35x + $2142 - $18x = $17x +$2142 Oya bring your lesson fee |
Re: Who Can Attempt This Math Question? by dejt4u(m): 7:25am On Jul 11, 2020 |
Re: Who Can Attempt This Math Question? by meum: 9:12am On Jul 11, 2020 |
dejt4u: $35x - $18x = $17x I've looked at it again. I don't think there's a mistake in my final answer. |
Re: Who Can Attempt This Math Question? by dejt4u(m): 9:40am On Jul 11, 2020 |
meum:sorry. You're correct |
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