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## Who Can Solve These?? - Education - Nairaland

 Who Can Solve These?? by simiife: 8:04pm On Oct 10, 2020 I need someone to solve these math's questions    Re: Who Can Solve These?? by NairalandSARS: 8:19pm On Oct 10, 2020 simiife:I need someone to solve these math's questionsQuestion in pic makes no sense. 80cm vs 14cm? Re: Who Can Solve These?? by Spartancosta(m): 10:09pm On Oct 10, 2020 simiife:I need someone to solve these math's questions186!/2!=6*5*4*3*2*1/2*1=360ways19.Increase in radius dr/dt = 0.5Area of the circular disc = πrIncrease in area: dA/dr = 2πrRate of increase in area: dA/dt = dA/dr * dr/dtwhen r = 6cm= 2πr * 0.5= 2 * π * 6 * 0.52 * π * 6 * / = 6 π cm /s Re: Who Can Solve These?? by simiife: 10:19pm On Oct 10, 2020 Spartancosta:186!/2!=6*5*4*3*2*1/2*1=360ways19.Increase in radius dr/dt = 0.5Area of the circular disc = πrIncrease in area: dA/dr = 2πrRate of increase in area: dA/dt = dA/dr * dr/dtwhen r = 6cm= 2πr * 0.5= 2 * π * 6 * 0.52 * π * 6 * / = 6 π cm /sThank you very much sir, I still have more tho Re: Who Can Solve These?? by Spartancosta(m): 10:23pm On Oct 10, 2020 simiife:I need someone to solve these math's questions17.tree's height =man's height + distance of the man's head to the birddistance of the man's height to the bird= /| / | /__ |the hypotenuse =25opposite=height=x@=30°sin@=opp/hypsin30=x/25x=25sin30x=25/2height of the tree =25/2+1.7=14.2 Re: Who Can Solve These?? by Spartancosta(m): 10:25pm On Oct 10, 2020 simiife: Thank you very much sir, I still have more tho sir? I'm a very young boy.post the questions,I will try to solve them if I can. Re: Who Can Solve These?? by simiife: 10:52pm On Oct 10, 2020 Spartancosta: sir? I'm a very young boy.post the questions,I will try to solve them if I can.You are the real MVP Re: Who Can Solve These?? by simiife: 10:54pm On Oct 10, 2020 Spartancosta: sir? I'm a very young boy.post the questions,I will try to solve them if I can.Here    Re: Who Can Solve These?? by simiife: 10:58pm On Oct 10, 2020 S    Re: Who Can Solve These?? by simiife: 11:01pm On Oct 10, 2020 W    Re: Who Can Solve These?? by Spartancosta(m): 11:03pm On Oct 10, 2020 simiife: Here will upload pics of the cone probt tomorrow r=d/2 r=10/2=5cm l²=h²+r l²=12²+5² l²=144+25 l²=169 l²=13² l=13 curved surface area =πrl π*5*13=65πcm² Re: Who Can Solve These?? by Spartancosta(m): 11:13pm On Oct 10, 2020 simiife: Here 2+x-x² differentiating 1-2x=0 1=2x x=1/2 13 + 24 =41(all in base m) 1*m¹+3*m° +2*m¹+4*m°=4*m¹+1*m° m°=1 m+3+2m+4=4m+1 3m+7=4m+1 7-1=4m-3m 6=m m=6 Re: Who Can Solve These?? by Tohsynetita1: 11:13pm On Oct 10, 2020 simiife:I need someone to solve these math's questionspost the rest Re: Who Can Solve These?? by Spartancosta(m): 11:14pm On Oct 10, 2020 simiife:Hereyou can do justice to the fraction question by applying the rules of bodmas or better still use the calculator 1 Like Re: Who Can Solve These?? by Spartancosta(m): 11:20pm On Oct 10, 2020 simiife: Here the answer to the fraction question is 1 11/60 1 Like Re: Who Can Solve These?? by Spartancosta(m): 11:33pm On Oct 10, 2020 simiife:S 6x³-5x²+1/3x² 6x³/3x² -5x²/3x² +1/3x² 2x-5/3+1/3x² 2x-5/3+3x^-2 differentiating dy/dx=2+1/3(-2)(x^-3) =2+(-2/3(x^-3)) =2-(2/3)x^-3 Re: Who Can Solve These?? by Spartancosta(m): 11:34pm On Oct 10, 2020 Spartancosta: 6x³-5x²+1/3x² 6x³/3x² -5x²/3x² +1/3x² 2x-5/3+1/3x² 2x-5/3+3x^-2 differentiating dy/dx=2+1/3(-2)(x^-3) =2+(-2/3(x^-3)) =2-(2/3)x^-3 omo my eyes don dey close Re: Who Can Solve These?? by simiife: 11:42pm On Oct 10, 2020 Spartancosta: will upload pics of the cone probt tomorrow r=d/2 r=10/2=5cm l²=h²+r l²=12²+5² l²=144+25 l²=169 l²=13² l=13 curved surface area =πrl π*5*13=65πcm²No qualms Re: Who Can Solve These?? by Spartancosta(m): 11:43pm On Oct 10, 2020 The equation is y =mx + c m is the slope = tan 135 = tan45=-1 (y - y¹)/(x - x¹) = m (y-3)/(x-2)=-1 y - 3 = -(x - 2) y-3=-x+2 y+x=2+3 x+y=5 Re: Who Can Solve These?? by simiife: 11:45pm On Oct 10, 2020 Spartancosta: omo my eyes don dey closePls rest brotherly,but always remember u are the realest MVP Re: Who Can Solve These?? by Spartancosta(m): 11:50pm On Oct 10, 2020 simiife: Pls rest brotherly,but always remember u are the realest MVP I stit dey learn I don solve two more on paper make I quickly type am Re: Who Can Solve These?? by Spartancosta(m): 12:06am On Oct 11, 2020 simiife:W x+2xy+y²+3x+3y-18 x+2xy+y²=(x+y)(x+y) 3x+3y=3(x+y) (x+y)²+3(x+y)-18 comparing with ax²+bx+c where x=(x+y) let z=(x+y) we have z²+3z-18 which can be factored z²-3z+6z-18 z(z-3)-6(z-3) (z-3)(z-6) but z=x+y ((x+y)-3)((x+y)-6) (x+y-3)(x+y-6) Re: Who Can Solve These?? by Spartancosta(m): 12:27am On Oct 11, 2020 simiife:WPBoy 1 (W=1/2) L(1/3)boy2 (W=1/3) L(2/3)boy3 (W=1/4) L(3/4)probability of only one boy winning only=probability of boy 1 winning only+ probability of boy 2 winning only+ probability of boy 3 winning only(1/2 *2/3 *3/4) +(1/2 *1/3*3/4) +(1/2*2/3* 1/4)=(1/4) +(1/ +(1/12)=11/24 Re: Who Can Solve These?? by Spartancosta(m): 12:36am On Oct 11, 2020 simiife:S formula for chord =2r * sin@/2 =2(14)*sin60/2 28*sin30 28*0.5 =14 Re: Who Can Solve These?? by simiife: 1:20am On Oct 11, 2020 Spartancosta: I stit dey learn I don solve two more on paper make I quickly type amThanks bro, thank you Re: Who Can Solve These?? by simiife: 8:54pm On Oct 19, 2020 Spartancosta: I stit dey learn I don solve two more on paper make I quickly type amGood evening bro, been busy, would have posted since    Re: Who Can Solve These?? by Spartancosta(m): 3:26am On Oct 20, 2020 simiife: Good evening bro, been busy, would have posted since 2x-y=4 x+y=2 from x+y=2,x=2-y substituting into 2x-y=4 2(2-y)-y=4 4-4y-y=4 5y=0 y=0 x=2-y x=2 points x,y=(2,0) and (4,3) formula for distance (√((x2-x1)²+(y2-y1)²) x1=2, x2=4 y1=0 y2=3 distance=(√(4-2)²+(3-0)²) =√((2)²+(3)1) =√13 Re: Who Can Solve These?? by Spartancosta(m): 3:31am On Oct 20, 2020 simiife: Good evening bro, been busy, would have posted since( (a²-a)C2=(a²-a)C4 let (a²-a)=x xC2=xC4 comparing both sides of the equation, 2 is not equal to 4 so definitely, x=2+4 x=6 (a²-a)=x a²-a=6 a²-a-6=0 a+2a-3a-6=0 a(a+2)-3(a+2)=0 (a-3)(a+2)=0 a=3 or -2 therefore a=3 there is no diagram in the third question Re: Who Can Solve These?? by Spartancosta(m): 3:33am On Oct 20, 2020 simiife: Good evening bro, been busy, would have posted since do justice to the simple interest question using the formula S.I=(PRT)/100 where S.I=interest P=principal R=rate T=time 1 Like Re: Who Can Solve These?? by simiife: 1:12am On Oct 21, 2020 Spartancosta: do justice to the simple interest question using the formula S.I=(PRT)/100 where S.I=interest P=principal R=rate T=timeGot this Re: Who Can Solve These?? by simiife: 1:36am On Oct 21, 2020 Spartancosta: do justice to the simple interest question using the formula S.I=(PRT)/100 where S.I=interest P=principal R=rate T=time    Re: Who Can Solve These?? by Spartancosta(m): 4:41pm On Oct 21, 2020 Sketch a triangle and place M at the upper vertex and N , O at the two vertexes of the base. Now, if the bisector at angle M,meets line NO at P( I.e,it divides the line NO in two parts. That is, |NP| is not equal to|PO | because the triangle is not an issoceles triangle. Bisection theorem states that; MN/MO = NP/PO Let us assume that,; NP=x and PO=y from the question ,MN=6, MO=4 and NO=12 substitute d values; 6/4=x/y ...... crossmultiplying and solving for y(because we were asked to find the value of NP,which we assumed it to be, x), u get y=4x/6.....equation 1 From the triangle, NP+PO=NO ( x +y=12) then, x+y=12.......equation2 substitute 4x/6,for y in equation 2. x+y=12 x+4x/6 = 12 multiply both sides by 6 6x+4x=72 10x=72 divide both sides by 10 Hence, x= NP=7.2