Education › Re: University of Ibadan 2019/2020 Admission Thread by freshsteph: 3:08am On Feb 23, 2019 |
Nice one here..
I'll help push this thread . |
Education › Re: UI 2019/2020 Admission Thread by freshsteph: 3:17pm On Jan 21, 2019 |
GEM19: Pls what is the cut off mark for Mathematics 56.2 |
Education › Re: UI 2019/2020 Admission Thread by freshsteph: 12:47pm On Jan 02, 2019 |
y'all can chat me up. .
I just got admitted(petroleum engineering) |
Education › Re: UI 2018/2019 Admission Thread by freshsteph: 12:01am On Nov 24, 2018 |
its been long here...
Any petroleum engineering stallite here 
i'm a newbie in the department... |
Education › Re: UI 2018/2019 Admission Thread by freshsteph: 9:15am On Sep 27, 2018 |
I hope we get the faculty of technology cutoff marks today.....
I can't even sleep wella... |
Education › Re: UI 2018/2019 Admission Thread by freshsteph: 8:59am On Sep 27, 2018 |
simplebb: Good morning, we will expect updates from you on this today. Thanks for the input so far.
PS, is this info confirmed?? I mean for Technology department if this is true.... then m safe... #team_pet |
Education › Re: UI 2018/2019 Admission Thread by freshsteph: 3:08pm On Sep 26, 2018 |
I hope i'm favoured...
Course----petroleum engineering..
agg----69.25% |
Education › Re: UI 2018/2019 Admission Thread by freshsteph: 1:57pm On Sep 24, 2018 |
Oau MBBS 79%
nursing 71.8% |
Education › Re: UI 2018/2019 Admission Thread by freshsteph: 6:54pm On Sep 23, 2018 |
Pes13
if you gat any into about the cutoff kindly inform us sire.... |
Education › Re: UI 2018/2019 Admission Thread by freshsteph: 3:24am On Sep 09, 2018 |
Eben331: The coefficient of kinetic friction between smooth, dry surface of steel and wood is approximately 0.02. Calculate the force require to pull 15kg block of steel along a horizontal wooden surface at a steady speed of 0.2m/s. (a) 1.94N (b) 2.49N (c) 1.52N (d) 2.94N PLS SHOW UR WORKINGS!! F-fr=ma U=a/g 0.02=a/10 a=0.2 F-(0.02×150)=15(0.2) F=3 +3 F=6N no option |
Education › Re: UI 2018/2019 Admission Thread by freshsteph: 9:38am On Sep 01, 2018 |
Gracy3535: A consequence of global warming is..........(a)air pollution (b)water pollution (c)increased humidity (d)flooding C |
Education › Re: UI 2018/2019 Admission Thread by freshsteph: 9:32am On Sep 01, 2018 |
. |
Education › Re: UI 2018/2019 Admission Thread by freshsteph: 9:30am On Sep 01, 2018 |
Bigboy289: what is the decrease in volume of air when pyrogallol is shaken with 30.00cm3 of air. A.0.63cm3 .B.0.06cm3 .C.15.00cm3 .D.6.30cm3 21/100 × 30 =630/100=6.30cm³ D |
Education › Re: UI 2018/2019 Admission Thread by freshsteph: 10:38pm On Aug 31, 2018 |
yeah eben....
3.06g is correct
conversion ish..... |
Education › Re: I Need Someone To Solve This Chemistry Question For Me by freshsteph: 1:39am On Aug 30, 2018 |
Timijo: Thanks. Here is another one. A 15kg monkey hangs from a cord suspended from the ceiling of an elevator. The cord can withstand a tension of 200N and breaks as the elevator accelerates. What was the elevator's minimum acceleration (in magnitude and direction)? Take g=10.0ms-2 THANKS SIR T=m(a+g) 200=15(a+10) 200=15a+150 15a=50 a=50/15 a=3.33m/s² |
Education › Re: UI 2018/2019 Admission Thread by freshsteph: 12:27am On Aug 30, 2018 |
Myketuale: please somebody should help me out what weight of HCL is present in 155ml of a 0.540 solution?? thanks 30.5505g |
Education › Re: I Need Someone To Solve This Chemistry Question For Me by freshsteph: 12:31am On Aug 29, 2018 |
Timijo: These ones are Physics questions can anyone solve them 1. A bullet of mass 20g travelling horizontally at 100m/s, embeds itself in the centre of a block of wood 1kg which is suspended by light vertical string 1m, calculate the velocity
M1V1 + M2V2=V(M1+M2)
20/1000(100) + 1(0)=V(20/1000 + 1)
2=51V/50
V=100/51m/s
V=1.961m/s |
Education › Re: UI 2018/2019 Admission Thread by freshsteph: 6:35pm On Aug 25, 2018*. Modified: 12:44am On Aug 28, 2018 |
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Education › Re: UI 2018/2019 Admission Thread by freshsteph: 12:46pm On Aug 25, 2018 |
SammieDollyP: Not too encouraging tho' 252.
