₦airaland Forum

Itz true bt nt applicable,unda mechinez mechanical advantage z blievd to be independent of load,nd we all knw dat they r linked by direct proportn.also elasticity,youngz modulus z believd to be independent on any of itz parameterz bt yet it increases as the stress.datz y physcz z sumhw intricate

emmyeuler1: but emf=Ir+V....which shows direct proportion between emf and internal resistance

I mean c

emmyeuler1: I DONT KNOW IT...BUT THE ANS IS B

Hmm,u tried 4dat...it depndz only on da electrod material

emmyeuler1: I DONT KNOW IT...BUT THE ANS IS B

Da emf of a cell depends on da followni)chargez (ii)electrodz (iii) internal resistnce (iv)concentratn of electrolyt. A ii iii & iv b. iii c.ii d.all

Yeah,absolutely correct!

emmyeuler1: K.....SINCE THERE ARE 2 PARTICLES INVOLVED N=2....R.M.S VELOCITY=SQRT[3PV/NM]=SQRT((3*30*10)/2*2)=15m/s

Ah,if u wld b good at physcz nko?u wil nw bcom a physcz wizard.u missd out da number of particlez(N),den itz done.wizard 2be!u r 2gud.

emmyeuler1: broda please help me because i am not good in physics............ Root mean squared velocity=sqrt(3pv/m)=sqrt[(3*30*10)/2]=21.13m/s

F-mgsin@=ma,then afta doubld it bcmz 2f-mgsin@=ma,sinc a2=(2f/m)-(mgsin@)/m,nd a1=(f/m)-(mgsin@/m),a2/a1 z nw equal to [2(f-mgsin@)/f-mgsin@] + [mgsin@/f-mgsin@]=2 +[mgsin@/f-mgsin@],hence a2>2a1

buzyguy: Sum1 try ds:a crate which z pulld up a smooth inclined plane with a force F moves up the plane with an acceleratn of a.if F z doubld,the acceleratn,a.is quadrupld b.more than doubld c.doubld d.lez dan doubld

buzyguy: Sum1 try ds:a crate which z pulld up a smooth inclined plane with a force F moves up the plane with an acceleratn of a.if F z doubld,the acceleratn,a.is quadrupld b.more than doubld c.doubld d.lez dan doubld

F=m1 *m2,direct proportn.then,m=dv,densistity timez volume.wit da density sam,da volume z equal to r^3.if r z nw doubld ,(2r)^3 wich z equal to 8r^3 separatly for da two bodiez.so far m z directly proportnal to r^3,then m 1* m2=8r^3 * 8r^3,so increasez by a factor 64

buzyguy: The gravitational force of attractn btwn two spherical bodiez having equal densities is increasd or decreasd by a factor of what if the radius of each body z doubled,a.increasd by 4 b.increasd by 64 c.decreasd by 4 d.decreasd by 2

Two particlez each of mass 2kg collide with 10N/m^2 occupiez a volume of 30m^3.calculate the rms value of their velocitiez in m/s.

Vry correct

snave007: (a)+/- 2mm

Correct

emmyeuler1: ....the answer is (A)....50/SIN15

A force of 100N is used to push a body up a plane inclined at an angle 15deg. To the horizontal.if one-half of da work done by the force is used to overcom frictn,the weight of the body in newtonz is,a.50/sin15deg. B.50sin15deg. C.100/sin15deg. D.100sin15deg.

Hmm,chck da questn wel.

joseboy199: C..
@All gudmrnin

Vry correct

emmyeuler1: ....+-2mm(ans A)

Apy sundae nd nw wk,scnd to last wk of xam.success z ourz ijn

Morin 2evrybdy

The gravitational force of attractn btwn two spherical bodiez having equal densities is increasd or decreasd by a factor of what if the radius of each body z doubled,a.increasd by 4 b.increasd by 64 c.decreasd by 4 d.decreasd by 2

Anoda:a student measurez the internal nd external diameter of a cylindrical vessel as 100(+-1)mm nd 104(+-1)mm respectivly.the possible error in the determinatn of the thicknez of the vessel is,a.+-2mm b.+-1mm c.+-0.5mm d.0 +- means pluz or minuz.

Oh,thks alot av really 4gottn

joseboy199: try again by usin echo 4mula,cuz of d word reflection

Yes nw,we av to aim far above 300,nd i bliev God wil surely do it 4us ijn

joseboy199: Tenx a lot bro...cuz i want high jamb score,i dnt want 2 joke wit even d simplest questn,,,

I wil fnd and chck,bt if itz sam questn dat means da both txts r wrng

emmyeuler1: Mr buzy what u did wasnt correct...check page 192,example 7.9 in m.w anyakoha for more clarification

Oh,thks i wz tryn to convert it to m nt cm

joseboy199: U tried...v/f=landa,20/10=2cm
dist btw adjacent node z 1/2landa
whr landa=2,dist btw adjacent node =2/2=1cm
@Emmeur wic phy6 txt buk r u usin

I use all txt i see cuz i normally borrow,i only av new skl nd essential physics.atimes nekson nd parka,bt nt dat useful anywy cuz we r dealn wit jamb.

joseboy199: @buzyguy wic txt buk r u using,or is past questn u r usin 2 set d questns

D=vt=4 *10^-3 * 3 * 10^-3=12 * 10^-6m

joseboy199: The wavelength of a stationary wave z 36.0cm.what z d distance btw a node n d nxt anti-node
2)A wave of frequency 10HZ forms a stationary wave pattern in a medium whr d velocity is 20cm/s.d distance btw d adjacent node z
3)radio waves emitted 4rm an antenna are pickd up by a radar afta reflection 4rm an aircraft in 4*10^-3s.how far is d aircraft 4rm d antenna(v=3*10^3m/s)

(2)0.2/10=v/f=landa=0.02cm,distnc btwn adjacent node z 1/2landa =0.02/2=0.01cm

joseboy199: The wavelength of a stationary wave z 36.0cm.what z d distance btw a node n d nxt anti-node
2)A wave of frequency 10HZ forms a stationary wave pattern in a medium whr d velocity is 20cm/s.d distance btw d adjacent node z
3)radio waves emitted 4rm an antenna are pickd up by a radar afta reflection 4rm an aircraft in 4*10^-3s.how far is d aircraft 4rm d antenna(v=3*10^3m/s)

(A)36/4=9cm

joseboy199: The wavelength of a stationary wave z 36.0cm.what z d distance btw a node n d nxt anti-node
2)A wave of frequency 10HZ forms a stationary wave pattern in a medium whr d velocity is 20cm/s.d distance btw d adjacent node z
3)radio waves emitted 4rm an antenna are pickd up by a radar afta reflection 4rm an aircraft in 4*10^-3s.how far is d aircraft 4rm d antenna(v=3*10^3m/s)

Datz vry correct!

joseboy199: Workdone in a string=average force*extension
therefore,average force=180+100/2=280/2=140N,extension=10cm=0.1m
workdone=140*0.1=14j

Bt u typd 2secs instead ov 2.2secs

joseboy199: Initial dist 4rm clif x1=412.5,final dist=x2,echo time t=2.2s.sound speed v=330m/s
x2=vt/c,330*2.2/2=363
dist moved toward cliff,x=x1-x2=412.5-363=49.5m

Anoda:as the tension in an elastic string is increased frm 100N to 180N,the string extends by 10cm.the workdone in the string z,a.8j b.10j c.14j d.18j

Una wldne,correct!

emmyeuler1: % OF original potential energy lost as heat=(100m/300m)*100=33.3%....ans(A)

U ve 4gottn dat da speed in organ pipes z constant

joseboy199: Ans z c