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Nairaland Forum / Nairaland / General / Education / Who Can Solve These?? (755 Views)
Pls Who Can Solve This Its Urgent(pics) / I'll Send A Card Worth #2000 If Anyone Can Solve These Problems / Can You Solve These Quantitative Aptitude Questions? (2) (3) (4)
Who Can Solve These?? by simiife: 8:04pm On Oct 10, 2020 
I need someone to solve these math's questions

Re: Who Can Solve These?? by NairalandSARS: 8:19pm On Oct 10, 2020 
simiife:Question in pic makes no sense. 80cm vs 14cm? 
Re: Who Can Solve These?? by Spartancosta(m): 10:09pm On Oct 10, 2020 
simiife:18 6!/2!=6*5*4*3*2*1/2*1=360ways 19. Increase in radius dr/dt = 0.5 Area of the circular disc = πr Increase in area: dA/dr = 2πr Rate of increase in area: dA/dt = dA/dr * dr/dt when r = 6cm = 2πr * 0.5 = 2 * π * 6 * 0.5 2 * π * 6 * / = 6 π cm /s 
Re: Who Can Solve These?? by simiife: 10:19pm On Oct 10, 2020 
Spartancosta: Thank you very much sir, I still have more tho 
Re: Who Can Solve These?? by Spartancosta(m): 10:23pm On Oct 10, 2020 
simiife:17. tree's height =man's height + distance of the man's head to the bird distance of the man's height to the bird= / /  /__  the hypotenuse =25 opposite=height=x @=30° sin@=opp/hyp sin30=x/25 x=25sin30 x=25/2 height of the tree =25/2+1.7=14.2 
Re: Who Can Solve These?? by Spartancosta(m): 10:25pm On Oct 10, 2020 
simiife:sir? I'm a very young boy.post the questions,I will try to solve them if I can. 
Re: Who Can Solve These?? by simiife: 10:52pm On Oct 10, 2020 
Spartancosta: You are the real MVP

Re: Who Can Solve These?? by simiife: 10:54pm On Oct 10, 2020 

Re: Who Can Solve These?? by simiife: 10:58pm On Oct 10, 2020 
S

Re: Who Can Solve These?? by simiife: 11:01pm On Oct 10, 2020 
W

Re: Who Can Solve These?? by Spartancosta(m): 11:03pm On Oct 10, 2020 
simiife:will upload pics of the cone probt tomorrow r=d/2 r=10/2=5cm l²=h²+r l²=12²+5² l²=144+25 l²=169 l²=13² l=13 curved surface area =πrl π*5*13=65πcm² 
Re: Who Can Solve These?? by Spartancosta(m): 11:13pm On Oct 10, 2020 
simiife:2+xx² differentiating 12x=0 1=2x x=1/2 13 + 24 =41(all in base m) 1*m¹+3*m° +2*m¹+4*m°=4*m¹+1*m° m°=1 m+3+2m+4=4m+1 3m+7=4m+1 71=4m3m 6=m m=6 
Re: Who Can Solve These?? by Tohsynetita1: 11:13pm On Oct 10, 2020 
simiife:post the rest 
Re: Who Can Solve These?? by Spartancosta(m): 11:14pm On Oct 10, 2020 
simiife:you can do justice to the fraction question by applying the rules of bodmas or better still use the calculator 1 Like 
Re: Who Can Solve These?? by Spartancosta(m): 11:20pm On Oct 10, 2020 
simiife:the answer to the fraction question is 1 11/60 1 Like 
Re: Who Can Solve These?? by Spartancosta(m): 11:33pm On Oct 10, 2020 
simiife:6x³5x²+1/3x² 6x³/3x² 5x²/3x² +1/3x² 2x5/3+1/3x² 2x5/3+3x^2 differentiating dy/dx=2+1/3(2)(x^3) =2+(2/3(x^3)) =2(2/3)x^3 
Re: Who Can Solve These?? by Spartancosta(m): 11:34pm On Oct 10, 2020 
Spartancosta:omo my eyes don dey close 
Re: Who Can Solve These?? by simiife: 11:42pm On Oct 10, 2020 
Spartancosta: No qualms 
Re: Who Can Solve These?? by Spartancosta(m): 11:43pm On Oct 10, 2020 
The equation is y =mx + c
m is the slope = tan 135 = tan45=1
(y  y¹)/(x  x¹) = m
(y3)/(x2)=1
y  3 = (x  2)
y3=x+2
y+x=2+3
x+y=5 
Re: Who Can Solve These?? by simiife: 11:45pm On Oct 10, 2020 
Spartancosta: Pls rest brotherly,but always remember u are the realest MVP 
Re: Who Can Solve These?? by Spartancosta(m): 11:50pm On Oct 10, 2020 
simiife:I stit dey learn I don solve two more on paper make I quickly type am 
Re: Who Can Solve These?? by Spartancosta(m): 12:06am On Oct 11, 2020 
simiife:x+2xy+y²+3x+3y18 x+2xy+y²=(x+y)(x+y) 3x+3y=3(x+y) (x+y)²+3(x+y)18 comparing with ax²+bx+c where x=(x+y) let z=(x+y) we have z²+3z18 which can be factored z²3z+6z18 z(z3)6(z3) (z3)(z6) but z=x+y ((x+y)3)((x+y)6) (x+y3)(x+y6) 
Re: Who Can Solve These?? by Spartancosta(m): 12:27am On Oct 11, 2020 
simiife:P Boy 1 (W=1/2) L(1/3) boy2 (W=1/3) L(2/3) boy3 (W=1/4) L(3/4) probability of only one boy winning only= probability of boy 1 winning only+ probability of boy 2 winning only+ probability of boy 3 winning only (1/2 *2/3 *3/4) +(1/2 *1/3*3/4) +(1/2*2/3* 1/4) =(1/4) +(1/+(1/12) =11/24 
Re: Who Can Solve These?? by Spartancosta(m): 12:36am On Oct 11, 2020 
simiife:formula for chord =2r * sin@/2 =2(14)*sin60/2 28*sin30 28*0.5 =14 
Re: Who Can Solve These?? by simiife: 1:20am On Oct 11, 2020 
Spartancosta: Thanks bro, thank you 
Re: Who Can Solve These?? by simiife: 8:54pm On Oct 19, 2020 
Spartancosta: Good evening bro, been busy, would have posted since

