₦airaland Forum

Richiez: @ chibuzor you are doing a very good job by keeping the thread lively...keep it up

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Chairman, its all you o.... @ur signature... na Abuja u dey?

Like a previous poster said, the sex gan itself na crap, joblessness dey worry ethiopian lawyers, make dem go run for iaaf...

johnpaul1101: Salute to everyone.
Plz help me make t the subject from:
s=ut+1/2*at^2

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Busy right now, I woulda attempted it myself, I ll tell you how to go about it tho..
Bring the S to the other side of the equation, and find a way to eliminate the .5 in at² . The equation should then have a form : at² + 2ut - 2s = 0 .. This is a classic quadratic equation... (Use Almighty Formula) and t will now equal to
-2u +/- sqrt ( {2u}² - 4 (a)(-2s) all over 2a ...Got it?

doubleDx: Yeah, I was able to download it. Here is it, you can download it here if the other link isn't working...interesting stuff!

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I dey tell you, So interesting to the point that I was reading just a page for 10mins...

Those posters u uploaded have been in abuja since 2months ago... If u go to A.Y.A under the bridge u ll see them there all tattered and old......

[quote author=Calculusf(x)]...how do you expect me to solve what guru like you doesn't know bro...i don't know it...but i promise you that immediately i will post it here...coz i have asked my generals and i know i will get positive result...SOPHOMORE'S DREAM...HMMMMMMMM[/quote].
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Hmmmm is the word boss... I got a pdf from the internet when i saw your previous post but I cant make a head of what they are trying to say... Here is the download link... http://www.scribd.com/doc/34977341/Sophomore-s-Dream-Function ... Someone here could have the insight....

labodinho: Hello sir,i've jst done dat,more examples wil be appriciated...........@ all.....*There are eight men and nine women on a committe.In how many ways can a subcommittee of two men and three women be chosen?

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no of ways 2men could be there 8Combination2 = 8!/6!2! = 8*7/2 = 28..
no of ways 3women could be there 9Combination3 = 9!/6!3! = 9*8*7/6 = 84
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No of ways the commitee could be formed is 28*84 = 2352 ways

Sorry guys, i got the website wrong initially, it has been corrected now... www.restralrecruit.com

www.restralrecruit.com
Accountants
Electrical Engineers
Computer Scientists
Business Admins and related
disciplines....
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When u have completed the registration just go ahead and log in with your email and password and begin the application process..
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Ezegozie: thank God for this thread. I have been dreaming of reading mathematics in unizik because i will only be solving
2+2=?
4-5+2=? Etc
i no know say na this masquerade i will be drawing in the name of solving maths.

Chai! chai!
So na suicide i for go commit?

Actually this RICHLEZ is he a human being or what to be solving these masquerades these people are posting?

Chai, thank you people for telling me what maths is all about. I will now have change of mind and consider MICRO-BIOLOGY wey maths no dey at all

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Lol man...Maths is not all that tough u know? Infact its not tough at all... I ll take maths anyday over Biology... But since u said its Microbiology u want, lemme give u heads up, theres a lil Statistics in Biology too... U ll meet a course called Biometrics or something like that...

johnpaul1101: thanks @chibuzor, although quite lengthy and confusing, but i'm still on it

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Take your time and welcome back to the thread..

indoorlove: pls, help me with this question.

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indoorlove: Help me with this
question pls Givn
that:u=4x-11x^2 2xy^2; n d
constraints is stated as: x
+2y=6. Determine d maximum
quantity of x n y.

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Ur question is an Operation research that deals with Maximizing Profits. But The parameters are not well stated... please check the question again and see if u copied the right thing thnx...

Richiez: Dats true bro, although he got the working correctly up to the point of cancelling logs...logs can't cancel eachother I think that's the lesson he should learn

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That fact (logs can't cancel eachother) has been stated several times here, but I think we ll still keep saying it... And like u said, the guy almost got the answer right...

[quote author=dr.genius]pls what r the job opportunities for a pure mathematics graduate apart from the academic environment[/quote].
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Number Crunching is the real deal, working with investment bankers (not sure if it works that way in Nigeria) but there are many mathematicians working in Wall Street...

Why the Bleep! did a MOD put a 2008 post on the frontpage in 2013? Someone is smoking rat dungs somewhere...

