Drop any question ayou find difficult or assignment dat u ave tried that u find difficult on these topics 1.Logarithms 2.Set 3.Mensuration(areas,volume,latitude and longitude e.t.c) 4.Word problem 5.Commercial maths 6.statistics 7.probabibility 8.All form of algebra 9.permutation and combination 10.Bearing 11.matrices 12.differencial calculus 13.Linear sequence 14.Indices and surd 15.Base form 16.polymomial 17.partial fraction 18.compound angle 19.geometry and trigonometry identity and any other pure maths ...others like graph,loci,circle geometry and construction cannot be solve here

MY PROJECT SUPERVISOR GAVE ME THIS TRIG PROBLEM TO SOLVE AS THIS WILL SERVE AS A GREATER EFFORT IN CONCLUDING MY PROJECT WITH HIM. THE QUESTION GOES THUS:USING THE TRIG IDENTITY COS3THETA=4COS^3THETA-3COSTHETA,EXPRESS COSTHETA AS A FUNCTION OF COS3THETA I.E COSTHETA=F(COS3THETA) EXPLICITLY. THANKS AND GOD BLESS

sagbar: MY PROJECT SUPERVISOR GAVE ME THIS TRIG PROBLEM TO SOLVE AS THIS WILL SERVE AS A GREATER EFFORT IN CONCLUDING MY PROJECT WITH HIM. THE QUESTION GOES THUS:USING THE TRIG IDENTITY COS3THETA=4COS^3THETA-3COSTHETA,EXPRESS COSTHETA AS A FUNCTION OF COS3THETA I.E COSTHETA=F(COS3THETA) EXPLICITLY. THANKS AND GOD BLESS

Now let '@' be theta....Cos3@=cos(@+2@), cos3@=cos@cos2@-sin@sin2@..{remember dat in trig identity cos2@ is 2cos^2@ and sin2@ is 2sin@cos@ and sin^2@ is 1-cos^2@} now continuation..cos3@=cos@(2cos^2@-1)-sin@(2sin@cos@), cos3@=cos@(2cos^2@-1)-2sin^2@cos@, cos3@=cos@(2cos^2@-1)-2(1-cos^2@)cos@, cos3@=cos@(2cos^2@-1)-2(cos@-cos^3@), cos3@=2cos^3@-cos-2cos@+2cos^3@, cos3@= 4cos^3@-3cos@ NOTE:Where cos3@ starts begin 4rm another line it be vertical....It's right if i really understand ur question.

pls check out dis New Question- What is the solution set for the equation |2x-3|=13.
A. (5, B.(-5, C. (-5,- D. (5,-

pls check out dis New Question- What is the solution set for the equation |2x-3|=13.

@Joshua,reframe d question..but if d que is like this (2x-3)=13....2x=3+13..... 2x=16.....x=8..but it's too simple,that is why i said reframe it.

Pls help me with dis: The quadratic equation whose roots are 1-113 and 1+113 is
a. X^2 +11x + 1= 0
b. X^2 - 2x +12 = 0
c. 1+ 2x + 12 = 0
d. X^2 -2x -12= 0

Emma_esty: Pls help me with dis: The quadratic equation whose roots are 1-113 and 1+113 is
a. X^2 +11x + 1= 0
b. X^2 - 2x +12 = 0
c. 1+ 2x + 12 = 0
d. X^2 -2x -12= 0

So let this_/ serve as our square root..If the root of the equation is 1+_/13 and 1+_/13 if i guess what u have written right...SO {x-(1+_/13)}{x-(1-_/13)}=(x-1-_/13)(x-1+_/13)..now by multiplying each of content in the first bracket by the whole second brack,like this...=x(x-1+_/13)-1(x-1+_/13)-_/13(x-1+_/13)=x^2-x+x_/13-x+1-_/13-x_/13+_/13-13...as you can se some will cancel out to give us zero e.g[x_/13-x_/13 and-_/13+_/13]..so it is a bit simplified to give us x^2-x-x+1-13=x^2-2x-12....So the answer is 'd' ...note the signs and square root and don't mix it up,nd if u want to write it down,make sure equals to sign = starts the next line.