Re: Who Can Solve These?? by Spartancosta(m): 3:26am On Oct 20, 2020 
simiife:2xy=4 x+y=2 from x+y=2,x=2y substituting into 2xy=4 2(2y)y=4 44yy=4 5y=0 y=0 x=2y x=2 points x,y=(2,0) and (4,3) formula for distance (√((x2x1)²+(y2y1)²) x1=2, x2=4 y1=0 y2=3 distance=(√(42)²+(30)²) =√((2)²+(3)1) =√13 
Re: Who Can Solve These?? by Spartancosta(m): 3:31am On Oct 20, 2020 
simiife:( (a²a)C2=(a²a)C4 let (a²a)=x xC2=xC4 comparing both sides of the equation, 2 is not equal to 4 so definitely, x=2+4 x=6 (a²a)=x a²a=6 a²a6=0 a+2a3a6=0 a(a+2)3(a+2)=0 (a3)(a+2)=0 a=3 or 2 therefore a=3 there is no diagram in the third question 
Re: Who Can Solve These?? by Spartancosta(m): 3:33am On Oct 20, 2020 
simiife:do justice to the simple interest question using the formula S.I=(PRT)/100 where S.I=interest P=principal R=rate T=time 1 Like 
Re: Who Can Solve These?? by simiife: 1:12am On Oct 21, 2020 
Spartancosta: Got this 
Re: Who Can Solve These?? by simiife: 1:36am On Oct 21, 2020 
Spartancosta:

Re: Who Can Solve These?? by Spartancosta(m): 4:41pm On Oct 21, 2020 
Sketch a triangle and place M at the upper vertex and N , O at the two vertexes of the base. Now, if the bisector at angle M,meets line NO at P( I.e,it divides the line NO in two parts. That is, NP is not equal toPO  because the triangle is not an issoceles triangle. Bisection theorem states that; MN/MO = NP/PO Let us assume that,; NP=x and PO=y from the question ,MN=6, MO=4 and NO=12 substitute d values; 6/4=x/y ...... crossmultiplying and solving for y(because we were asked to find the value of NP,which we assumed it to be, x), u get y=4x/6.....equation 1 From the triangle, NP+PO=NO ( x +y=12) then, x+y=12.......equation2 substitute 4x/6,for y in equation 2. x+y=12 x+4x/6 = 12 multiply both sides by 6 6x+4x=72 10x=72 divide both sides by 10 Hence, x= NP=7.2 
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