Complex Math Solution: Somebody Help - Education - Nairaland
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| Complex Math Solution: Somebody Help by bobbyray(op): 10:24am On Feb 11, 2011 |
Could anyone help me find what x is in this equations; and prob the steps 4x^4 - x^3 + 2 = 0 |
| Re: Complex Math Solution: Somebody Help by Beaf: 5:20pm On Feb 11, 2011 |
| Re: Complex Math Solution: Somebody Help by IbrahimB: 8:58pm On Feb 11, 2011 |
Just plot it on a graph. The values for x are where the curve crosses the x-axis  |
| Re: Complex Math Solution: Somebody Help by bobbyray(op): 9:31am On Feb 14, 2011 |
plotting the graph is w whole lot of riddle, can you guide me? |
| Re: Complex Math Solution: Somebody Help by webmonkey(m): 11:24am On Feb 14, 2011 |
Open your microsoft excel and do the following. |
| Re: Complex Math Solution: Somebody Help by bobbyray(op): 12:39pm On Feb 14, 2011 |
Thanks, the domain is actually 4 But the graph never really cross the x-axis, does that mean there is no inflexion point? |
| Re: Complex Math Solution: Somebody Help by webmonkey(m): 2:39pm On Feb 14, 2011 |
| Re: Complex Math Solution: Somebody Help by bobbyray(op): 2:50pm On Feb 14, 2011 |
i dont get it |
| Re: Complex Math Solution: Somebody Help by webmonkey(m): 2:55pm On Feb 14, 2011 |
What do you mean by Inflection point? |
| Re: Complex Math Solution: Somebody Help by Nobody: 12:25am On Feb 16, 2011 |
The solution is in the attached pdf file. |
| Re: Complex Math Solution: Somebody Help by webmonkey(m): 10:22am On Feb 16, 2011 |
Thank you Omotodun. |
| Re: Complex Math Solution: Somebody Help by Nobody: 8:04pm On Feb 16, 2011 |
You are welcome. |
| Re: Complex Math Solution: Somebody Help by bobbyray(op): 10:39am On Feb 17, 2011 |
webmonkey:Literarily its a point where a curve changes signature. It can be gotten after finding a 2nd derivative of f(x) having looked at your solution critically, it is very difficult to say where these points are. Omotoduni, thanks for you solutions of complex cnumbers, it is amazing to find out that they are four. note am using this for geodata processing reason yor answers have given me different ideas to model my features. Thank |
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