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Who Can Solve These?? - Education - Nairaland

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Who Can Solve These?? by simiife: 8:04pm On Oct 10, 2020
I need someone to solve these math's questions

Re: Who Can Solve These?? by NairalandSARS: 8:19pm On Oct 10, 2020
simiife:
I need someone to solve these math's questions
Question in pic makes no sense.
80cm vs 14cm?
Re: Who Can Solve These?? by Spartancosta(m): 10:09pm On Oct 10, 2020
simiife:
I need someone to solve these math's questions
18
6!/2!=6*5*4*3*2*1/2*1=360ways
19.
Increase in radius dr/dt = 0.5
Area of the circular disc = πr
Increase in area: dA/dr = 2πr
Rate of increase in area: dA/dt = dA/dr * dr/dt
when r = 6cm
= 2πr * 0.5
= 2 * π * 6 * 0.5
2 * π * 6 * / = 6 π cm /s
Re: Who Can Solve These?? by simiife: 10:19pm On Oct 10, 2020
Spartancosta:

18
6!/2!=6*5*4*3*2*1/2*1=360ways
19.
Increase in radius dr/dt = 0.5
Area of the circular disc = πr
Increase in area: dA/dr = 2πr
Rate of increase in area: dA/dt = dA/dr * dr/dt
when r = 6cm
= 2πr * 0.5
= 2 * π * 6 * 0.5
2 * π * 6 * / = 6 π cm /s

Thank you very much sir, I still have more tho
Re: Who Can Solve These?? by Spartancosta(m): 10:23pm On Oct 10, 2020
simiife:
I need someone to solve these math's questions
17.
tree's height =man's height + distance of the man's head to the bird
distance of the man's height to the bird=
/|
/ |
/__ |
the hypotenuse =25
opposite=height=x
@=30°
sin@=opp/hyp
sin30=x/25
x=25sin30
x=25/2
height of the tree =25/2+1.7=14.2
Re: Who Can Solve These?? by Spartancosta(m): 10:25pm On Oct 10, 2020
simiife:

Thank you very much sir, I still have more tho
sir? I'm a very young boy.post the questions,I will try to solve them if I can.
Re: Who Can Solve These?? by simiife: 10:52pm On Oct 10, 2020
Spartancosta:

sir? I'm a very young boy.post the questions,I will try to solve them if I can.


You are the real MVP

Re: Who Can Solve These?? by simiife: 10:54pm On Oct 10, 2020
Spartancosta:

sir? I'm a very young boy.post the questions,I will try to solve them if I can.


Here

Re: Who Can Solve These?? by simiife: 10:58pm On Oct 10, 2020
S

Re: Who Can Solve These?? by simiife: 11:01pm On Oct 10, 2020
W

Re: Who Can Solve These?? by Spartancosta(m): 11:03pm On Oct 10, 2020
simiife:


Here
will upload pics of the cone probt tomorrow r=d/2 r=10/2=5cm l²=h²+r l²=12²+5² l²=144+25 l²=169 l²=13² l=13 curved surface area =πrl π*5*13=65πcm²
Re: Who Can Solve These?? by Spartancosta(m): 11:13pm On Oct 10, 2020
simiife:


Here
2+x-x² differentiating 1-2x=0 1=2x x=1/2 13 + 24 =41(all in base m) 1*m¹+3*m° +2*m¹+4*m°=4*m¹+1*m° m°=1 m+3+2m+4=4m+1 3m+7=4m+1 7-1=4m-3m 6=m m=6
Re: Who Can Solve These?? by Tohsynetita1: 11:13pm On Oct 10, 2020
simiife:
I need someone to solve these math's questions
post the rest
Re: Who Can Solve These?? by Spartancosta(m): 11:14pm On Oct 10, 2020
simiife:



Here
you can do justice to the fraction question by applying the rules of bodmas or better still use the calculator

1 Like

Re: Who Can Solve These?? by Spartancosta(m): 11:20pm On Oct 10, 2020
simiife:


Here
the answer to the fraction question is 1 11/60

1 Like

Re: Who Can Solve These?? by Spartancosta(m): 11:33pm On Oct 10, 2020
simiife:
S
6x³-5x²+1/3x² 6x³/3x² -5x²/3x² +1/3x² 2x-5/3+1/3x² 2x-5/3+3x^-2 differentiating dy/dx=2+1/3(-2)(x^-3) =2+(-2/3(x^-3)) =2-(2/3)x^-3
Re: Who Can Solve These?? by Spartancosta(m): 11:34pm On Oct 10, 2020
Spartancosta:
6x³-5x²+1/3x² 6x³/3x² -5x²/3x² +1/3x² 2x-5/3+1/3x² 2x-5/3+3x^-2 differentiating dy/dx=2+1/3(-2)(x^-3) =2+(-2/3(x^-3)) =2-(2/3)x^-3
omo my eyes don dey close
Re: Who Can Solve These?? by simiife: 11:42pm On Oct 10, 2020
Spartancosta:

will upload pics of the cone probt tomorrow
r=d/2
r=10/2=5cm
l²=h²+r
l²=12²+5²
l²=144+25
l²=169
l²=13²
l=13
curved surface area =πrl
π*5*13=65πcm²

