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[qu of water in the ves


2. A transformer is required to supply 0.2ampere at 100volt from the secondary using a primary voltage of 250volt. if the primary has 120turns, calculate the number of secondary turns and the primary current assuming the transformer is 100% efficient.(answer= 480turns, 0.8ampere. pls solve and get this answer) cc indomixx eben331 drbestjc aceed[/quote]Is=0.2

Vs=100

Vp=250


Ns=


Ip=


Vs/Vp=Ns/Np=Ip/Is


100/250=Ns/120


Ns=120×100/250


Ns=48 turns



Vs/Vp=Ip/Is


100/250=Ip/0.2



Ip=100×0.2/250


Ip=0.08A

m2>m1



T-4g=4a


12g-T=ma


T=4g+4a



T=12g-12a


12g-12a=4a+4g


12g-4g=12a+4a


8g=16a


g=2a


9.81=2a


a=4.905m/s=4.91m/s'2


T=mg-ma

T=m(g-a)

T=12(9.81-4.91)

T=59N


A is correct....

that's it...

wait lemme post the picture...

1. A cord passing over a frictionless massless pulley has a 4kg object to one end and a 12kg object fixed to the other end. Find the acceleration and the tension in the end.
A. 4.9m/s^2, 59N
B. 6.0m/s^2, 57N
C. 2.5m/s^2, 59N
D. 9.0m/s^2, 60N
Take g as 9.81m/s^2




applying Newton's second law.




4g-T=4a


T=12a


4g-12a=4a


4g=16a



a=4g/16


a=2.5m/s^2




Tension in which end bro

A hose lying on the ground shoots a stream of water upward at an angle of 40' to the horizontal. The speed of the water is 20m/s as it leaves the hose. How high up will it strike a wall which is 8.0m away
A. 2m high
B. 5.4m high
C. 4m high
D. 6m high




H=maximum height reached...



H=u^2sin^2@/2g



H=20^2×sin^2 40/20


H=8.42m


R=horizontal range=8m


sin40=x/8.42


x=sin40×8.42


x=5.41m

3. The ratio of linear expansivity of copper to iron is approximately 1.5. A specimen of iron and a specimen of copper expand by the same amount per unit rise in temperature. The ratio of their lengths is
A. 3
B. 1.5
C. 1.32
D. 1
E. 0.67


increase in length of copper=Lc


increase in length of iron=Li



¥c=Lc/(li@)



Lc=¥cli@



¥i=Li/(li@)


Li=¥ili@




¥c/¥1=3/2


¥c=3¥i/2


Lc=(3¥i/2)li@



Li=¥ili@



Lc/Li=(3¥ili@)/2 ÷ ¥ili@



Lc/Li=3¥ili@/2¥ili@



Lc/Li=3/2=1.5

Nltaliban:
School is fine.. We're trying our best.

okay boss....

kinda new on nairaland tho...

Nltaliban



Boss how's school?

TeflonBlixx:
Mind posting Physics Utme based questions?? I'm quite rusty with physics

Bring it on Teflon blixx

Anyone online?

BiafranDel:
How much sodium hydroxide is required to make 25cm3 of a 0.1 molar solution? ( na=23, O=16, H=1) A4g B2g C1g D5g

Eben was right...the volume should be 250cm^3 not 25 tho using 25cm^3 would give 0.1g


C=n/v


c=conc in mol/dm^3


n=no of moles


v=volume in dm^3=250/1000=1/4dm^3


note n=mass/molar mass


C=(m/mm)÷v


0.1=(m/40)×1/(1/4)



0.1=(m/40)×4



0.1=m/10


m=1g

Damayogenius18:
...thanks for attempting it...but its not correct

kindly show workings sir...

Damayogenius18:
Maybe I should give u some warming up b4 i come back....A 3kg ball moving at 8m/s strike a 2kg ball at rest.... If the collision is elaestic,what is the speed of each ball after collision ...its simple o.....

Velocity of each ball is 4.8m/s

Damayogenius


can you please add me to your group on Whatsapp
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i'm Stephen

09069015773

FTC

add me too



09069015773

[quote][/quote]@TeflonBlixx which course did you apply for

hello guys.... i'm Ayomide, an aspirant of unibadan petroleum engineering..

[/color][color=#990000]hello guys....I'm an aspirant....unibadan petroleum engineering