₦airaland Forum

please eh, I got some PDF on python, Buh don know how to study, can any one tell me how to study programming languages

Thanks ooh I will send more questions

doggedemmy:
The salary in 1975, 1976, 1977... will form a GP with a = 2000, r = 1.1 (2000, 2200, 2420, 2662...)

Sum of the terms from 1775 to 1984 (ten years, since both years are inclusive)
So n = 10. S = a(r^n-1)/r-1
S = 2000 (1.1^9 - 1)/(1.1-1)
= N27158.95

A mans salary in 1975 was N2000.00 per year and it increased by 10% each year. Find how much he earned in the years up to 1984 both years inclusive, please help , word problems on sequence and series

mathefaro:
for any G.P, the common ratio is given as T(n+1)/T(n) I.e
r = T2/T1 = T3/T2 = T4/53 = . . .
In this particular case, r = m/(4/3) = 1/m = n/1
The equality that concerns us is the last one
1/m = n/1
From which cross multiplication gives the product mn = 1

thanks sir

``If 4/3, m,1,n....... Is GP, the product of m and n is ? I just need the workings ooh