Codelove's Posts
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i am developing a comment box with php and mysql,but my problem now is how to post the comment after user has enter their comment.so far i my php and mysql that save the comment in the database,but i want it to be visible on my webpage after it is save to database,i don't know the code for that,i need help. [CODE] <!DOCTYPE html> <html> <head> <title> commenting system </title> </head> <body> <form action = "cm.php" method = "POST"> <input type = "text" name = "fname" placeholder = "Name"><br><br> <input type = "text" name = "website" placeholder = "website"><br><br> <textarea type = "text" name = "scomment" rows = "6" col = "250" placeholder = "comment here...."> </textarea> <button type = "submit">SUBMIT</button> </form> </body> </html> cm.php <?php include 'db.php'; $fname = $_POST['fname']; $website = $_POST['website']; $scomment = $_POST['scomment']; $sql = "INSERT INTO client (fname, website, comment) VALUES ('$fname', '$website', '$scomment')"; $result = $con->query($sql); header("Location:index.php" ;?> db.php <?php $con = mysqli_connect("localhost", "root", "", "comment" ;if(!$con){ die("connection error".mysqli_connect_error()); } [/CODE] |
please i have a problem,i create new input field when a button is click,but i want each of the new create field to have a unique id,so i can use it for calculation in javascript. function create(){ var newinput = document.createElement('input'); newinput.placeholder = "test1"; document.getElementById("mytest" .appendChild(newinput);} |
please i have a website and i want to link a facebook icon to my web page in facebook and also add a share and like button but i don't know how to go about it i need help. |
thanks it worked as i wanted. |
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