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Solve The Fizz - Buzz Hackerrank Challenge In Both Java And Javascript - Programming - Nairaland

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Solve The Fizz - Buzz Hackerrank Challenge In Both Java And Javascript by kemi72: 4:24pm On Nov 18, 2023
Solve the fizzbuzz hackerrank challenge question:

Given a number n, for each integer i in the range from 1 to n inclusive, print out one value per line as follows:

if i is a multiple of both 3 and 5, print FizzBuzz
if i is a multiple of 3(but not 5), print Fizz
if i is a multiple of 5(but not 3), print Buzz
if i is not a multiple of 3 or 5, print the value of i
Java Solution
import java.io.*;
import java.math.*;
import java.security.*;
import java.text.*;
import java.util.*;
import java.util.concurrent.*;
import java.util.function.*;
import java.util.regex.*;
import java.util.stream.*;
import static java.util.stream.Collectors.joining;
import static java.util.stream.Collectors.toList;



class Result {

/*
* Complete the 'fizzBuzz' function below.
*
* The function accepts INTEGER n as parameter.
*/

public static void fizzBuzz(int n) {
for(int i=1; i<=n; i++){
if(i%3 == 0 && i%5 == 0){
System.out.println("FizzBuzz"wink;
}else if(i%3 == 0){
System.out.println("Fizz"wink;
}else if(i%5 == 0){
System.out.println("Buzz"wink;
}else{
System.out.println(i);
}
}
}

}

public class Solution {
public static void main(String[] args) throws IOException {
BufferedReader bufferedReader = new BufferedReader(new InputStreamReader(System.in));

int n = Integer.parseInt(bufferedReader.readLine().trim());

Result.fizzBuzz(n);

bufferedReader.close();
}
}

Read more for Javascript solution: https://codeflarelimited.com/blog/fizzbuzz-hackerrank-challenge/

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