ositadima1:


Back to this question

Each term => (n+7)^3
where n=1 to n=200-7=193

Meaning we have 193 terms from 8^3 to 200^3.

Summation of (n+7)^3 for n=1 to n=193

Sn= (1+7)^3+(2+7)^3+(3+7)^3+...+(193+7)^3

Let`s expand (n+7)^3
(n+7)^3=(n+7)(n+7)(n+7
=n^3+21n^2+147n+343

Let's see the summation of each term above

S= n^3= 1^3+2^3+3^3+...+nth= (1/4)(n^2)(n+1)^2


S=n^2= 1^2+2^2+3^2+...+nth= (1/6)(n)(n+1)(2n+1)

S=n =1+2+3+...+nth= (1/2)(n)(n+1)

S=1+1+1+...+nth= n

Now substituting back

Sn= (1/4)(n^2)[(n+1)^2]+21(1/6)(n)(n+1)(2n+1)+147(1/2)(n)(n+1)+343(n)

So, if u now carefully substitute n=193

Sn=404009216

Actually that equation can give u sum to any number of terms u want, hope this was helpful

tnx bros i gat it

ositadima1:

Boom!!! Memba mi tell yu.

Sum n=1 to 193,
(n+7)^3= 404009216

tnx bros.. Buh can u explain further 2make it clear

ositadima1:

Boom!!! Memba mi tell yu.

Sum n=1 to 193,
(n+7)^3= 404009216

tnx bross buh can u pls explain further cos i didn't get u sir.. Thanks !

Gurus pls solve dis na.. Find d sum of 8^3 + 9^3 + 10^3 + ... + 200^3

Pls gurus elp me solve dis... Determine d sum of 8^3 + 9^3 + 10^3 + ... + 200^3

doubleDx:

If the options are 1, -2, -1, 3/8 then I'm afraid something must be wrong with the question. It's either you did not copy it correctly or there may be some kind of tpyo-errors in the question (If it's a past question). I tried checking by substituting 'n' with each of the option given but none of the result equals 3.

Try copying the question properly or write with a pen, snap or scan and upload!

yeah non of d options s right... Mayb dre s a mistake wit d options.

doubleDx:


3^n +1 + 6.3^n - 2 - 3^n = 3 . There are no brackets to show that: eg. 3 is to the power of (n+1). But I believe your question is the same as the one below? :

3^(n +1) + 6.3^(n - 2) - 3^n = 3

If it is then we can proceed by applying the law of indices:

3^n.3^1 + 6.3^n/3^2 - 3^n = 3
Lets put 3^n = x, substituting yields:

(x).3 + 2.(x)/3 - x = 3
[3x.3 + 2x - (x).3]/3 = 3
9x + 2x - 3x = 3.(3)
8x = 9
x = 9/8

Since 3^n = x
Then 3^n = 9/8
Taking log of both sides gives :

Log3^n = Log 9/8
nLog3 = Log9 - Log8
n = (Log3^2 - Log8 )/log3
n = 2Log3/Log3 - (Log8 )/Log3
n = 2 - Log8 ₃
n = 2 - Log2^3 ₃
n = 2 - 3Log2 ₃

dre s no any bracket in it n d options r a. -2 b. -1 c. 1 d. 3/8 pls i nid ur elp cos dis s a kind of question I'll b facing soon in d exam hall n av tried alot buh i couldn't get it n it's just 45sec per each question...! Futminna bad !

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swagrr..01:
xory guyz..hw do i knw d courses i am supposd to register

my man u nid 2 c ur level adviser on d course 2b registerd

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Hmmm...!