₦airaland Forum

afo7219:
the answer is 19 students

explanation to the answer.
Universal set 68
H= 25
M=25
E=34
HnMnE= 3
Using Venn diagram
25+25+34-x-y-z+3=68
X+y+z= 87-68= 19
Where x,y,z are those doing exactly two subjects

Fela40:
brilliant Mehn.

lol... This is your first attempt I guess.

This last question is for you alone.

In a group of 68 students, each student is registered for at least one of three classes - History, Math and English. Twenty-five students are registered for History, twenty-five students are registered for Math, and thirty-four students are registered for English. If only three students are registered for all three classes, how many students are registered for exactly two classes?

the answer is 19 students

Fela40:
Attempt this last one...

Both answers are correct, but I assume I didn't give you a unique one to answer.

Indian restaurant has 60% of spicy dishes in the menu and the rest are non-spicy. Analysis shown that in 2016 75% of the spicy dishes were profitable, but 75% of the non-spicy dishes were unprofitable. If the restaurant has a total of 40 dishes, and broke even on none of them, how many of their dishes were profitable?

.75×.6×40=18
Ans = 18 dishes profitable

Fela40:
Correct!!!

Attempt this one as your second question

During 2015, a plant delivers an average of 2,000 cars per month. How many cars will the plant need to produce from 2016 through 2018 in order to increase its monthly average for the period from 2015 through 2018 by 200% over its 2015 average?

2016 to 2018= 3years.
Yearly average production 2000
% increase 200%
Therefore prod = 200% of 2000= 4000
No of years is 3 so 3× 4000= 12,000 cars
Ans 12,000 cars

Gain =96-80=16
Loss =120-96=24
Therefore overall loss in the transaction is equally to$8
Ans= $8

Question 1 solution:
For gain 120/100×96=115.20(selling price)
For loss 80/100×96=76.8(selling price)
Therefore,
115.2-96=19.2gain
96-76.8=19.2 loss
The answer is NIL no gain no loss
Mistake

labodinho:
they used post utme screening... written exam, cbt

15 maths, 15 english and 10 general paper.
datz 40 questions - 30

jamb/8 + ur post utme*2.5 = aggregate

don't really get it. Which one is 30 and 2.5 .pls explain abeg

davbravo:
So it's official



The Federal Government has lifted the ban on the controversial examinations usually organised by universities in Nigeria for admission seekers after the Unified Tertiary Matriculation Examinations (UTME).
The Federal Government had last year ordered the scrapping of post-UTME for candidates.Speaking in an exclusive interview with The Guardian in Abuja yesterday, the Minister of Education, Malam Adamu Adamu, said universities could now organise post-UTME as a pre-condition to gaining admission into universities in the country.
The minister, who however urged university authorities to make the fees for the screening affordable and not to impose huge financial burden on the parents, said: “We are going to allow universities to organise post-UTME if they want.
“We have asked them not to impose huge financial burden on the parents. The burden should not be more than what they can bear.”Adamu said that the Federal Government had stopped the scrapping of the examination to fully understand what was going on in universities, adding: “We are now wiser.”
The minister, who expressed confidence in the examination conducted by the Joint Admissions and Matriculation Board (JAMB), said the management of JAMB had remitted N5 billion to the Federal Government coffers, which happens to be the highest so far in the last 40 years of the board’s existence.
He said: “Since JAMB was established more than 40 years ago, the total amount it has given government was N200 million, but in one year, Prof. Ishaq Oloyede has remitted N5 billion to government.
“The new JAMB registrar has been correcting many anomalies in the board. Within a year, he has been able to stop all the untold things that were happening there.

how official is this "its official" post cos I have search n search every nook n cranny( newspapers et all) to get d news but to no avail except this blog post. Pls endeavor to quote d source.

blessedvisky:
How can I get such score Pls. I really need advice from experience people

which other experience person do u want to respond to ur query. @ibadanfinest is more than experience.

THEPOTTER:
I have the newly updated requirements of unilag admission

share it pls

45

ChucE:
Using bodmas, you solve the bracket first
= (6-7+4)=-1+4=3
Now we multiply
=2(3)*2=6*2=12
Now division comes in
=12/12=1
Therefore answer=C=1

oga , division comes b4 multiplication

Ekakamba:
Show workings

12÷2(6-7+4)×2
Applying bodmas
(6-7+4)=6+4-7=3
12÷2x3×2
12÷2=6
Therefore 6×3×2=36
Ans 36(A)

A. The relative pronoun'who' refers to d woman which is singular so we have singular verb' sells'

Next question pls

MrOlai:
What's your number?

Let me give you #400 MTN.

Manage it pls.

pls remember me too o
My Mtn no: 08037230350

MasterMind21:
Sorry for taking so long. I used 12th degree of the binomial theorem(pascal's triangle). Hope you know about it. If we expand
(x +y)¹... It equals x + y (their coefficients being 1 and 1)
(x + y)²... You'll get coefficients of 1 2 1
(x + y)³ gives...... 1 3 3 1
(x + y)⁴ gives.... 1 4 6 4 1
Now, if you look closely you'll notice that the sum of two consecutive coefficients of the previous degree gives the value of the coefficient of the corresponding next degree.
For example in degree 1, we have, 1 & 1(I want to obtain degree 2 coefficients from 1). We take it that zero(imaginary) is standing by the left side of the first 1.. So 0 + 1 = 1 (first coefficient of degree 2)... 1 + 1 = 2 (second coefficient of degree 2)... 1 + 0 (by the right of the second 1)... That's it 1 2 1...
Let me try to get degree 3 from 2..
Recall two is 1 2 1... Now 0 + 1= 1(first coefficient of degree 3). 1 + 2 =3(second coefficient of degree 3)...2 + 1 (by the left of 2)= 3(third coefficient and second 3 of degree 3).... 1 + 0= 1(last coefficient). So with this you'll be able to get the coefficient of any degree you want.
N. B The first and last coefficients are always the same i.e 1. You should also put the powers(degrees) of variables into consideration.
If I expand (x + y)³ I'll get(using the coefficients 1 3 3 1)... 1x³ +3x²y¹ + 3x¹y² + 1y³ which can be simplified to x³ + 3x²y + 3xy² + y³... If you look at the powers of the respective variables you'll notice that the sum of indices will always be equal to the degree(i.e in this case 3).
See....x³(total 3), 3(x²y)(total 2+1=3), 3(xy²) (total 1+2=3).....including that of y³.. Sorry for the long story.. I hope this'll do.. Thanks.

yea. Tanks alot

Next question sir

MasterMind21:
495 X 3⁴ X 2^8 = 10264320

pls, step by step sir

MrOlai:
Find the term independent of x in the expansion of

(3x² - 2/x)¹²

(3x)^12 -(2)^12
Independent of x
The ans= 2^12

Next question pls

MrOlai:
Correct!

hello sir,if u wish to give me recharge card, I will appreciate too o at least one question rite. Jus to encourage a learner like me cos I knw u guys are gurus. I use Mtn network if u wish to give or u can transfer d money's worth to my acc . tanks in anticipation. God bless u.

MasterMind21:
33

u must b a mathematician. Kudos to you. Can pls always endeavour to show ur workings so DAT som1 like me can gain n add more knowledge.

No of people 21

MrOlai:
Ok

next question sir. Even if u no give me recharge card I no mind

Next question pls

13th term is 51

21

Tank 0

(3a+9b)(7a-b)

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