No qualms
Re: Who Can Solve These?? by Spartancosta(m): 11:43pm On Oct 10, 2020
The equation is y =mx + c m is the slope = tan 135 = tan45=-1 (y - y¹)/(x - x¹) = m (y-3)/(x-2)=-1 y - 3 = -(x - 2) y-3=-x+2 y+x=2+3 x+y=5
Re: Who Can Solve These?? by simiife: 11:45pm On Oct 10, 2020
Spartancosta:

omo my eyes don dey close

Pls rest brotherly,but always remember u are the realest MVP
Re: Who Can Solve These?? by Spartancosta(m): 11:50pm On Oct 10, 2020
simiife:

Pls rest brotherly,but always remember u are the realest MVP
I stit dey learn I don solve two more on paper make I quickly type am
Re: Who Can Solve These?? by Spartancosta(m): 12:06am On Oct 11, 2020
simiife:
W
x+2xy+y²+3x+3y-18 x+2xy+y²=(x+y)(x+y) 3x+3y=3(x+y) (x+y)²+3(x+y)-18 comparing with ax²+bx+c where x=(x+y) let z=(x+y) we have z²+3z-18 which can be factored z²-3z+6z-18 z(z-3)-6(z-3) (z-3)(z-6) but z=x+y ((x+y)-3)((x+y)-6) (x+y-3)(x+y-6)
Re: Who Can Solve These?? by Spartancosta(m): 12:27am On Oct 11, 2020
simiife:
W
P
Boy 1 (W=1/2) L(1/3)
boy2 (W=1/3) L(2/3)
boy3 (W=1/4) L(3/4)
probability of only one boy winning only=
probability of boy 1 winning only+ probability of boy 2 winning only+ probability of boy 3 winning only
(1/2 *2/3 *3/4) +(1/2 *1/3*3/4) +(1/2*2/3* 1/4)
=(1/4) +(1/cool+(1/12)
=11/24
Re: Who Can Solve These?? by Spartancosta(m): 12:36am On Oct 11, 2020
simiife:
S
formula for chord =2r * sin@/2 =2(14)*sin60/2 28*sin30 28*0.5 =14
Re: Who Can Solve These?? by simiife: 1:20am On Oct 11, 2020
Spartancosta:

I stit dey learn I don solve two more on paper make I quickly type am

Thanks bro, thank you
Re: Who Can Solve These?? by simiife: 8:54pm On Oct 19, 2020
Spartancosta:

I stit dey learn I don solve two more on paper make I quickly type am

Good evening bro, been busy, would have posted since

Re: Who Can Solve These?? by Spartancosta(m): 3:26am On Oct 20, 2020
simiife:

Good evening bro, been busy, would have posted since
2x-y=4 x+y=2 from x+y=2,x=2-y substituting into 2x-y=4 2(2-y)-y=4 4-4y-y=4 5y=0 y=0 x=2-y x=2 points x,y=(2,0) and (4,3) formula for distance (√((x2-x1)²+(y2-y1)²) x1=2, x2=4 y1=0 y2=3 distance=(√(4-2)²+(3-0)²) =√((2)²+(3)1) =√13
Re: Who Can Solve These?? by Spartancosta(m): 3:31am On Oct 20, 2020
simiife:

Good evening bro, been busy, would have posted since
( (a²-a)C2=(a²-a)C4 let (a²-a)=x xC2=xC4 comparing both sides of the equation, 2 is not equal to 4 so definitely, x=2+4 x=6 (a²-a)=x a²-a=6 a²-a-6=0 a+2a-3a-6=0 a(a+2)-3(a+2)=0 (a-3)(a+2)=0 a=3 or -2 therefore a=3 there is no diagram in the third question
Re: Who Can Solve These?? by Spartancosta(m): 3:33am On Oct 20, 2020
simiife:

Good evening bro, been busy, would have posted since
do justice to the simple interest question using the formula S.I=(PRT)/100 where S.I=interest P=principal R=rate T=time

1 Like

Re: Who Can Solve These?? by simiife: 1:12am On Oct 21, 2020
Spartancosta:

do justice to the simple interest question using the formula
S.I=(PRT)/100
where S.I=interest
P=principal
R=rate
T=time


Got this
Re: Who Can Solve These?? by simiife: 1:36am On Oct 21, 2020
Spartancosta:

do justice to the simple interest question using the formula
S.I=(PRT)/100
where S.I=interest
P=principal
R=rate
T=time

Re: Who Can Solve These?? by Spartancosta(m): 4:41pm On Oct 21, 2020
Sketch a triangle and
place M at the upper
vertex and N , O at the
two vertexes of the base.
Now, if the bisector at
angle M,meets line NO
at P( I.e,it divides the
line NO in two parts.
That is, |NP| is not
equal to|PO | because the
triangle is not an
issoceles triangle.
Bisection theorem states that;
MN/MO = NP/PO
Let us assume that,;
NP=x and PO=y
from the question ,MN=6,
MO=4 and NO=12
substitute d values;
6/4=x/y ......
crossmultiplying and
solving for y(because we were
asked to find the value of
NP,which we assumed it
to be, x), u get
y=4x/6.....equation 1
From the triangle, NP+PO=NO ( x
+y=12)
then,
x+y=12.......equation2
substitute 4x/6,for y in
equation 2.
x+y=12
x+4x/6 = 12
multiply both sides by 6
6x+4x=72
10x=72
divide both sides by 10
Hence, x= NP=7.2

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