Wemmy6284: So let this_/ serve as our square root..If the root of the equation is 1+_/13 and 1+_/13 if i guess what u have written right...SO {x-(1+_/13)}{x-(1-_/13)}=(x-1-_/13)(x-1+_/13)..now by multiplying each of content in the first bracket by the whole second brack,like this...=x(x-1+_/13)-1(x-1+_/13)-_/13(x-1+_/13)=x^2-x+x_/13-x+1-_/13-x_/13+_/13-13...as you can se some will cancel out to give us zero e.g[x_/13-x_/13 and-_/13+_/13]..so it is a bit simplified to give us x^2-x-x+1-13=x^2-2x-12....So the answer is 'd' ...note the signs and square root and don't mix it up,nd if u want to write it down,make sure equals to sign = starts the next line.

wow!! I'm lost ooo. . .

Where?

check dis solve for 0<or=x<or=360
sin2x=cosx

Michelle22: check dis solve for 0<or=x<or=360
sin2x=cosx

In ur trig identity sin2x=2sinxcosx so put it where you see sin2x...2sinxcosx=cosx...so divide both sides by cosx and cosx will cancel out to give 2sinxcosx/cosx=cosx/cosx...2sinx=1...sinx=1/2...sinx=0.5...x=sin inverse or arc sin 0.5.....x=30 or 150(degree) ...since it should be less between 0 and 360...So the answer is 30 or 150(in degrees

attention needed here:

https://www.nairaland.com/886908/pls-need-help-solving-this/3

Wemmy6284: Where?

From the beginning

This should be easy 4 d braniacs here, what is the total surface area of pyramid and prism fastest person 2 answer gets credit!

Lucario007: This should be easy 4 d braniacs here, what is the total surface area of pyramid and prism fastest person 2 answer gets credit!

For prism u need to be specific,there are triangular prism,rectangular prism but generally surface area is crossectional areas * depth(height)... For pyramid since it's not volume,the surface area is complicated it has no general specific formula but u have to work it out based on the question.

@lucario007 jst lyk my bro wemmy said. No singular formulae exit for determining the total surface area of a prism and that of a pyramid.
For prism in general, the total surface area=sum of the areas of al d surfaces.
Likwise for pyramid, the total surface area of a pyramid=Area of base+sum of areas of the triangular faces. N.B (a pyramid has a number of the triangular faces depending on the shape of the base. Eg a square base pyramid has 4 triangular faces)
PEACE

A workout 4 guys on this tread.
If m:n=2:3, u:v=4:5 and m-u:n+v=2:5, find the ratio m+10u:2n-5v

Johncasey did u saw my message.

Yes bro, sori i saw it late, tanks.. Check ur e-mail

pls check out dis New Question- What is the solution set for the equation |2x-3|=13.
A. (5, B.(-5, C. (-5,- D. (5,


Ans.=8

purplekayc: pls check out dis New Question- What is the solution set for the equation |2x-3|=13.
A. (5, B.(-5, C. (-5,- D. (5,


Ans.=8

The answer is 8 or -5 since the left hand side equation is in modulo

Hello my maths gurus...pls,let's keep the thread moving...a tree can never make a forest

Johncasey: A workout 4 guys on this tread.
If m:n=2:3, u:v=4:5 and m-u:n+v=2:5, find the ratio m+10u:2n-5v

3:1

Hmmmmm

Wemmy6284:
Drop any question ayou find difficult or assignment dat u ave tried that u find difficult on these topics 1.Logarithms 2.Set 3.Mensuration(areas,volume,latitude and longitude e.t.c) 4.Word problem 5.Commercial maths 6.statistics 7.probabibility 8.All form of algebra 9.permutation and combination 10.Bearing 11.matrices 12.differencial calculus 13.Linear sequence 14.Indices and surd 15.Base form 16.polymomial 17.partial fraction 18.compound angle 19.geometry and trigonometry identity and any other pure maths ...others like graph,loci,circle geometry and construction cannot be solve here

Any Mathematician in the house to help me with this maths i saw in FAAN test.

x+y=10
2x+2y=20

dbestuncle:

Any Mathematician in the house to help me with this maths i saw in FAAN test.

x+y=10
2x+2y=20

This is weird.

MaxGraviton:


This is weird.

Find X and Y.
Ans: X=5, Y=5.

Slot in the values into the equation and you will see ur answers.

dbestuncle:

Any Mathematician in the house to help me with this maths i saw in FAAN test.

x+y=10
2x+2y=20

Find X and Y.
Ans: X=5, Y=5.

Slot in the values into the equation and you will see ur answers.

pls slot in 4 and 6, 2 and 8, 3 and 7, 1 and 9, 5 and 5.

c wat the above givs to u.thanx 4 trying

kunleakin:




Find X and Y.
Ans: X=5, Y=5.

Slot in the values into the equation and you will see ur answers.