Least XPected it. you're welcome bro..... |
Education › Re: UI 2018/2019 Admission Thread by freshsteph: 12:45pm On Aug 25, 2018 |
Afternoon guys......
Any whatsapp group??.. |
Education › Re: UI 2018/2019 Admission Thread by freshsteph: 1:36am On Aug 25, 2018 |
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Education › Re: UI 2018/2019 Admission Thread by freshsteph: 8:19pm On Aug 24, 2018 |
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Education › Re: UI 2018/2019 Admission Thread by freshsteph: 10:46pm On Aug 23, 2018 |
yeah I've done that....
the cost of electricity that liberated 1g of Magnesium is #5, find the cost of electricity that would liberate 10g of Aluminium.... |
Education › Re: UI 2018/2019 Admission Thread by freshsteph: 9:49pm On Aug 23, 2018*. Modified: 10:44pm On Aug 23, 2018 |
my Fb username is...... |
Education › Re: UI 2018/2019 Admission Thread by freshsteph: 9:33pm On Aug 23, 2018 |
Eben331: Freshsteph, this is the question you asked me to repost again. The answers you get are not correct. The answers they get are 84.07N and 44.16N but I dnt knw how they get them. okay bro....I'll try it again..... bro your Fb username  ? |
Education › Re: UI 2018/2019 Admission Thread by freshsteph: 9:31pm On Aug 23, 2018 |
@Rursh
Bro the ui 2017 postutme questions
can you please send it to me...
email: freshstephkid@gmail.com
i'll be grateful bro.. |
Education › Re: UI 2018/2019 Admission Thread by freshsteph: 9:25pm On Aug 23, 2018 |
abeylysis92: I think it's A and D sha yeah bro...
A and D is correct
...
I didn't see the 2mol of Pb |
Education › Re: UI 2018/2019 Admission Thread by freshsteph: 9:14pm On Aug 23, 2018 |
DrBESTJC: Abeg bosses here,I need clear explanations to the correct answers to these questions....It's kinda confusing....
CHEMISTRY.
1) A cold aqueous solution of sodium chloride is electrolysed using a graphite anode and an iron cathode. In the course of the electrolysis, the electrolyte is continously stirred. The liquid left after the electrolysis will therefore consist of : A) Sodium hydroxide solution B) Chlorine water C) Pure water D) Sodium hypochlorite solution E) Hydrochloric acid solution.
2) If 48000 coloumbs of electricity are required to discharge 0.5 mole of sodium from a molten sodium chloride mass, then the number of coloumbs required to discharge 2 moles of Lead from molten Lead(II) chloride is : A) 48000 B) 96000 C) 192000 D) 384000 E) 576000 A and D Na+ 48000c=1/2m 1m=48000×2=96000c Pb2+ 2f=1mol 4f=2mol 4(96000)=2mol 384000c=2mol 384000C is correct... |
Education › Re: 2018/2019 Admission Process Thread Guide by freshsteph: 8:56pm On Aug 23, 2018 |
waw.....
it's been a long time..... |
Education › Re: UI 2018/2019 Admission Thread by freshsteph: 11:14am On Aug 09, 2018 |
freshsteph: 62.5N and 37.5 N if it's correct, kindly send the question again..... |
Education › Re: UI 2018/2019 Admission Thread by freshsteph: 1:16am On Aug 09, 2018 |
Gracy3535: is the answer 10N or 400N 62.5N and 37.5 N |
Education › Re: UI 2018/2019 Admission Thread by freshsteph: 12:45am On Aug 07, 2018 |
yah i'm back.....
eben repost your question...... |