[quote author=Calculusf(x)]...it's not bro,it just requires something called the position of centre of gravity of a triangle which is two-third of its altitude...[/quote].
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I have absolutely no idea of what you are talking about.. And by that I am Assuming u are an engineer of some sorts?

[quote author=Calculusf(x)]What's the centre of gravity of an equilateral triangle of side 24?...[/quote].
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This should be a geometric construction problem now? Or not...

[quote author=Calculusf(x)]...ade can do it in 3 hours...therefore for 1 hour...ade will do 1/3 of the job...and for 1 hour obi will do 1/5 of the job while audu will do 1/7 of the job for just one hour...combining the work all of them will do in one hour...therefore it's 1/3 + 1/5 + 1/7=71/105...therefore for one hour they will do 71/105 of the job...and for the whole job to be completed they will do 105/71 as this;
1hr~~>71/105 therefore,
xhr~~>1...
Cross multiply from there to get 71x/105=1...therefore x=105/71 hours[/quote].
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You are correct sir, I saw this question on another thread earlier today, I think this is a variation problem... All the same.. Good Job..

[quote author=Calculusf(x)]...1.increase or decrease of each element in a data by a constant number or element has no effect on variance and standard deviation...so the answer is still d...2...for odd...1,3,5...and the nth term is 2n-1...so,we need to find the summation of that...therefore €(summation)2n-1.and from the rule,it becomes €2n-€1...therefore 2€n-€1...and €n=n(n+1)/2 while €1=n...therefore back to 2€n-€1...which is equal to n(n+1)-n...which is equal to n^2...therefore the formula for the sum of odd numbers is n^2...and there are 25 odd numbers in 50...so it will be 25 square to give 625(odd numbers)...therefore y=625 and using the same procedure...for the even numbers the sum is n(n+1) and there are 25 even numbers in 50...therefore 25*26=650...therefore x=650...therefore x-y=25[/quote].
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.Great minds think alike...

busuyem: No. 1 is correct but explain ur answer in question 2.

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The difference between two consecutive odd numbers is 2, with this info, u can use the Sum of arithmetic Progression to get the sum of odd numbers from 1 - 50, which is 625, Then u do the same for the sum of even numbers between 1 - 50, which is 650... The difference is 25.. U got it now?

busuyem: solve these questions:
1) If the standard deviation of a, b and c is d, what is the standard deviation of a+1, b+1 and c+1?
A. 3d B. 2d C. d/2 D. d+1 E. d
2)If the sum of the odd integers frm 1 to 50 is x and the sum of the even integers frm 1 to 50 is y, what id the value of x-y?
A. 50 B. 25 C. 0 D. 75 E. 15

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.1) Standard deviation is still d (Option E)
2) Actual Value of x-y is -25, but id value is 25 (Option B)

echibuzor: .
Sum cant be greater that Product in this instant... or do you mean concatenation? as in 2 years old and 5 years old becoming 25?

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Going by concatenation, the ages would be 13yrs and 30yrs....

rashywire: m still waiting 4 u guys 2 solve oooooooo

rashywire: pls i need d answer b4 3pm.
QUESTION
A MAN IS X YRS OLD WHILE HIS SON IS Y YRS OLD. D SUM OF THEIR AGES IS TWICE D PRODUCT OF THEIR AGE. IF D PRODUCT OF THEIR AGE IS 675, FIND D AGE OF D MAN

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Sum cant be greater that Product in this instant... or do you mean concatenation? as in 2 years old and 5 years old becoming 25?

I didnt read much of the Post, neither did I read the comments but I have the confidence to say that the Ministry is really trying to up the ante, judging by usual standards... I happen to be a Youth Corps Member serving in one of the Parastatals under the MMSD (Ministry of Mines and Steel Development) So I therefore know a bit of what i am talking about...

Richiez: Seems we have more gurus popping into the house...
Sorry guys for being away for a while, let's get back to business. But firstly, I must appreciate the efforts of my generals and other gurus in the house...I'm marvelled at the way you all keep the thread lively. Kudos!

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No give us dat tori joor... Wetin u carry come? Mathematical Problems is our food here, its all we ask for... LOL... Welcome Boss..

Ortarico: lolzz. . . . .Are you trying to say we have always been rivals?

