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Who Can Attempt This Math Question? - Education - Nairaland

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Who Can Attempt This Math Question? by Miracle911(m): 7:18pm On Jul 10, 2020
Mathematics Gurus in the house please try

Re: Who Can Attempt This Math Question? by Nobody: 7:28pm On Jul 10, 2020
Yes.
There are so many X's there, which one should I find?
Re: Who Can Attempt This Math Question? by meum: 9:21pm On Jul 10, 2020
Bro this is easy na. Lemme casually solve it 4 u
**Grabs pen and paper**

Done. Lemme upload the answers grin

I Don slove maths tire 4 dis nairaland.lol grin grin

Mathematics class for a fee. Send me an email let's start that online maths class.

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Re: Who Can Attempt This Math Question? by meum: 9:53pm On Jul 10, 2020
I don't know if you can see it(I've taken down the image of the solution & decided to solve it here so you can see it well).

U fit ask questions if you don't understand.

Solution:

The sum of the angles in a triangle always adds up to 180°

So, (5x)°+ (x+6)°+(2x-2)°=180°

(5x+x+6+2x-2)°=180°

5x+x+6+2x-2 = 180

Collecting like terms:

8x+4=180

Subtracting 4 from both sides we have

8x=180-4

8x = 176

Therefore, x =22

Substitute the value of x into each expression
(5x)° = (5 x 22)°= 110°
(x+6)°= (22+6)° = 28°
(2x-2)°= [(2 x 22) - 2]° =[44 - 2]° = 42°

Therefore,m<U = 28°, m<V=42° and m<W=110°

Notice that the sum of m<U, m<V and m<W sums up to 180°(sum of angles in a triangle)

ie. 28°+42°+110° =180°


Mathematics class for a fee. Send me an email let's start that online maths class. Tell some1 you know he/she might need it grin

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Re: Who Can Attempt This Math Question? by dejt4u(m): 10:24pm On Jul 10, 2020
Answer to the second question is 1.8 hours

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Re: Who Can Attempt This Math Question? by dejt4u(m): 10:27pm On Jul 10, 2020
Re: Who Can Attempt This Math Question? by Miracle911(m): 10:32pm On Jul 10, 2020
meum:
I don't know if you can see it(I've taken down the image of the solution & decided to solve it here so you can see it well).

U fit ask questions if you don't understand.

Solution:

The sum of the angles in a triangle always adds up to 180°

So, (5x)°+ (x+6)°+(2x-2)°=180°

(5x+x+6+2x-2)°=180°

5x+x+6+2x-2 = 180

Collecting like terms:

8x+4=180

Subtracting 4 from both sides we have

8x=180-4

8x = 176

Therefore, x =22

Substitute the value of x into each expression
(5x)° = (5 x 22)°= 110°
(x+6)°= (22+6)° = 28°
(2x-2)°= [(2 x 22) - 2]° =[44 - 2]° = 42°

Therefore,m<U = 28°, m<V=42° and m<W=110°

Notice that the sum of m<U, m<V and m<W sums up to 180°(sum of angles in a triangle)

ie. 28°+42°+110° =180°


Mathematics class for a fee. Send me an email let's start that online maths class. Tell some1 you know he/she might need it grin


Got it bro.... thanks..
Re: Who Can Attempt This Math Question? by Miracle911(m): 10:34pm On Jul 10, 2020
dejt4u:
Answer to the second question is 1.8 hours

Thanks man..

I’d love to see how you arrived at 1.8hrs
Re: Who Can Attempt This Math Question? by meum: 10:36pm On Jul 10, 2020
Miracle911:


Got it bro.... thanks..
Glad I could help. Next time u go pay lesson fee.
**smiles**
Re: Who Can Attempt This Math Question? by Miracle911(m): 10:43pm On Jul 10, 2020
dejt4u:
Answer to the second question is 1.8 hours


Got it. Thanks
Re: Who Can Attempt This Math Question? by dejt4u(m): 10:53pm On Jul 10, 2020
Miracle911:


Thanks man..

I’d love to see how you arrived at 1.8hrs
the first train travels faster. Their speed is in the ratio 95:75

Using that ratio for their respective distances each of them will cover before they meet; the faster train will cover 171 miles (i.e 95/170 × 306miles) and the second train will cover 135 miles (i.e 75/170 × 306miles)

Using the formula, time = distance ÷ speed
1st train, time = 171miles ÷ 95 miles per hour = 1.8 hours
2nd train, time = 135miles ÷ 75 miles per hour = 1.8 hours

Each of the will therefore travel for 1.8hours before the meet
Re: Who Can Attempt This Math Question? by meum: 11:17pm On Jul 10, 2020
Miracle911:


Thanks man..

I’d love to see how you arrived at 1.8hrs

Solution: the distance between the two trains is 306miles. This is the total distance the trains will cover in order for them to meet.

Let the two trains be A & B

Recall that distance = rate x time ie D=RT.
Now let's calculate or express the distance traveled by both trains A & B

Since Train A is moving at 95miles in T hours, it will cover a distance of 95 x T miles

Also, since Train B is moving at 75 miles in T hours it will cover a distance of 75 x T miles

Together the two trains A & B will cover a distance of 95T + 75T


From the question we know that the distance between them is 306 miles, we can express this in algebraic equation thus:

95T + 75T = 306

Solving the above equation we have:

170T = 306
Therefore, T = 1.8hours
This shows that the two trains will meet in 1.8hours.
Re: Who Can Attempt This Math Question? by Miracle911(m): 11:41pm On Jul 10, 2020
Thanks brothers... Really appreciate your help
Re: Who Can Attempt This Math Question? by meum: 11:48pm On Jul 10, 2020
Profit from sale of each Mp3 =$35
Profit from sale of each DVDplayer = $18
Total items sold = 119
Number of Mp3 players sold = x

Number of DVD players sold = total number of items sold - number of Mp3 players sold ie (119-x)

Therefore, total profit = $35x + $18(119-x)
= $35x + $2142 - $18x
= $17x +$2142

Oya bring your lesson fee grin
Re: Who Can Attempt This Math Question? by dejt4u(m): 7:25am On Jul 11, 2020
Re: Who Can Attempt This Math Question? by meum: 9:12am On Jul 11, 2020
dejt4u:
you made a mistake in your final answer. Kindly check again.. It's not 17x

$35x - $18x = $17x

I've looked at it again. I don't think there's a mistake in my final answer.
Re: Who Can Attempt This Math Question? by dejt4u(m): 9:40am On Jul 11, 2020
meum:


$35x - $18x = $17x

I've looked at it again. I don't think there's a mistake in my final answer.
sorry. You're correct

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