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Not rivals per say, but neither is willing to concede the higher ground....
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emekakelvin: Soln: prime number from 1-10= 2,3,5,7(dat is 4 numbers)
multiple of 3= 3,6,9(dat is 3 numbers)
the key word here is INCLUSIVE,
pr(A nd B)= PR(A)+PR(B) -PR(A nd B)
=4/10+3/10-1/10
7/10-1/10= 6/10 which gives u 3/5
n.b= pr(a)= probability of prime number
pr(b)= probability of multiple of 3
pr(A nd B)= intersection of both


dis is the rubbish d textbook solve , pls learn from it sir..tanx

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Man, now that I think about it, the textbook is the most most correct.... Thanks man..

yemmytcm: ortarico,you my personal person,na you wan disgrace me for here....kai,well I aint ashamed to learn...the prime numbers are 1,2,3,5,7

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Chief, 1 is not a prime number o, A prime number must have two factors only, 1 and itself... In the case of Number 1, it has just one factor which is........ Yeah, you are right, its 1.
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yemmytcm: learn from what ? I should learn that 4 is a prime number ?...[sighs]..it i s well

It is well gan ni

Ortarico: NB: There's no missing 1k!
The problem lies with the method you used to calculate. You loaned money from two different individuals. In this case, the amount you used to buy the shirt is odd, you then added the money you borrowed from them to get one bulky money. When returning, you get the bulky money together and divide, which you clearly didn't divide :. Let's divide the 97k by two:
: 97k/2 = 48.5k

Remember you've given each of them 1k before. So, that accounts to:
=> 2(48.5k + 1k)
=> 2(49.5k)
=> 99k
Finally, add the 1k you took to yourself:
=> 100k....

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Thats the problem that Economists throw around to bamboozle the average scientist that tries to form Mathematician with them...

emekakelvin: Do u believe ur dat ur answer is wrong

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I believe that answer is most correct sir..ask any examiner....

doubleDx: Yeah bruv, on point! Typing some mathematical symbols here ain't easy.... One of the reason why some questions are ignored on this thread!

[quote author=doubleDx][/quote]U got that right

doubleDx: Solution

Log(x² + 7x - 2)₂ = Log(x² + 3x - 6)₂ + Log8₄

Log(x² + 7x - 2)₂ = Log(x² + 3x - 6)₂ + Log2³_2²
Log(x² + 7x - 2)₂ - Log(x² + 3x - 6)₂ = 3/2Log2₂

Log2₂ = 1, also we have same bases on the LHS, so we apply the law of log here to yield=>

Log{(x² + 7x - 2)/(x² + 3x - 6)}₂ = 3/2 * (1)

Eliminating Log₂ yields =>

(x² + 7x - 2)/(x² + 3x - 6) = 2^(3/2)
(x² + 7x - 2)/(x² + 3x - 6) = √2³
(x² + 7x - 2)/(x² + 3x - 6) = 2√2
x² + 7x - 2 = 2√2 (x² + 3x - 6)
x² + 7x - 2 = 2√2 x² + 6x√2 - 12√2

Collecting like terms yields =>

x² - 2√2 x² + 7x - 6x√2 + 12√2 - 2 = 0
x²( 1 - 2√2) + x (7 - 6√2) + 12√2 - 2 = 0

Applying quadratic formula to the above =>

a = ( 1 - 2√2), b = (7 - 6√2) and c = 12√2 - 2
x = {-b±√(b² - 4ac)}/2a
x = {(6√2 - 7) ± √[(7 - 6√2)² - 4(1 - 2√2)(12√2 - 2)]}/2( 1 - 2√2)

√2 = 1.44 approx, substituting and evaluating yields =>

x = {(6(1.44) - 7) ± √[(7 - 6(1.44))² - 4(1 - 2(1.44))(12(1.44) - 2)]}/2( 1 - 2(1.44))
x = {1.64 ± √(2.69 + 114.91)}/(-3.76)
x = {1.64 ± √117.6}/(-3.76)
x = {1.64 ± 10.84/(-3.76)

Splitting =>

x = (1.64 + 10.84)/(-3.76) or (1.64 - 10.84)/(-3.76)
x = 12.48/(-3.76) or 9.2/3.76

Rounding the values of x to one decimal place yields=>

x = -3.3 approx or 2.4 approx

I hope that helps. 1heart man

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I stopped when I got to the 2 root 2 part.. I know from there its gonna be tiresome to write...